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An average of \(1.4\) private airplanes arrive per hour at an airport. a. Find the probability that during a given hour no private airplane will arrive at this airport. b. Let \(x\) denote the number of private airplanes that will arrive at this airport during a given hour. Write the probability distribution of \(x\). Use the appropriate probabilities table from Appendix \(B\).

Short Answer

Expert verified
a) The probability of no airplanes arriving is obtained by inputting \(x = 0\) and \(\lambda = 1.4\) into the Poisson distribution formula. b) The probability distribution of \(x\) can be found by substituting various reasonable values of \(x\) into the Poisson distribution formula and summarizing in a table.

Step by step solution

01

Calculate the Probability of No Airplanes Arriving

To find the probability that no planes will arrive, we want the expected number (\(k\)) to be 0. We substitute \(k = 0\) and \(\lambda = 1.4\) into the Poisson distribution formula to get: \( P(X=0) = (1.4^0 * e^{-1.4}) / 0! \). Now, continue to calculate.
02

Calculate the Probability for Various Values of \(x\)

To find the probability distribution of \(x\), we substitute different values of \(x = k\) into the Poisson distribution formula to develop a table. It should include all reasonable values of \(x\), given that we are told there is an average of 1.4 airplanes per hour. Thus, it would be logical to calculate probabilities for \(x = 0\) (already done in step 1), \(x = 1\), \(x = 2\), ..., and so on up to a rational limit like \(x = 10\). Once done, the table should summarize the calculated probabilities for each value.
03

Create the Probability Distribution

To form a distribution, list all the probabilities calculated in step 2 for each possible value of \(x\). This will create a table showing the number of airplanes arriving and the associated probability.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Distribution
A probability distribution describes how likely different outcomes are in a random process. For our case, we're looking at the Poisson distribution, which is a common model used for count-based data. It helps us understand the probabilities of a given number of events, like airplane arrivals, happening within a fixed interval of time or space. In mathematical terms, the Poisson distribution gives us the probability that a certain number of events, denoted as \( x \), will happen, given an average rate \( \lambda \). This formula is helpful when we know the average events but want to predict specific occurrences.

To construct a probability distribution for airplane arrivals, we take this average rate (\( \lambda = 1.4 \) arrivals per hour) and apply the Poisson formula for various \( x \) values, like 0, 1, 2, etc. This approach helps to visualize the likelihood of different numbers of arrivals, making it easier to predict and prepare for such events.
Expected Number
The expected number in the context of a Poisson distribution is a key concept. It tells us the average or mean number of events we anticipate over a certain period. Here, the expected number of private airplane arrivals per hour is given as \( \lambda = 1.4 \). This number represents our average rate of occurrences over the specified period.

This average is critical because it allows us to set our expectations realistically. Whether planning resources or preparing for operational tasks, knowing this average helps. It's a statistical cornerstone that feeds into the calculations of specific probabilities for individual event counts. Knowing the expected number sets the base for further statistical analysis.
Probability Calculation
Calculating probabilities in a Poisson distribution is straightforward once you grasp the basics. The formula is:

\[ P(X = k) = \frac{\lambda^k e^{-\lambda}}{k!} \]

Here's what each term means:
  • \( \lambda \): the average rate (1.4 in our scenario).
  • \( k \): the specific number of events (e.g., 0, 1, 2).
  • \( e \): Euler's number, approximately 2.71828.
  • \( k! \): factorial of \( k \), which is the product of all positive integers up to \( k \).
For instance, to find the probability of no airplanes arriving (\( k = 0 \)), substitute these values into the formula. With \( \lambda = 1.4 \), it simplifies to:

\[ P(X = 0) = \frac{1.4^0 \cdot e^{-1.4}}{0!} = e^{-1.4} \]

Understanding this process is crucial for interpreting statistical data and making informed predictions.
Probability Table
Once probabilities for different values of \( x \) are calculated, they can be organized into a probability table. This table acts as a summary of potential outcomes and their associated probabilities.

Start by calculating the probability for each \( x \) value: 0, 1, 2, and so on until reaching a logical stopping point like \( x = 10 \). Fill these values into the table:
  • For \( x = 0 \), use the calculation \( e^{-1.4} \).
  • For \( x = 1 \), apply the formula \( \frac{1.4^1 \cdot e^{-1.4}}{1!} \).
  • Continue this process for each \( x \).
The table aids in quick reference and comparison, showcasing how likely different numbers of arrivals are within a given time. It's an efficient way to convey a dense set of potential outcomes and probabilities, facilitating better decision-making and planning.

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Most popular questions from this chapter

A high school boys' basketball team averages \(1.2\) technical fouls per game. a. Using the appropriate formula, find the probability that in a given basketball game this team will commit exactly 3 technical fouls. b. Let \(x\) denote the number of technical fouls that this team will commit during a given basketball game. Using the appropriate probabilities table from Appendix \(\mathrm{B}\), write the probability distribution of \(x\).

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