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According to a Pew poll, \(67 \%\) of Americans believe that jury duty is part of good citizenship. Suppose 500 Americans are randomly selected. a. Find the probability that more than half believe that jury duty is part of good citizenship. b. In a group of 500 Americans, how many would we expect hold this belief? c. Would it be surprising to find that more than 450 out of the 500 American randomly selected held this belief? Why or why not?

Short Answer

Expert verified
a) The probability that more than half believe that jury duty is part of good citizenship is nearly 100%. b)The expected number of Americans among the 500 that hold this belief is 335. c)It would indeed be surprising to find more than 450 out of 500 Americans believe that jury duty is part of good citizenship as it is more than 1.5 standard deviations away from the mean.

Step by step solution

01

Understanding the given percentage

The exercise mentions that 67% of Americans believe that jury duty is part of good citizenship. Therefore, the chance for one randomly selected American to believe that jury duty is part of good citizenship is 0.67.
02

Calculate the Probability

In a binomial setting, the distribution of the number of successes can often be approximated by the normal distribution when the sample size is large. In this case with 500 Americans, using the normal distribution to approximate the binomial is appropriate. Here, the mean for normal approximation would be n*p where n = number of trials=500 and p= probability of success=0.67 which gives 335. The standard deviation would be sqrt(n*p*q) where q= 1-p= 0.33. This gives approximately 10.95. To find the probability that more than half believe, half of 500 is 250. So, the probability is the z-score of 250-335 / 10.95 which gives approximately 0. In other words, nearly all 500 Americans would believe that jury duty is part of good citizenship.
03

Calculate Expected Number

The expected value of a binomial distribution is simply n*p, where n represents the number of trials and p represents the probability of success on each trial. Here, n=500 and p=0.67, hence expected value= n*p = 335.
04

Analyzing Belief of More Than 450

Given the distribution characteristics, finding over 450 out of 500 randomly selected people holding the belief seems quite surprising. This number is far above our mean (335) and statistically stands at around 1.5 standard deviations above the mean.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Probability
Probability is the measure of how likely an event is to occur. In the context of our exercise, we consider the probability of Americans believing that jury duty is part of good citizenship. A critical aspect of working with probabilities is knowing how to interpret them. For example, when we say there is a 67% chance that a randomly chosen American believes jury duty is a part of good citizenship, it's like saying that if we picked 100 Americans randomly, we'd expect approximately 67 to hold that belief.

The probability can be calculated in various situations using different probability distributions. In this case, since we are considering a large number of trials, that is, 500 Americans, we are dealing with the binomial distribution. The binomial distribution is used when there are exactly two mutually exclusive outcomes of a trial, often called a success and a failure. In our exercise, the 'success' is an American believing in jury duty as part of citizenship, with a probability of success being 0.67.
Normal Approximation to Binomial Distribution
When we're dealing with a large number of trials in a binomial distribution, we can use the normal approximation for simplification. The central limit theorem tells us that with a sufficiently large sample size, the binomial distribution of successes will approximate a normal distribution, known for its bell-shaped curve. This makes it easier to calculate probabilities for events, such as finding more than a certain number of Americans believing in jury duty.

To use normal approximation, we need to calculate the mean (average) and standard deviation of the distribution. The mean is the expected value, and for a binominal distribution, it's found by multiplying the number of trials (n) by the probability of success (p).

Standard Deviation and Z-score

The standard deviation measures variability and is calculated by taking the square root of the mean multiplied by the probability of failure (q). When we look for the probability of more than half believing, we calculate a z-score, which tells how many standard deviations an element is from the mean. In this exercise, the z-score calculation indicates that it's highly likely that more than half of the selected Americans believe in the importance of jury duty.
Calculating Expected Value
The expected value in probability provides us with an idea of what to anticipate as the average outcome over a long series of trials. For a binomial distribution, it's simply the total number of trials (n) multiplied by the probability of success (p).

In our given problem, the expected number of Americans who believe that jury duty is part of good citizenship is the expected value, which is 335 out of the 500 people surveyed, derived by multiplying 500 by 0.67. This expected value is immensely useful. It not only gives us a point of reference to compare actual results against but also helps in understanding the average outcome around which the distribution centers.

If we were to find a significantly different number from our expected value—like more than 450 out of 500—it would indeed be surprising. This deviation from the expected number would be considerable, potentially indicating that our sample may not be representative of the general population, or there may have been a change in public opinion.

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