/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 In a 2009 study reported in the ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In a 2009 study reported in the New England Journal of Medicine, Boyer et al. randomly assigned children aged 6 months to 18 years who had nonlethal scorpion stings to receive an experimental antivenom or a placebo. "Good" results were no symptoms after four hours and no detectable plasma venom. $$ \begin{array}{|lccc|} \hline & \text { Antivenom } & \text { Placebo } & \text { Total } \\ \hline \text { No Improvement } & 1 & 6 & 7 \\ \hline \text { Improvement } & 7 & 1 & 8 \\ \hline \text { Total } & 8 & 7 & 15 \\ \hline \end{array} $$ The alternative hypothesis is that the antivenom leads to improvement. The p-value for a one-tailed Fisher's Exact Test with these data is \(0.009\). a. Suppose the study had turned out differently, as in the following table. $$ \begin{array}{|lcc|} \hline & \text { Antivenom } & \text { Placebo } \\ \hline \text { Bad } & 0 & 7 \\ \hline \text { Good } & 8 & 0 \\ \hline \end{array} $$ Would Fisher's Exact Test have led to a p-value larger or smaller than 0.009? Explain. b. Suppose the study had turned out differently, as in the following table. $$ \begin{array}{|lcc|} \hline & \text { Antivenom } & \text { Placebo } \\ \hline \text { Bad } & 2 & 5 \\ \hline \text { Good } & 6 & 2 \\ \hline \end{array} $$ Would Fisher's Exact Test have led to a p-value larger or smaller than 0.009? Explain. c. Try the two tests, and report the p-values. Were you right? Search for a Fisher's Exact Test calculator on the Internet, and use it.

Short Answer

Expert verified
In the perfect study, the p-value would likely be less than 0.009 due to the definitive effectiveness of the antivenom. In the less perfect study, the p-value would likely be more than 0.009 because the effectiveness is less clear. The exact p-values for both scenarios can be computed using a Fisher's Exact Test calculator.

Step by step solution

01

Predict the p-value in the perfect study

Given that the effectiveness of antivenom is much more prominent in this scenario, it is expected that the p-value is going to be smaller than 0.009.
02

Predict the p-value in the less perfect study

In this case, the effect of the antivenom is less definitive. Thus, the p-value is expected to be larger than 0.009 as the clear efficacy of the antivenom is lessened.
03

Compute the p-values

To check the predictions from Steps 1 and 2, use a Fisher's Exact Test calculator. Input the values from the contingency tables given in parts a and b, and let the calculator do the computation for the p-value. Repeat this for both tables.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fisher's Exact Test
Fisher's Exact Test is a statistical method used to determine if there are nonrandom associations between two categorical variables. It is particularly useful when dealing with small sample sizes, as it provides an exact p-value rather than an approximation. In the context of our study, it allows us to assess whether the observed distribution of 'Good' and 'Bad' results across the antivenom and placebo groups is due to chance or is statistically significant.

It is based on the principle of exact probabilities and uses a hypergeometric distribution to calculate the likelihood of obtaining the observed data, or data that is more extreme, assuming that there is no association between the variables (i.e., under the null hypothesis). This test is ideal for 2x2 contingency tables like those presented in the exercise, making it a perfect choice for small samples in medical research like the antivenom study.
p-value
The p-value is a critical concept in hypothesis testing and represents the probability of finding the observed data, or something more extreme, given that the null hypothesis is true. A lower p-value indicates stronger evidence against the null hypothesis, suggesting that the alternative hypothesis may be true.
  • If the p-value is below a predefined threshold (commonly 0.05), we reject the null hypothesis.
  • A p-value of 0.009, as found in the initial study, suggests strong evidence against the null hypothesis.
In our study example, we are interested in whether the antivenom is effective. The p-value helps us understand the likelihood that our observed pattern of effects - the differences in improvement between the antivenom and placebo groups - happened by mere chance.
Contingency Tables
Contingency tables are a fundamental tool for summarizing data in categorical format. They help organize data into a matrix format, allowing easy visualization of the relationships between two qualitative variables. They form the basis for tests like Fisher's Exact Test.

For instance, let's consider the study on scorpion antivenom. Here, a contingency table displays cases with 'Good' or 'Bad' outcomes for each treatment group (Antivenom vs. Placebo). It essentially provides a snapshot of how subjects respond differently to the two treatments.
  • Columns represent the different treatments or categories (e.g., Antivenom, Placebo).
  • Rows represent different outcomes (e.g., Bad, Good).
  • The total counts in cells allow for calculating probabilities and performing statistical tests.
These tables are vital for conducting statistical analyses as they offer a structured way to examine relationships in data.
Alternative Hypothesis
The alternative hypothesis is an essential aspect of inferential statistics, representing the statement that contradicts the null hypothesis. It posits that there is a significant effect or a relationship between variables.

In the context of the scorpion antivenom study, the alternative hypothesis is that the antivenom leads to a better improvement rate compared to the placebo. It's what the researchers hope to show evidence for through statistical testing.
  • It suggests that the positive or negative effect observed is unlikely to be due to random chance alone.
  • If the p-value is low, it challenges the null hypothesis and suggests support for the alternative hypothesis.
  • For the improvement seen in the antivenom group, a significant p-value would indicate that these results are not likely due to random variations.
Therefore, accepting the alternative hypothesis implies that the intervention (antivenom) has a real impact compared to the control (placebo). This is the ultimate goal of such clinical trials.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Cockroaches tend to rest in groups and prefer dark areas. In a study by Halloy et al. published in Science Magazine in November 2007 , cockroaches were introduced to a brightly lit, enclosed area with two different available shelters, one darker than the other. Each time a group of cockroaches was put into the brightly lit area will be called a trial. When groups of 16 real cockroaches were put in a brightly lit area, in 22 out of 30 trials, all the cockroaches went under the same shelter. In the other 8 trials, some of the cockroaches went under one shelter, and some under the other one. Another group consisted of a mixture of real cockroaches and robot cockroaches ( 4 robots and 12 real cockroaches). The robots did not look like cockroaches but had the odor of male cockroaches, and they were programmed to prefer groups (and brighter shelters). There were 30 trials. In 28 of the trials, all the cockroaches and robots rested under the same shelter, and in 2 of the trials they split up. $$ \begin{array}{|l|cc|} \hline & \text { Cockroaches Only } & \text { Robots Also } \\ \hline \text { One Shelter Used } & 22 & 28 \\ \hline \text { Both Shelters Used } & 8 & 2 \\ \hline \end{array} $$ Is the inclusion of robots associated with whether they all went under the same shelter? To answer the following questions, assume the cockroaches are a random sample of all cockroaches. a. Use a chi-square test for homogeneity with a significance level of \(0.05\) to see whether the presence of robots is associated with whether roaches went into one shelter or two. b. Repeat the question using Fisher's Exact Test. (If your software will not perform the test for you, search for Fisher's Exact Test on the Internet to do the calculations.) Conduct a two-sided hypothesis test so that the test is consistent with the test in part a. c. Compare the p-values and conclusions from part a and part b. Which statistical test do you think is the better procedure in this case? Why?

In a 2015 study reported in the New England Journal of Medicine, Du Toit et al. randomly assigned infants who were likely to develop a peanut allergy (as measured by having eczema, egg allergies, or both) to either consume or avoid peanuts until 60 months of age. The infants in this cohort did not previously show any preexisting sensitivity to peanut extract. The numbers in each group developing a peanut allergy by 60 months of age are shown in the following table. $$ \begin{array}{lcc} & \text { Treatment Group } \\ \hline \begin{array}{l} \text { Peanut allergy at age } \\ \mathbf{6 0} \text { mos. } \end{array} & \text { Consume peanuts } & \text { Avoid peanuts } \\ \hline \text { Yes } & 5 & 37 \\ \hline \text { No } & 267 & 233 \\ \hline \end{array} $$ a. Compare the percentages in each group that developed a peanut allergy by age 60 months. b. Test the hypothesis that treatment group and peanut allergy are associated using the chi-square statistic. Use a significance level of \(0.05\). c. Do a Fisher's Exact Test for the data with the same significance level. Report the two-tailed p-value and your conclusion. (Use technology to run the test.) d. Compare the p-valucs for parts \(\mathrm{b}\) and \(\mathrm{c}\). Which is morc accurate? Explain.

You flip a coin 100 times and get 58 heads and 42 tails. Calculate the chi- square statistic by hand, showing your work, assuming the coin is fair.

Here are the conviction rates with the "stand your ground" data mentioned in the previous exercise. "White shooter on nonwhite" means that a white assailant shot a minority victim. $$ \begin{array}{lr} & \text { Conviction Rate } \\ \hline \text { White shooter on white } & 35 / 97=36.1 \% \\ \text { White shooter on nonwhite } & 3 / 21=14.3 \% \\ \text { Nonwhite shooter on white } & 8 / 22=36.4 \% \\ \text { Nonwhite shooter on nonwhite } & 11 / 45=24.4 \% \end{array} $$ a. Which has the higher conviction rate: white shooter on nonwhite or nonwhite shooter on white? b. Create a two-way table using White Shooter on Nonwhite and NonWhite Shooter on White across the top and Convicted and Not Con- victed on the side. c. Test the hypothesis that race and conviction rate (for these two groups) are independent at the \(0.05\) level. d. Because some of the expected counts are pretty low, try a Fisher's Exact Test with the data, reporting the p-value (two-tailed) and the conclusion.

Suppose a polling organization asks a random sample of people if they are Democrat, Republican, or Other and asks them if they think the country is headed in the right direction or the wrong direction. If we wanted to test whether party affiliation and answer to the question were associated, would this be a test of homogeneity or a test of independence? Explain.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.