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According to the Pew Research Center, \(73 \%\) of Americans have read at least one book during the past year. Suppose 200 Americans are randomly selected. a. Find the probability that more than 150 have read at least one book during the past year. b. Find the probability that between 140 and 150 have read at least one book during the past year. c. Find the mean and the standard deviation for this binomial distribution. d. Using your answer to part c, complete this sentence: It would be surprising to find that fewer than \(-\) people in the sample had read at least one book in the last year.

Short Answer

Expert verified
The probability of having more than 150 successful cases, the probability of having between 140 and 150 successful cases, the mean, and the standard deviation of the binomial distribution need to be calculated. Further, to determine the surprising number of people who haven't read at least one book, subtract two standard deviations from the mean. Note that binomial distribution calculations can be intricate and typically require software or a calculator with statistical functions.

Step by step solution

01

Calculate probability for more than 150 successful cases

Start by finding the probability of exactly 150 people having read a book. Use binomial distribution formula \(\binom{n}{r}p^{r}q^{(n-r)}\), where \(n\) = 200, \(r\) = 150, \(p\) = 0.73 and \(q\) = \(1 - p\) = 0.27. Calculate this and subtract it from 1 to get the probability of more than 150.
02

Calculate probability between 140 and 150 successful cases

Apply the binomial distribution formula for each \(r\) from 140 to 150 and sum up the probabilities to get the total probability of having successful cases between 140 and 150.
03

Calculate mean and standard deviation

The mean of a binomial distribution is given by \(np\), and the standard deviation is equal to \(\sqrt{npq}\). Substitute \(n\) = 200, \(p\) = 0.73 and \(q\) = 0.27 into these formulas to find the mean and standard deviation.
04

Determine surprising number of people

Using the empirical rule, any value falling below 2 standard deviations from the mean could be considered surprising. Subtract 2 standard deviations from the mean to get this value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Probability
Probability is the measure of how likely an event is to occur. Think of it as a way of expressing the chances of a particular outcome in a situation where there is uncertainty. In the case of the Pew Research Center's finding that 73% of Americans have read at least one book in the past year, we say that the probability, denoted as 'p', of one person having read a book is 0.73. Conversely, the probability of a person not having read a book, denoted as 'q' where q = 1 - p, would be 0.27. When analyzing the likelihood of a series of outcomes, such as whether 200 random Americans have read a book, we rely on specific probability models, one of which is the binomial distribution.

In practical terms, probability helps us set expectations and make informed predictions in daily life. From weather forecasts to medical diagnoses, understanding probability allows us to assess risk and make decisions with greater confidence.
Navigating the Binomial Probability Formula
The binomial probability formula is a cornerstone of understanding statistical probability in situations with two possible outcomes, like success or failure, yes or no, or reading a book or not. When asking about a fixed number of independent trials, say 200 people possibly reading books, we use this specific formula to find the probability of a particular count of successes.

The formula is given as
\[ P(X = r) = \binom{n}{r} p^r (1-p)^{ n - r } \]
where \( P(X = r) \) is the probability of 'r' successes in 'n' trials, \( \binom{n}{r} \) is the binomial coefficient representing the number of combinations of 'n' items taken 'r' at a time, 'p' is the probability of success on an individual trial, and \( 1-p \) the probability of failure (which also equals 'q'). This formula is powerful because it quantifies the distribution of outcomes over many trials, illuminating patterns that are not obvious at first glance.
Mean and Standard Deviation of Binomial Distribution
The mean and standard deviation are critical statistical measurements that summarize a binomial distribution. The mean, often referred to as the expected value, tells us the average number of successes we can expect. In the example of Americans reading books, it's calculated by simply multiplying the total number of trials, 200, by the probability of success per trial, 0.73. This gives us the intuitive result that, on average, about 146 Americans have read a book.

The standard deviation, on the other hand, gives us an idea of how spread out or variable the number of successes might be around this mean. It's found by taking the square root of the product of the number of trials, the probability of success, and the probability of failure (\( \text{Standard Deviation} = \$nPq \)). When the mean and standard deviation are known, they serve as a solid base for making predictions and assessing variability in binomial scenarios.
Applying the Empirical Rule
The empirical rule, often referred to as the 68-95-99.7 rule, is a statistical guideline that applies to normally distributed data. According to this rule, approximately 68% of data falls within one standard deviation of the mean, 95% within two, and 99.7% within three. Although binomial distributions become approximately normal under certain conditions, using the empirical rule offers a quick way to estimate the unusualness of outcomes.

For instance, using the empirical rule, we could say that if the number of people who have read at least one book in the past year falls more than two standard deviations below the mean, it would indeed be surprising. Mathematically, this implies subtracting twice the standard deviation from the mean to set a lower bound, beyond which the amounts become increasingly rare. It's an invaluable rule that helps quantify our expectations in probabilistic terms.

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Most popular questions from this chapter

A coin will be flipped four times, and the number of heads recorded. Explain why this is a binomial experiment. Check all four required conditions.

The Empirical Rule applies rough approximations to probabilities for any unimodal, symmetric distribution. But for the Normal distribution we can be more precise. Use the figure and the fact that the Normal curve is symmetric to answer the questions. Do not use a Normal table or technology. According to the Empirical Rule, a. Roughly what percentage of \(z\) -scores are between \(-2\) and 2 ? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) b. Roughly what percentage of \(z\) -scores are between \(-3\) and 3 ? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) c. Roughly what percentage of \(z\) -scores are between \(-1\) and 1 . i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) d. Roughly what percentage of \(z\) -scores are greater than 0 ? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) e. Roughly what percentage of \(z\) -scores are between 1 and 2 ? i. almost all iii. \(50 \%\) ii. \(13.5 \%\) iv. \(2 \%\)

Use the table or technology to find the answer to each question. Include an appropriately labeled sketch of the Normal curve for each part. Shade the appropriate region. A section of the Normal table is provided. a. Find the area in a Standard Normal curve to the left of \(1.13\). b. Find the area in a Standard Normal curve to the right of \(1.13\).

Use technology or a Normal table to find each of the following. Include an appropriately labeled sketch of the Normal curve for each part with the appropriate area shaded. a. Find the probability that a \(z\) -score will be \(2.12\) or greater. b. Find the probability that a \(z\) -score will be less than \(-0.74\). c. Find the probability that a \(z\) -score will between \(1.25\) and \(2.37\).

According to a 2017 Gallup poll, \(44 \%\) of Americans report they frequently feel stressed. Suppose 200 Americans are randomly sampled. Find the probability of the following: a. Fewer than 80 frequently feel stressed b. At least 90 frequently feel stressed c. Between 80 and 100 frequently feel stressed d. At most 75 frequently feel stressed

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