/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 \(1,3,5,7\), and 9 are odd and 0... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

\(1,3,5,7\), and 9 are odd and 0,2, 4,6, and 8 are even. Consider a 30 -digit line from a random number table. a. How many of the 30 digits would you expect to be odd on average? b. If you actually counted, would you get exactly the number you predicted in part a? Explain.

Short Answer

Expert verified
a. On average, one would expect 15 of the 30 digits to be odd. b. The actual count will probably not always match the expected number due to randomness in the counting process. However, over many trials, the average should approach the expected value of 15.

Step by step solution

01

Identifying Odd and Even Numbers

First, identify the set of odd and even numbers in the range 0-9. There are 5 odd numbers: {1,3,5,7,9}, and 5 even numbers: {0,2,4,6,8}.
02

Calculate the Probability of Odd Numbers

As we are considering a uniform random number table where each digit between 0 and 9 is equally likely, the probability of getting an odd number at any given position in the 30-digit line is equal to the ratio of odd numbers to total numbers. This is \( \frac{5}{10} = 0.5 \)
03

Calculate Expected Value

The expected value is the hypothetical average result of an experiment (selecting a digit in the number line) repeated many times. In this case, it's the total number of digits (30) multiplied by the probability of getting an odd number (0.5). Therefore, the Expected value = 30*0.5 = 15. We expect 15 out of 30 digits to be odd.
04

Variability around the Expectation

In part b, the question is about whether the actual count will match the expected result or not. Although the expected value is 15, this is a random process, so the actual count can vary. When repeating this experiment several times, we expect the count to vary around the value of 15. Sometimes it would be more, sometimes less, but on average, it should be approximately 15. Therefore, we wouldn't expect the number to be exactly 15 every time, due to the randomness of the process.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability in Statistics
Probability is a fundamental concept in statistics, representing the likelihood of a particular event occurring. It ranges from 0 (impossible) to 1 (certain). When dealing with a finite set of equally likely outcomes, such as picking a numbered ball from a bag, the probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.

For example, in a random number table where every digit from 0 to 9 has an equal chance of being selected, the probability of choosing an odd number is the number of odd digits (1, 3, 5, 7, 9) divided by the total digits (0 through 9). Since there are five odd and five even numbers in this set, the probability is calculated as \( \frac{5}{10} = 0.5 \). This means if we were to pick a digit at random, there's a 50% chance it would be odd. In relation to the exercise, with a 30-digit line from a random number table, we would thus expect on average half of the digits to be odd, that is 15 out of 30.
Random Number Table
A random number table is a tool used in statistics to simulate random outcomes. It consists of a sequence of digits (usually 0-9) that are generated in a manner where each digit has an equal chance of appearing. This method ensures that there is no discernible pattern which could influence the results of an experiment based on randomness.

When working with a random number table, as in the given exercise, it is important to remember that each digit is independent of the others. That means knowing the value of one digit does not provide any information about the values of subsequent or preceding digits. The table is thus utilized to mimic the randomness you would find in real-world scenarios. If we were inspecting a 30-digit sequence from such a table to find out how many odd numbers appear, we'd employ the concept of expected value. However, while the expected value provides a mean for prediction, the 'law of large numbers' implies that the actual observed frequency will converge to the expected value only over a large number of trials.
Odd and Even Numbers
Odd and even numbers are the most basic categories of integers. An even number is any integer that can be divided by two without a remainder, such as 0, 2, 4, 6, and 8. Conversely, an odd number cannot be evenly divided by two; the set includes numbers like 1, 3, 5, 7, and 9. These properties have distinct implications in probability exercises involving randomness.

In the context of the exercise, recognizing a number as odd or even tells us its membership in one of two equally sized groups. This categorization is crucial for calculating expectations about their frequency in any random numeric sample, such as the 30-digit line from a random number table. It's important to note that while we might expect, on average, an equal distribution of odd and even numbers, any given sample could deviate from this average due to natural variability inherent to random processes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In carrying out a study of views on capital punishment, a student asked a question two ways: 1\. With persuasion: "My brother has been accused of murder and he is innocent. If he is found guilty, he might suffer capital punishment. Now do you support or oppose capital punishment?" 2\. Without persuasion: "Do you support or oppose capital punishment?" Here is a breakdown of her actual data. $$ \begin{aligned} &\text { Men }\\\ &\begin{array}{lcc} & \begin{array}{c} \text { With } \\ \text { persuasion } \end{array} & \begin{array}{c} \text { No } \\ \text { persuasion } \end{array} \\ \hline \text { For capital punishment } & 6 & 13 \\ \hline \text { Against capital punishment } & 9 & 2 \\ \text { Women } \end{array}\\\ &\begin{array}{lcc} & \begin{array}{c} \text { With } \\ \text { persuasion } \end{array} & \begin{array}{c} \text { No } \\ \text { persuasion } \end{array} \\ \hline \text { For capital punishment } & 2 & 5 \\ \hline \text { Against capital punishment } & 8 & 5 \end{array} \end{aligned} $$ a. What percentage of those persuaded against it support capital punishment? b. What percentage of those not persuaded against it support capital punishment? c. Compare the percentages in parts a and b. Is this what you expected? Explain.

According to a 2017 Pew Research report, \(40 \%\) of millennials have a BA degree. Suppose we take a random sample of 500 millennials and find the proportion who have a driver's license. Find the probability that at most \(35 \%\) of the sample has a BA degree. Begin by verifying that the conditions for the Central Limit Theorem for Sample Proportions have been met.

The city of San Francisco provides an open data set of commercial building energy use. Each row of the data set represents a commercial building. A sample of 100 buildings from the data set had a mean floor area of 32,470 square feet. Of the sample, \(28 \%\) were office buildings. a. What is the correct notation for the value 32,470 ? b. What is the correct notation for the value \(28 \%\) ?

According to a 2017 Pew Research Center report on voting issues, \(59 \%\) of Americans feel that the everything should be done to make it easy for every citizen to vote. Suppose a random sample of 200 Americans is selected. We are interested in finding the probability that the proportion of the sample who feel with way is greater than \(55 \%\). a. Without doing any calculations, determine whether this probability will be greater than \(50 \%\) or less than \(50 \%\). Explain your reasoning. b. Calculate the probability that the sample proportion is \(55 \%\) or more.

According to a 2017 article in The Washington Post, \(72 \%\) of high school seniors have a driver's license. Suppose we take a random sample of 100 high school seniors and find the proportion who have a driver's license. Find the probability that more than \(75 \%\) of the sample has a driver's license. Begin by verifying that the conditions for the Central Limit Theorem for Sample Proportions have been met.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.