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According to a 2018 Pew Research report, \(40 \%\) of Americans read print books exclusively (rather than reading some digital books). Suppose a random sample of 500 Americans is selected. a. What percentage of the sample would we expect to read print books exclusively? b. Verify that the conditions for the Central Limit Theorem are met. c. What is the standard error for this sample proportion? d. Complete this sentence: We expect _____% of Americans to read print books exclusively, give or take _____%.

Short Answer

Expert verified
a. We expect \(40 \% \) of the sample to read print books exclusively. b. The conditions for the Central Limit Theorem are met as our sample size is both less than \(10 \% \) of the population and large enough for given proportion. c. The standard error for this sample proportion is 0.02236. d. We expect \(40 \% \) of Americans to read print books exclusively, give or take \(2.236 \% \).

Step by step solution

01

Calculate Expected Percentage

The expected percentage in the sample that read print books exclusively would be the same as the population percentage. This is because a random sample is expected to reflect the population. Therefore, the expected percentage is \(40 \% \).
02

Verify Central Limit Theorem Conditions

The conditions for the Central Limit Theorem are that the sample size is less than \(10 \% \) of the population size (which is definitely true in this case as the population is all Americans) and that the sample size is large enough. For proportions, we require \(np > 10\) and \(n(1-p) > 10\). Given the sample size of 500 and p = 0.4, both \(np = 500 * 0.4 = 200\) and \(n(1-p) = 500 * 0.6 = 300\) are greater than 10. Hence the conditions are met.
03

Calculate Standard Error

The standard error for the sample proportion is given by the square root of \(p(1-p)/n\). Substituting the given values we get standard error as \( \sqrt{0.4 * 0.6 / 500} = 0.02236\).
04

Express Expected Proportion

We expect \(40 \% \) of Americans to read print books exclusively, give or take the standard error expressed as a percentage which is \( 0.02236 * 100 = 2.236 \% \). So we can estimate that we expect \(40 \% \) of Americans to read print books exclusively, give or take \(2.236 \% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
When we talk about the sample proportion, we're referring to the proportion of individuals in our sample group that exhibit a particular characteristic. In this case, we're interested in the percentage of Americans who exclusively read print books. From a given population where 40% are known to read print books exclusively, one might wonder what proportion we expect to see in our sample.
This is where the sample proportion comes into play: it's expected to mirror the population proportion when a sample is randomly chosen. Thus, if we collect a random sample of 500 Americans, the sample should reflect around 40% reading print books exclusively. This doesn't mean every sample will show exactly 40%, but on average, many samples will. This estimation helps us make generalizations about the population from our smaller sample.
Standard Error Calculation
Standard error is a measure of how much the sample proportion is expected to vary from the true population proportion. It helps us understand the variability and reliability of our sample results. The formula for calculating standard error for a sample proportion is given by: \[ \text{SE} = \sqrt{\frac{p(1-p)}{n}} \]where \( p \) is the sample proportion and \( n \) is the sample size. In our example, using \( p = 0.4 \) and \( n = 500 \), plugging these into the formula gives us a standard error of approximately 0.02236.
This number tells us that, due to random sampling variation, we expect the sample proportion to vary by about 2.236% (when expressed as a percentage) from the population proportion. In simpler terms, we should expect a natural variability of plus or minus 2.236% from the 40% of print-exclusive readers if we were to take many samples.
Random Sampling Conditions
For the Central Limit Theorem to apply to sample proportions, certain conditions must be met in the sampling process. These include:
  • The sample must be random. This means every individual in the population should have an equal chance of being chosen.
  • The sample size should be a small fraction of the total population (less than 10%). For a country as large as the USA, a sample of 500 certainly fits.
  • The sample size must be large enough for the proportion values: both \( np \) and \( n(1-p) \) must be greater than 10. For our example, with \( p = 0.4 \), both calculations meet this requirement (\( 200 \, \text{and} \, 300 \), respectively).
These criteria ensure that our sample proportion will accurately reflect the population proportion and that the normal distribution is a good approximation for our sampling distribution. This is crucial for making valid inferences about the population.
Population Parameter Estimation
Estimating a population parameter, such as the proportion of people reading print books exclusively, involves using your sample data to infer about the broader population. Population parameters are fixed and often unknown values, which we seek to estimate using our sample statistics. In our case, we use a sample proportion to estimate the actual population proportion.
Using the Central Limit Theorem, we can confidently say that our sample proportion of 40%, with a standard error of 2.236%, allows us to estimate that between approximately 37.764% and 42.236% of the entire American population read print books exclusively. This range, known as a confidence interval, gives us a level of certainty in our population estimate, while acknowledging the natural sampling variability.

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