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For each question, find the area to the right of the given \(z\) -score in a standard Normal distribution. In this question, round your answers to the nearest \(0.000\). Include an appropriately labeled sketch of the \(N(0,1)\) curve. a. \(z=-4.00\) b. \(z=-8.00\) c. \(z=-30.00\) d. If you had the exact probability for these right proportions, which would be the largest and which would be the smallest? e. Which is equal to the area in part b: the area below (to the left of) \(z=8.00\) or the area above (to the right of) \(z=8.00\) ?

Short Answer

Expert verified
a. The area to the right of \(z=-4.00\) is 0.9997. b. The area to the right of \(z=-8.00\) is 1.0. c. The area to the right of \(z=-30.00\) is 1.0. d. If we had the exact probabilities, the largest right proportion would be \(z = -4.00\), and the smallest would be \(z = -8.00\) and \(z = -30.00\). e. The area to the right of \(z=8.00\) is less than the area to the right of \(z=-8.00\).

Step by step solution

01

Find the Areas for Given Z-Scores

In the Normal distribution table, areas to the right of the score are found by subtracting the cumulative probability from one. Given z-scores are -4, -8, -30. We find out their respective areas: \n\n For \(z = -4.00\), the area to the right is \(1 - 0.00003 = 0.9997\) \n\n For \(z = -8.00\) and \(z = -30.00\), they fall beyond the extent of the z-table and hence, the areas to the right are considered as 1.0.
02

Determine the Larger and Smaller Areas

If the exact probability of these right proportions were known, the largest right proportion would be \(z = -4.00\) as it is closest to the mean, and the smallest would be \(z = -8.00\) or \(z = -30.00\) as they are farthest from the mean.
03

Compare the Areas

The area below (to the left of) \(z = 8.00\) is practically 1 because 8.00 is significantly far from the mean. So the area above (to the right of) \(z=8.00\) is essentially 0, meaning the area to the right of \(z=8.00\) is less than the area to the right of \(z=-8.00\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score
The Z-score is a statistical measurement that describes a value's relationship to the mean of a group of values. When we talk about the standard normal distribution, the Z-score gives us an idea of how many standard deviations a particular value is from the mean.
  • The formula for the Z-score is: \( Z = \frac{(X - \mu)}{\sigma} \)
  • Where \(X\) is the value, \(\mu\) is the mean, and \(\sigma\) is the standard deviation.
When a Z-score is calculated, it allows you to understand whether the score is typical for a data set or if it is an outlier. A Z-score of 0 indicates that the value is exactly at the mean. Positive Z-scores indicate values above the mean, whereas negative Z-scores indicate values below the mean.
In exercises like these, understanding Z-scores is essential as it helps determine the likelihood of a particular data point occurring within a given distribution. By interpreting Z-scores, one can making sense of where data points lie in the context of a normal distribution.
Cumulative Probability
Cumulative probability is the probability that a variable will take a value less than or equal to a certain specified value. This concept is especially useful in dealing with normal distributions.
In terms of a Z-score, cumulative probability corresponds to the area under the normal distribution curve to the left of the Z-score. It gives you the likelihood that a randomly selected score is less than or equal to a given score.
  • For example, if the cumulative probability of a Z-score of -4.00 is 0.00003, this suggests that only 0.003% of the distribution falls to the left.
  • To get the area to the right of a Z-score, we subtract the cumulative probability from 1.
Cumulative probability is vital in hypothesis testing, determining percentiles, and many practical applications in statistics.
Normal Distribution Table
A normal distribution table, also known as a Z-table, is a mathematical table used to find the cumulative probability of a standard normal distribution. It shows the cumulative probabilities of a standard normal distribution associated with various Z-scores.
These tables typically provide the cumulative probability from the mean to a particular Z-score. By using a Z-table, we can quickly find probabilities and areas under the curve for any standard normal distribution.
  • For Z-scores like -4.00, tables give the cumulative probability directly.
  • Z-scores beyond the table, such as -8.00 and -30.00, results in cumulative probabilities close to 0, indicating most of the data lies far from these points.
Normal distribution tables are crucial for quickly calculating probabilities without needing complex calculations and are widely used in various statistical analyses.
Area under Curve
The concept of "area under the curve" in statistics concerns the region enclosed by the normal distribution curve and the horizontal axis. The total area under a standard normal distribution curve is always equal to 1.
For Z-scores, calculating the area corresponds to finding the probability associated with that Z-score.
  • The area represents the probability of a variable falling within a particular range.
  • The area to the right or left of a Z-score is determined using cumulative probabilities and subtracting from 1, if needed.
This area is valuable for inferential statistics, allowing practitioners to predict outcomes and make informed decisions. The entire exercise targets this concept, as students must find these areas for negative Z-scores to interpret various probabilities.

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Most popular questions from this chapter

According to Anthropometric Survey data, the distribution of arm spans for males is approximately Normal with a mean of \(71.4\) inches and a standard deviation of 3. 3 inches. a. What percentage of men have arm spans between 66 and 76 inches? b. Professional basketball player, Kevin Durant, has an arm span of almost 89 inches. Find the \(z\) -score for Durant's arm span. What percentage of males have an arm span at least as long as Durant's?

The distribution of white blood cell count per cubic millimeter of whole blood is approximately Normal with mean 7500 and standard deviation 1750 for healthy patients. Use technology or a table to answer these questions. For each include an appropriately labeled and shaded Normal curve. a. What is the probability that a randomly selected person will have a white blood cell count between 6000 and 10,000 ? b. An elevated white blood cell count can be a sign of infection somewhere in the body. A white blood cell count can be considered elevated if it is over 10,500 . What percentage of people have white blood cell counts in this elevated range? c. A white blood cell count below 4500 is considered low. People in this range may be referred for additional medical testing. What is the probability that a randomly selected person has a white blood cell count below 4500 ?

Assume that college women's heights are approximately Normally distributed with a mean of 65 inches and a standard deviation of \(2.5\) inches. On the horizontal axis of the graph, indicate the heights that correspond to the \(z\) -scores provided. (See the labeling in Exercise 6.14.) Use only the Empirical Rule to choose your answers. Sixty inches is 5 feet, and 72 inches is 6 feet. a. Roughly what percentage of women's heights are greater than \(72.5\) inches? i. almost all iii. \(50 \%\) v. about \(0 \%\) ii. \(75 \%\) iv. \(25 \%\) b. Roughly what percentage of women's heights are between 60 and 70 inches? i. almost all iii. \(68 \%\) v. about \(0 \%\) ii. \(95 \%\) iv. \(34 \%\) c. Roughly what percentage of women's heights are between 65 and \(67.5\) inches? i. almost all iii. \(68 \%\) v. about \(0 \%\) ii. \(95 \%\) iv. \(34 \%\) d. Roughly what percentage of women's heights are between \(62.5\) and \(67.5\) inches? i. almost all iii. \(68 \%\) v. about \(0 \%\) ii. \(95 \%\) iv. \(34 \%\) e. Roughly what percentage of women's heights are less than \(57.5\) inches? i. almost all iii. \(68 \%\) v. about \(0 \%\) ii. \(95 \%\) iv. \(34 \%\) f. Roughly what percentage of women's heights are between 65 and 70 inches? i. almost all iii. \(47.5 \%\) v. \(2.5 \%\) ii. \(95 \%\) iv. \(34 \%\)

College women have heights with the following distribution (inches): \(N(65,2.5)\). a. Find the height at the 75 th percentile. b. Find the height at the 25 th percentile. c. Find the interquartile range for heights. d. Is the interquartile range larger or smaller than the standard deviation? Explain.

Alaska Airlines has an on-time arrival rate of \(88 \%\). Assume that in one day, this airline has 1200 flights. Suppose we pick one day in December and find the number of ontime Alaska Airline arrivals. Why would it be inappropriate to use the binomial model to find the probability that at least 1100 of the 1200 flights arrive on time? What condition or conditions for use of the binomial model is or are not met?

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