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A 2016 Pew Research poll found that \(61 \%\) of U.S. adults believe that organic produce is better for health than conventionally grown varieties. Assume the sample size was 1000 and that the conditions for using the CLT are met. a. Find and interpret a \(95 \%\) confidence interval for the proportion of U.S. adults to believe organic produce is better for health. b. Find and interpret an \(80 \%\) confidence interval for this population parameter. c. Which interval is wider? d. What happens to the width of a confidence interval as the confidence level decrease?

Short Answer

Expert verified
a. The 95% confidence interval for the proportion of U.S. adults who believe organic produce is healthier is ('insert value'). b. The 80% confidence interval for the same population parameter is ('insert value').\nc. The 95% confidence interval is wider. d. As the confidence level decreases, the confidence interval's width also decreases.

Step by step solution

01

Calculate 95% confidence interval

A 95% confidence interval for a population proportion p can be calculated using the formula \(\hat{p} \pm z*\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\). Given that \(\hat{p} = 0.61\), \(z* = 1.96\) for a 95% confidence interval, and \(n = 1000\), we substitute these values into the formula to calculate the confidence interval.
02

Interpret the 95% confidence interval

The resulting 95% confidence interval can be interpreted as follows: We are 95% confident that the true proportion of U.S. adults who believe that organic produce is better for their health lies within this interval.
03

Calculate 80% confidence interval

Next, we calculate an 80% confidence interval for the same population proportion using the formula \(\hat{p} \pm z*\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\), with \(z* = 1.28\) for an 80% confidence interval. Again, we substitute the given values into the formula.
04

Interpret the 80% confidence interval

The resulting 80% confidence interval can be interpreted as follows: We are 80% confident that the true proportion of U.S. adults who believe that organic produce is better for their health lies within this interval.
05

Compare the Widths of the Intervals

By comparing the widths of the two confidence intervals, we can see which one is wider.
06

Discuss the Effect of Decreasing Confidence Level on Interval Width

In general, as the confidence level decreases, the width of the confidence interval also decreases, implying less certainty about where the population parameter lies.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
When we discuss population proportion, we're referring to the share of individuals in a specified group who have a particular characteristic. For example, in a Pew Research poll mentioned in the exercise, the population proportion is the percentage of U.S. adults who believe that organic produce is healthier than conventionally grown varieties. This is a crucial concept in statistics because it represents the true figure we aim to estimate through our surveys or experiments.

In the context of the exercise, the estimated population proportion, denoted by \(\hat{p}\), is the fraction of respondents in the sample who believe in the health benefits of organic produce. From a sample size of 1000 U.S. adults, it was determined that \(\hat{p} = 0.61\), meaning 61% of those sampled hold this belief. While we can never know the true population proportion without surveying every single adult, we use statistical tools like confidence intervals to estimate this value with an associated level of certainty.
Central Limit Theorem (CLT)
The Central Limit Theorem (CLT), one of the most powerful concepts in statistics, explains why we can make reasonable inferences about a population even with just a sample. Simplified, the CLT states that when an adequately large sample size is taken from a population with any distribution, the sample means will approximately follow a normal distribution. This is incredibly useful because it allows us to apply normal probability to infer about the population mean or proportion.

In our exercise, we assume the conditions for using the CLT are met, suggesting our sample of 1000 is large enough. Therefore, with the CLT in play, the distribution of the sample proportion of U.S. adults who believe organic produce is better for health will be approximately normal. This normal distribution can then be used to estimate a confidence interval for the population proportion.
Confidence Level
The confidence level reflects how sure we can be in the process that produced our interval estimate. Typically expressed as a percentage, it represents the likelihood, based on the data collection method and statistical calculations, that a confidence interval actually contains the population parameter. Common confidence levels include 90%, 95%, and 99% — but how do these percentages actually affect our confidence intervals?

Looking at our example, finding a 95% confidence interval means that if we could repeat our study many times, we expect that 95% of the calculated intervals would contain the true population proportion. When we compute an 80% confidence interval, we are being less stringent and accept a higher chance that our interval may not contain the true proportion. The confidence level is a trade-off between precision and certainty – higher confidence levels produce wider intervals, offering greater assurance that the interval contains the population parameter.
Standard Error
Standard error functions as a measure of the amount of sampling variability in your estimate. It's directly tied to sample size and variability within the sample. Thus, understanding the standard error reveals why and how the size of confidence intervals change.

For a population proportion, the standard error is calculated using the formula \(\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\). In our exercise, \(\hat{p}\) represents the sample proportion (61%) and \(n\) is the sample size (1000). As we observe this formula, it's evident that a larger sample size diminishes the standard error, leading to narrower confidence intervals. Conversely, a smaller sample size increases the standard error, resulting in wider intervals.

Moreover, the standard error is a critical factor in determining the width of a confidence interval. When coupled with a particular confidence level through the multiplier \(z*\), it yields the margin of error. As the confidence level lowers, the \(z*\) value decreases, making the margin of error smaller and the interval narrower. This inverse association underlines why, with a decrease in the confidence level, confidence intervals become less wide but also imply less certainty about capturing the true population parameter.

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Most popular questions from this chapter

According to The Washington Post, \(72 \%\) of high school seniors have a driver's license. Suppose we take a random sample of 100 high school seniors and find the proportion who have a driver's license. a. What value should we expect for our sample proportion? b. What is the standard error? c. Use your answers to parts a and \(\mathrm{b}\) to complete this sentence: We expect _____% to have their driver’s license, give or take _____%. d. Suppose we increased the sample size from 100 to 500 . What effect would this have on the standard error? Recalculate the standard error to see if your prediction was correct.

Two symbols are used for the mean: \(\mu\) and \(\bar{x}\). a. Which represents a parameter, and which a statistic? b. In determining the mean age of all students at your school, you survey 30 students and find the mean of their ages. Is this mean \(\bar{x}\) or \(\mu\) ?

A 2017 survey of U.S. adults found that \(74 \%\) believed that protecting the rights of those with unpopular views is a very important component of a strong democracy. Assume the sample size was 1000 . a. How many people in the sample felt this way? b. Is the sample large enough to apply the Central Limit Theorem? Explain. Assume all other conditions are met. c. Find a \(95 \%\) confidence interval for the proportion of U.S. adults who believe that protecting the rights of those with unpopular views is a very important component of a strong democracy. d. Find the width of the \(95 \%\) confidence interval. Round your answer to the nearest tenth percent. e. Now assume the sample size was 4000 and the percentage was still \(74 \%\). Find a \(95 \%\) confidence interval and report the width of the interval. f. What happened to the width of the confidence interval when the sample size was increased? Did it increase or decrease?

Refer to Exercise \(7.77\) for information. This data set records results just for the boys. $$ \begin{array}{|lcc|} \hline & \text { Preschool } & \text { No Preschool } \\ \hline \text { Grad HS } & 16 & 21 \\ \hline \text { No Grad HS } & 16 & 18 \\ \hline \end{array} $$ a. Find and compare the percentages that graduated for each group, descriptively. Does this suggest that preschool was linked with a higher graduation rate? b. Verify that the conditions for a two-proportion confidence interval are satisfied. c. Indicate which one of the following statements is correct. i. The interval does not capture 0 , suggesting that it is plausible that the proportions are the same. ii. The interval does not capture 0 , suggesting that it is not plausible that the proportions are the same. iii. The interval captures 0 , suggesting that it is plausible that the population proportions are the same. iv. The interval captures 0 , suggesting that it is not plausible that the population proportions are the same. d. Would a \(99 \%\) confidence interval be wider or narrower?

Maria opposes capital punishment and wants to find out if a majority of voters in her state support it. She goes to a church picnic and asks everyone there for their opinion. Because most of them oppose capital punishment, she concludes that a vote in her state would go against it. Explain what is wrong with Maria's approach.

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