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Stradivarius violins, made in the 1700 s by a man of the same name, are worth millions of dollars. They are prized by music lovers for their uniquely rich, full sound. In September 2009 , an audience of experts took part in a blind test of violins, one of which was a Stradivarius. There were four other violins (modernday instruments) made of specially treated wood. When asked to pick the Stradivarius after listening to all five violins, 39 got it right and 113 got it wrong (Time, November 23,2009 ). a. If this group were just guessing, how many people (out of the 152 ) would be expected to guess correctly? And how many would be expected to guess incorrectly? b. Calculate the observed value of the chi-square statistic showing each step of the calculation.

Short Answer

Expert verified
The expected number of individuals who guess correctly and incorrectly (if guessing were random) are 30.4 and 121.6, respectively. The calculated chi-square statistic for this data is approximately 2.526.

Step by step solution

01

Calculate Expected Values

Divide the total number of guesses (152) by the number of violins (5). This will give the expected number of correct guesses if the group was just guessing. Then, subtract this value from the total number of guesses to find the expected number of incorrect guesses. For example: Expected correct = 152 / 5 = 30.4 guesses. Expected incorrect = 152 - 30.4 = 121.6 guesses.
02

Calculate Chi-Square Statistic

The chi-square statistic evaluates how well the observed data fit the expected data. It is calculated using the formula: \(\chi^2\) = \(\sum [ (Observed-Expected)^2 / Expected ]\). Fill in the observed and expected values: \(\chi^2\) = [ (39-30.4)^2 / 30.4 ] + [ (113-121.6)^2 / 121.6 ]. This will yield the chi-square statistic value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Significance
Understanding statistical significance is crucial when analyzing experimental data, as it helps us determine whether the results of an experiment are likely due to chance or to a specific cause. In the context of the Stradivarius violin experiment, statistical significance would allow us to assess if listeners were able to reliably identify the Stradivarius over other violins, or if the correct guesses were just random.

When conducting a chi-square test, the calculation of the chi-square statistic gives us a numerical value that we can compare against a critical value from the chi-square distribution table. The critical value is determined based on the desired level of significance (commonly 0.05 for a 5% chance that the results are due to random variation) and the degrees of freedom in the experiment. If the computed chi-square statistic exceeds the critical value, we consider the results statistically significant, suggesting that performance was better (or worse) than random chance. In the violin experiment, comparing the chi-square statistic to the critical value would show us if the ability to identify the Stradivarius is statistically significant or not.

It's important to note that statistical significance does not necessarily imply practical significance; it simply indicates that the results are not likely due to random chance. The actual importance and applicability of the results need to be considered in its real-world context.
Hypothesis Testing
The backbone of many statistical analyses is hypothesis testing, a method used to decide between two competing hypotheses. In the case of the Stradivarius violins, hypothesis testing is used to evaluate whether listeners can truly differentiate a Stradivarius from other violins based on sound alone.

The first step in hypothesis testing is to establish the null hypothesis ((H_0)), which essentially states that there is no effect or no difference, and in our case, it would be that people are just guessing when identifying the Stradivarius. Contrarily, the alternative hypothesis ((H_A)), suggests that participants can genuinely identify the Stradivarius. After conducting the test and calculating the chi-square statistic, we compare the value to a threshold (critical value) to determine if we should reject the null hypothesis or not. In the Stradivarius example, the chi-square test helps to decide whether the ability to identify the violin is due to skill/knowledge or if it's due to chance.

In hypothesis testing, it's essential to understand the concepts of Type I and Type II errors. A Type I error happens when we wrongly reject the null hypothesis, while a Type II error occurs when we fail to reject a false null hypothesis. The chi-square test helps minimize these errors by providing a framework to make decisions regarding the hypotheses.
Expected Value
The notion of expected value plays a significant role in statistics, especially when dealing with categorical data, as in the chi-square test. It represents the anticipated value of a variable if we were to sample the population many times. In hypothesis testing scenarios, such as with the Stradivarius violins, the expected value is calculated under the assumption of the null hypothesis.

In the violin listeners' test, the expected value for correct and incorrect guesses was calculated assuming that each person was equally likely to guess any of the five violins correctly—purely based on chance. This gives us an expected correct guess count (30.4) and incorrect guess count (121.6) when the sample size (152) is equally divided among the possible choices (5 violins).

The expected values serve as a benchmark against which we measure the observed values. If the observed frequencies differ significantly from the expected frequencies, we have grounds to believe that something other than chance is at play. In the example, the chi-square test takes the discrepancy between the observed and expected values to assess the likelihood that the observed distribution of guesses is due to random guessing or if the participants could discern the unique qualities of the Stradivarius.

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Most popular questions from this chapter

Professional musicians listened to five violins being played, without seeing the instruments. One violin was a Stradivarius, and the other four were modern-day violins. When asked to pick the Stradivarius (after listening to all five), 39 got it right and 113 got it wrong. a. Use the chi-square goodness-of-fit test to test the hypothesis that the experts are not simply guessing. Use a significance level of \(0.05\). b. Perform a one-proportion \(z\) -test with the same data, using a one-tailed alternative that the experts should get more than \(20 \%\) correct. Use a significance level of \(0.05\). c. Compare your p-values and conclusions.

The 2018 Pew Research poll in exercise \(10.43\) also reported responses by political party. Survey results found \(45 \%\) of Republicans and \(69 \%\) of Democrats supported marijuana legalization. a. Use these results to fill in the following two-way table with the counts in each category. Assume the sample size for each group was 200 . b. Test the hypothesis that support of marijuana legalization is independent of political party for these two groups using a significance level of \(0.05 .\) c. Does this suggest that these political parties differ significantly in their support of marijuana legalization?

A 2018 Gallup poll asked college graduates if they agreed that the courses they took in college were relevant to their work and daily lives. The respondents were also classified by their field of study. If we wanted to test whether there was an association between response to the question and the field of study of the respondent, should we do a test of independence or homogeneity?

A vaccine is available to prevent the contraction of human papillomavirus (HPV). The Centers for Disease Control and Prevention recommends this vaccination for all young girls in two doses. In a 2015 study reported in the Journal of American College Health, Lee et al. studied vaccination rates among Asian American and Pacific Islander (AAPI) women and non-Latina white women. Data are shown in the table. Test the hypothesis that vaccination rates and race are associated. Use a \(0.05\) significance level. $$ \begin{array}{|lcc|} \hline \text { Completed HPV vaccinations } & \text { AAPI } & \text { White } \\\ \hline \text { Yes } & 136 & 1170 \\ \hline \text { No } & 216 & 759 \\ \hline \end{array} $$

A 2018 Pew Research poll recorded respondents political affiliation and generation. A summary of the results for Millennials and GenXers are shown in the following table, assuming a sample size of 200 . Test the hypothesis that political party affiliation and generation are associated at the \(0.05\) level for these generations. $$ \begin{array}{|lcc|} \hline & \text { Political Party Affiliation } \\ \hline \text { Generation } & \text { Democrat } & \text { Republican } \\ \hline \text { Millennials } & 118 & 64 \\ \hline \text { GenX } & 98 & 86 \\ \hline \end{array} $$

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