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An average of \(6.3\) robberies occur per day in a large city. a. Using the Poisson formula, find the probability that on a given day exactly 3 robberies will occur in this city. b. Using the appropriate probabilities table from Appendix \(\mathbf{B}\), find the probability that on a given day the number of robberies that will occur in this city is \(\begin{array}{lll}\text { i. at least } 12 & \text { ii. at most } 3 & \text { iii. } 2 \text { to } 6\end{array}\)

Short Answer

Expert verified
The probability of exactly 3 robberies occurring on a single day is 0.075 or 7.5%. The exact probabilities of at least 12 robberies, at most 3 robberies, and 2 to 6 robberies occurring on a given day can be obtained from the cumulative Poisson distribution table.

Step by step solution

01

Using the Poisson Formula

The Poisson formula is \(P(x; μ) = (e^-μ) * (μ^x) / x!\), where: - \(x\) is the actual number of successes that result from the experiment. - \(μ\) is the expected number of successes that occur in a specified region. - \(e\) is a constant equals to approximately 2.71828. - \(P(x; μ)\) is the Poisson probability, which is the probability of getting exactly \(x\) successes when the average number of successes is \(μ\).In this case, we are trying to find the probability that exactly 3 robberies will occur, so \(x=3\) and the average, \(μ = 6.3\). Substituting these values in, the equation becomes \(P(3; 6.3) = (e^-6.3) * (6.3^3) / 3!\).
02

Calculate the Probability

Do the calculations in the formula: - First, calculate \(e^-6.3\), which equals 0.0018. - Then, calculate \(6.3^3\), which equals 250.047. - Factorial of 3 \((3!)\), is 6.Substitute these values back in to the equation: \(P(3; 6.3) = 0.0018 * 250.047 / 6\).After calculations, \(P(3; 6.3) = 0.075\). Therefore, the probability of exactly 3 robberies occurring on a given day is 0.075 or 7.5%.
03

Using the Appendix B Table

Appendix B is a cumulative Poisson distribution table, which should be used to find:- The probability of at least 12 robberies: look up the cumulative probability for \(μ=6.3\) and \(x=11\), then subtract it from 1, because the table provides the probability of 'at most' events.- The probability of at most 3 robberies: directly look at the cumulative probability for \(μ=6.3\) and \(x=3\).- The probability of 2 to 6 robberies occurring: subtract the cumulative probability at \(x=1\) from the cumulative probability at \(x=6\) for \(μ=6.3\).
04

Read the Probabilities from the Table

Without the actual table provided we cannot find the exact probabilites required in the exercise. But one would replace this step with the values obtained from the table entry for the specified conditions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Probability calculation is a fundamental concept in statistics that enables us to determine the likelihood of specific events. In the context of the Poisson distribution, this involves calculating the probability of a certain number of events occurring within a fixed period or region. For the problem of robberies in a city, we can use the Poisson formula to find the probability of exactly three robberies on a given day.

The Poisson formula is expressed as:
  • \(P(x; μ) = \frac{(e^{-μ}) \cdot (μ^x)}{x!}\), where:
    • \(x\) is the number of events we are interested in.
    • \(μ\) is the average number of events expected.
    • \(e\) is the base of the natural logarithm, approximately 2.71828.

By plugging in the given values \(x = 3\) and \(μ = 6.3\), we perform the steps:\(e^{-6.3} = 0.0018\), \(6.3^3 = 250.047\), and \(3! = 6\).
Substituting in these values, we calculate: \(P(3; 6.3) = \frac{0.0018 \times 250.047}{6} = 0.075\). Hence, there's a 7.5% chance of exactly three robberies occurring on a given day.
Cumulative Poisson Distribution
When dealing with statistical problems that ask for questions of 'at most' or 'at least', the cumulative Poisson distribution becomes invaluable. It helps determine the probability of a number of events happening up to a point or more than a point.

The cumulative Poisson distribution table gives us probabilities for 'at most' events directly. To find the probability for 'at least' events, subtract the cumulative probability for 'at most' one less than the desired number from 1, since probabilities for all outcomes sum to 1.

For instance, in the robbery scenario:
  • For 'at most 3' robberies, directly use the table value for \(μ=6.3\) and \(x=3\).
  • For 'at least 12' robberies, find the cumulative probability of 'at most 11' and subtract from 1: \(P(X \geq 12) = 1 - P(X \leq 11)\).
  • To find the probability between two numbers, like 2 to 6, subtract the cumulative probability for \(x=1\) from that for \(x=6\): \(P(2 \leq X \leq 6) = P(X \leq 6) - P(X \leq 1)\).
The ability to manipulate these probabilities is essential to effectively utilizing cumulative Poisson tables.
Statistical Problem-Solving
Statistical problem-solving often involves identifying an appropriate model and applying tools like distributions to solve real-world problems. The exercise showcases how to select and manipulate the Poisson distribution to calculate the likelihood of discrete, independent events over a period.

Key elements to effective statistical problem-solving include:
  • Identifying the type of distribution applicable, which in scenarios of rare events with a known average rate, is typically the Poisson distribution.
  • Accurate calculation using formulas or tables depending on what is asked (e.g., exact numbers versus range of events).
  • Sensitivity to how cumulative and exact probability calculations differ and are used based on the context of 'at most', 'at least', or 'exactly' type questions.
Applying these steps helps demystify statistical problems and render them into solvable challenges. Recognizing how the parameters, such as \(μ\), affect the outcome aids in crafting well-informed conclusions that translate the abstract statistics into actionable insights.

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Most popular questions from this chapter

An average of \(1.4\) private airplanes arrive per hour at an airport. a. Find the probability that during a given hour no private airplane will arrive at this airport. b. Let \(x\) denote the number of private airplanes that will arrive at this airport during a given hour. Write the probability distribution of \(x\). Use the appropriate probabilities table from Appendix \(B\).

According to a survey conducted at the local DMV, \(50 \%\) of drivers who drive to work stated that they regularly exceed the posted speed limit on their way to work. Suppose that this result is true for the population of drivers who drive to work. A random sample of 13 drivers who drive to work is selected. Use the binomial probabilities table (Table I of Appendix B) or technology to find the probability that the number of drivers in this sample of 13 who regularly exceed the posted speed limit on their way to work is a. at most 5 b. 6 to 9 c. at least 7

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