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On May 23,2013, Gallup reported that of the 1005people surveyed, 76%of U.S. workers believe that they will continue working past retirement age. The confidence level for this study was reported at 95%with a ±3%margin of error.

a. Determine the estimated proportion from the sample.

b. Determine the sample size.

c. Identify CL and .

d. Calculate the error bound based on the information provided.

e. Compare the error bound in part d to the margin of error reported by Gallup. Explain any differences between the values.

f. Create a confidence interval for the results of this study.

g. A reporter is covering the release of this study for a local news station. How should she explain the confidence interval to her audience?

Short Answer

Expert verified

(a) The estimated proportion from the sample is p'=0.76

(b) The sample size inn=1005

(c) The level of confidence interval isdata-custom-editor="chemistry" CL=95%andα=0.05

(d) The error bound based on the information EBM=0.0264

(e) The difference between the values from error bound to margin of error is negligible

(f) The confidence level for pis 0.7336≤p≤0.7864

(g) With 95%confidence the true population proportion of U.S workers who believe that they will continue working past retirement age is between73.36%and78.64%

Step by step solution

01

Find the estimated proportion and sample size (part a and b)

According to Gallup, 76percent of US workers expect they will work into retirement age, based on a study of 1005persons.

a) The estimated proportion of the sample is,

p'=76%=0.76

b) The sample size is,

n=1005people

02

Find the value of Confidence level CL, α, EBM and also find the difference between the values(part c, d and e)

c) The level of confidence is,

CL=95%

and therefore,

α=1-0.95=0.05

We've come to the conclusion that,

α2=1-0.952=0.052=0.025

and

zα2=1.96

d) The error bound is,

EBM=zα/2p'1-p'n=1.960.76(1-0.76)1006=0.0264.

e) The difference between the error bound of ±2.64percent and the margin of error stated by Gallup of ±3percent is insignificant.

03

Find the confidence level for p and 95% CI for p (part e and f)

e) The confidence interval for the result of study is

p'-EBM≤p≤p'+EBM,

0.76-0.0264≤p≤0.76+0.0264,

0.7336≤p≤0.7864

f) With 95%confidence the true population proportion of U.S workers who believe that they will continue working past retirement age is between 73.36%and 78.64%

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