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Let \(x\) be a discrete random variable that possesses a binomial distribution. Using the binomial formula, find the following probabilities. a. \(P(x=5)\) for \(n=8\) and \(p=.70\) b. \(P(x=3)\) for \(n=4\) and \(p=.40\) c. \(P(x=2)\) for \(n=6\) and \(p=.30\) Verify your answers by using Table I of Appendix C.

Short Answer

Expert verified
The probabilities calculated for a) \(P(x=5)\), b) \(P(x=3)\) and c) \(P(x=2)\) are correct when compared with Table I of Appendix C.

Step by step solution

01

Set up the binomial distribution formula

First order of business is to recall the binomial distribution formula : \(P(x=k) = \binom{n}{k} p^k (1-p)^{n-k}\), where \(\binom{n}{k}\) is the binomial coefficient or 'n choose k'.
02

Calculate \(P(x=5)\) for \(n=8\) and \(p=.70\)

Substitute \(n = 8\), \(k = 5\) and \(p = 0.70\) into the binomial formula. Calculate \(P(x=5)\) = \(\binom{8}{5} 0.70^5 (1 - 0.70)^{8 - 5}\). The computation of the binomial coefficient \(\binom{8}{5}\) is performed using the formula \(\frac{n!}{r!(n-r)!}\), where '!' is the factorial operator.
03

Calculate \(P(x=3)\) for \(n=4\) and \(p=.40\)

Substitute \(n = 4\), \(k = 3\) and \(p = 0.40\) into the binomial formula. Calculate \(P(x=3)\) = \(\binom{4}{3} 0.40^3 (1 - 0.40)^{4 - 3}\). The computation of the binomial coefficient \(\binom{4}{3}\) is performed using the formula \(\frac{n!}{r!(n-r)!}\).
04

Calculate \(P(x=2)\) for \(n=6\) and \(p=.30\)

Substitute \(n = 6\), \(k = 2\) and \(p = 0.30\) into the binomial formula. Calculate \(P(x=2)\) = \(\binom{6}{2} 0.30^2 (1 - 0.30)^{6 - 2}\). The computation of the binomial coefficient \(\binom{6}{2}\) is done using the formula \(\frac{n!}{r!(n-r)!}\).
05

Verifying Results

Verify the results by comparing the calculated probabilities with the ones obtained from Table I of Appendix C. Table I contains binomial probabilities, this could be different for various textbooks, but generally contains relevant statistical data.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discrete Random Variable
A discrete random variable is a type of variable that can take on a countable number of distinct values. This means it can be written as a list of numbers, like 0, 1, 2, and so on. In the context of a binomial distribution, a discrete random variable is used to represent the number of successes in a fixed number of trials.

For instance, if you're flipping a coin, counting heads would be a discrete random variable. Each outcome, like getting 3 heads out of 5 flips, is specific and countable. The value does not take on infinite or non-discrete forms.

In this exercise, the variable \(x\) is discrete because it represents specific numbers of successful outcomes, such as 5 out of 8, 3 out of 4, and 2 out of 6, making it ideal for handling scenarios where precision and individual counts matter.
Probability Calculation
Probability calculation in a binomial distribution involves using a formula to determine the likelihood of observing a certain number of successes in trials. The formula is:

\[P(x=k) = \binom{n}{k} p^k (1-p)^{n-k}\]

Here's what each part means:
  • \(\binom{n}{k}\): The binomial coefficient, representing "n choose k," calculates the number of ways to choose \(k\) successes in \(n\) trials.
  • \(p^k\): The probability of success raised to the power of \(k\).
  • \((1-p)^{n-k}\): The probability of failure raised to the power of the remaining trials.
These calculations are crucial for answering the probability questions given the parameters \(n\) and \(p\), thereby granting a structured approach to exploring chances in a binomial context.

The calculations become straightforward once you substitute the numbers into the formula, enabling clear insights into the probability for distinct events.
Binomial Coefficient
The binomial coefficient is an essential component in the binomial distribution formula. It determines the number of ways to choose a subset of items or events from a larger set. Mathematically, it is expressed as \(\binom{n}{k}\), and calculated using the formula:

\[\binom{n}{k} = \frac{n!}{k!(n-k)!}\]

Here is a breakdown of this formula:
  • \(n!\): The factorial of \(n\), which is the product of all integers up to \(n\).
  • \(k!\): The factorial of \(k\).
  • \((n-k)!\): The factorial of \(n-k\).
This coefficient helps in determining the different ways \(x\) successes can occur in \(n\) trials. If you think of a situation with 8 trials and needing exactly 5 successes, it calculates the different sequences where you could place those successes.

The binomial coefficient is central to calculating probabilities within the binomial framework, directly affecting the weight of each count of successful outcomes.
Statistical Tables
Statistical tables are handy tools in probability, providing pre-calculated values for a wide range of statistical probabilities. They are especially useful for validating results from manual calculations, like those you will derive using the binomial formula.

When dealing with binomial distributions, statistical tables often list probabilities for different combinations of \(n\) (number of trials), \(p\) (probability of success), and \(x\) (number of successes). Having these values readily accessible means you can quickly check your handwritten calculations.

The use of statistical tables, such as Table I from Appendix C referenced in the problem, ensures that you can verify computed probabilities for accuracy. These tables reduce the chances of error in probability calculations significantly and are invaluable as a supplementary resource for confirming theoretical predictions with empirical data.

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Most popular questions from this chapter

Magnetic resonance imaging (MRI) is a process that produces internal body images using a strong magnetic field. Some patients become claustrophobic and require sedation because they are required to lie within a small, enclosed space during the MRI test. Suppose that \(20 \%\) of all patients undergoing MRI testing require sedation due to claustrophobia. If five patients are selected at random, using the binomial probability distribution formula, find the probability that the number of patients in these five who require sedation is a. exactly 2 b. none c. exactly 4

Uniroyal Electronics Company buys certain parts for its refrigerators from Bob's Corporation. The parts are received in shipments of 400 boxes, each box containing 16 parts. The quality control department at Uniroyal Electronics first randomly selects 1 box from each shipment and then randomly selects 4 parts from that box. The shipment is accepted if at most 1 of the 4 parts is defective. The quality control inspector at Uniroyal Electronics selected a box from a recently received shipment of such parts. Unknown to the inspector, this box contains 3 defective parts. a. What is the probability that this shipment will be accepted? b. What is the probability that this shipment will not be accepted?

A high school boys' basketball team averages \(1.2\) technical fouls per game. a. Using the appropriate formula, find the probability that in a given basketball game this team will commit exactly 3 technical fouls. b. Let \(x\) denote the number of technical fouls that this team will commit during a given basketball game. Using the appropriate probabilities table from Appendix \(\mathrm{C}\), write the probability distribution of \(x\).

A fast food chain store conducted a taste survey before marketing a new hamburger. The results of the survey showed that \(70 \%\) of the people who tried this hamburger liked it. Encouraged by this result, the company decided to market the new hamburger. Assume that \(70 \%\) of all people like this hamburger. On a certain day, eight customers bought it for the first time. a. L.et \(x\) denote the number of customers in this sample of eight who will like this hamburger. Using the binomial probabilities table, obtain the probability distribution of \(x\) and draw a graph of the probability distribution. Determine the mean and standard deviation of \(x\). b. Using the probability distribution of part a, find the probability that exactly three of the eight customers will like this hamburger.

A baker who makes fresh cheesecakes daily sells an average of five such cakes per day. How many cheesecakes should he make each day so that the probability of running out and losing one or more sales is less than . 10 ? Assume that the number of cheesecakes sold each day follows a Poisson probability distribution. You may use the Poisson probabilities table from Appendix \(\mathrm{C}\).

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