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Chapter 5: Q.5.22 (page 348)

The data that follow are the square footage (in 1,000 feet squared) of 28 homes.

The sample mean = 2.50 and the sample standard deviation = 0.8302. The distribution can be written as X~U(1.5,4.5).

What is P(x<3.5|x<4)?

Short Answer

Expert verified

The value of theP(x<3.5鈭�x<4)is0.80.

Step by step solution

01

Given information

Table,

Sample mean = 2.50

Standard deviation = 0.8302

02

Solution

The probability density function to calculate P(x<3.5鈭�x<4)for 1.5鈮�x鈮�4.5will be:

f(x)=14鈭�1.5

=12.5

Thus, the value of P(x<3.5鈭�x<4)is:

P(x<3.5鈭�x<4)=(3.5鈭�1.5)脳12.5

=2脳12.5

=0.80

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Most popular questions from this chapter

Use the following information to answer the next eleven exercises. The age of cars in the staff parking lot of a suburban college is uniformly distributed from six months (0.5 years) to 9.5 years.

Find the probability that a randomly chosen car in the lot was less than four years old;

a. Sketch the graph, and shade the area of interest.

b. Find the probability. P(x<4)

Use the following information to answer the next seven exercises. A distribution is given as X~Exp(0.75). What is m?

Use the following information to answer the next eleven exercises. The age of cars in the staff parking lot of a suburban college is uniformly distributed from six months (0.5 years) to 9.5 years.

Write the probability density function

Use the following information to answer the next eleven exercises. The age of cars in the staff parking lot of a suburban college is uniformly distributed from six months (0.5 years) to 9.5 years.

Find the third quartile of ages of cars in the lot. This means you will have to find the value such that 34or75%,of the cars are at most (less than or equal to) that age.

a. Sketch the graph, and shade the area of interest.

b. Find the value k such thatP(x<K)=0.75

c. The third quartile is _____

Use the following information to answer the next ten exercises. A customer service representative must spend different amounts of time with each customer to resolve various concerns. The amount of time spent with each customer can be modeled by the following distribution: X~Exp(0.2)

What type of distribution is this?
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