/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 25 The mean age for all Foothill Co... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The mean age for all Foothill College students for a recent Fall term was 33.2. The population standard deviation has been pretty consistent at 15. Suppose that twenty-five Winter students were randomly selected. The mean age for the sample was 30.4. We are interested in the true mean age for Winter Foothill College students. Let X=the age of a Winter Foothill College student.

___=15.

Short Answer

Expert verified

Standard Deviationσ=15.

Step by step solution

01

Given Information

The mean age for all Foothill College students for a recent Fall term was 33.2. The population standard deviation has been pretty consistent at 15. The mean age for the sample was 30.4.

02

Explanation

The square root of the variance of a set of integers is used to calculate the population standard deviation. It's used to calculate a confidence interval before making a decision (such as accepting or rejecting a hypothesis).

The average of the data set is the mean.

The population standard deviation of the age of the whole Foothill College students for a recent Fall term is 15.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose that the insurance companies did do a survey. They randomly surveyed 400drivers and found that 320claimed they always buckle up. We are interested in the population proportion of drivers who claim they always buckle up.

a. i. x = __________ ii. n = __________ iii. p′ = __________

b. Define the random variables Xand P', in words.

c. Which distribution should you use for this problem? Explain your choice.

d. Construct a 95%confidence interval for the population proportion who claim they always buckle up. i. State the confidence interval. ii. Sketch the graph. iii. Calculate the error bound.

e. If this survey were done by telephone, list three difficulties the companies might have in obtaining random results.

A sample of 16small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is normal. The weight of each bag was then recorded. The mean weight was two ounces with a standard deviation of 0.12ounces. The population standard deviation is known to be 0.1ounce.

a.

i.x¯=________ii.σ=________iii.sx=________

b. In words, define the random variable X.

c. In words, define the random variable X¯.

d. Which distribution should you use for this problem? Explain your choice.

e. Construct a 90%confidence interval for the population mean weight of the candies.

i. State the confidence interval.

ii. Sketch the graph.

iii. Calculate the error bound.

f. Construct a 98%confidence interval for the population mean weight of the candies.

i. State the confidence interval.

ii. Sketch the graph.

iii. Calculate the error bound.

g. In complete sentences, explain why the confidence interval in part fis larger than the confidence interval in part e.

h. In complete sentences, give an interpretation of what the interval in part fmeans.

On May 23,2013, Gallup reported that of the 1005people surveyed, 76%of U.S. workers believe that they will continue working past retirement age. The confidence level for this study was reported at 95%with a ±3%margin of error.

a. Determine the estimated proportion from the sample.

b. Determine the sample size.

c. Identify CL and .

d. Calculate the error bound based on the information provided.

e. Compare the error bound in part d to the margin of error reported by Gallup. Explain any differences between the values.

f. Create a confidence interval for the results of this study.

g. A reporter is covering the release of this study for a local news station. How should she explain the confidence interval to her audience?

Forbes magazine published data on the best small firms in 2012. These were firms that had been publicly traded for at least a year, have a stock price of at least \(5per share, and have reported annual revenue between \)5million and$1 billion.

The Table 8.13 shows the ages of the corporate CEOs for a random sample of these firms.

Use this sample data to construct a 90%confidence interval for the mean age of CEO’s for these top small firms. Use the Student's t-distribution.

Construct a 95% confidence interval for the population proportion of households where the women make the majority of the purchasing decisions. State the confidence interval, sketch the graph and calculate the error bound.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.