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The data that follow are the square footage (in 1,000 feet squared) of 28 homes.

The sample mean = 2.50 and the sample standard deviation = 0.8302. The distribution can be written as X~U(1.5,4.5).

What is the 90thpercentile of square footage for homes?

Short Answer

Expert verified

The value of the 90thpercentile of square footage for homes is 4.2.

Step by step solution

01

Given information

Table,

Sample mean = 2.50

Standard deviation = 0.8302

02

Solution

Here, we need to find the probability density function or height of the X~U(1.5,4.5),

f(x)=height

=14.5−1.5

=13

So, the 90thpercentile will be,

P(x<k)=base×height

0.90=(k−1.5)13

(k−1.5)=0.90×3

k=2.7+1.5

k=4.2

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