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Five percent of all items sold by a mail-order company are returned by customers for a refund. Find the probability that of two items sold during a given hour by this company, a. both will be returned for a refund b. neither will be returned for a refund Draw a tree diagram for this problem.

Short Answer

Expert verified
a. The probability that both items will be returned for a refund is 0.0025. b. The probability that neither item will be returned for a refund is 0.9025. The tree diagram will have four end branches representing the four scenarios: both items returned (0.0025), first returned second not (0.0475), first not returned second returned (0.0475), neither returned (0.9025).

Step by step solution

01

Identify the probabilities

Before we can calculate anything, we need to identify our probabilities. Here, we are given that 5 percent of all items sold are returned by customers for a refund. Therefore, \nthe probability of an item being returned, denoted as \(P(R)\), is 0.05. \nthe probability of an item not being returned, denoted as \(P(NR)\), is 1 - \(P(R) = 1 - 0.05 = 0.95.\)
02

Calculate the Probability for Both Items Being Returned

The problem asks for the probability of both items being returned. This can be symbolized as \(P(R \cap R)\) which represents the probability of the first item being returned and the second item being returned. Since the sale of both items are independent events, this can be calculated by multiplying the probabilities of the two events. Therefore, \(P(R \cap R) = P(R) * P(R) = 0.05 * 0.05 = 0.0025\)
03

Calculate the Probability for Neither Item Being Returned

Just as with Step 2, we want to find the probability that neither of the items is returned. This time we're looking for \(P(NR \cap NR)\). Similar to the above step, we multiply both probabilities. Therefore, \(P(NR \cap NR) = P(NR) * P(NR) = 0.95 * 0.95 = 0.9025\)
04

Drawing the tree Diagram

A tree diagram can help visualize these probabilities. Start with a branch for the first item sold, with the branches labelled 'Returned' (with probability 0.05) and 'Not Returned' (probability 0.95). From each of those branches, branch off again for the second item sold. Label as before. The end branches will represent the combinations of items being sold and returned/not returned, with their associated probabilities as a multiplication of the individual events' probabilities.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
In probability, independent events refer to two or more events where the outcome of one event does not affect the outcomes of the others. This concept is essential in probability calculations because it affects how probabilities are combined.

For instance, let's consider the scenario from the exercise, where two items are sold, and we need to determine the likelihood of both being returned. Whether the first item is returned does not influence the probability of the second item being returned. Thus, these events are independent. The probability of both items being returned is calculated by multiplying the individual probabilities of return for each item. This multiplication is valid only because the events are independent.

The probability of an item being returned is 0.05, so the probability that both items are returned (an independent scenario) would be:
  • \( P(R \cap R) = P(R) \times P(R) = 0.05 \times 0.05 = 0.0025 \).
Understanding the independence of these events enables accurate calculations when determining the chances that certain outcomes will occur.
Probability Tree Diagram
A probability tree diagram is a visual representation that helps illustrate all potential outcomes of a series of events and their associated probabilities. This tool is especially helpful to organize and compute probabilities when dealing with multiple stages in an event.

In our exercise, the tree diagram starts with the first item and its two potential outcomes: "Returned" with probability 0.05 and "Not Returned" with probability 0.95.
From each of these outcomes, the next item's outcomes are drawn, splitting further down the branches:
  • Under the "Returned" branch, the second item can be "Returned" (0.05) or "Not Returned" (0.95).
  • Similarly, under the "Not Returned" branch, you branch out to "Returned" (0.05) or "Not Returned" (0.95).
At the end of these branches, you can find the probabilities of all possible combinations. These branches help in visualizing complex problems and systematically understanding possible outcomes which can be matched to the probability calculations you perform.
Probability Calculation
Calculating probability involves identifying the likelihood of specific outcomes occurring among all possible outcomes. In this scenario, the key steps involve determining the probabilities of all individual events initially, and then using the rules of probability to find the required outcomes.

From the given probability of returning an item, denoted as 0.05, and not returning an item, as 0.95, we can determine:
  • The probability that both items are returned: \(P(R \cap R)\) which calculates to 0.0025.
  • The probability that neither item is returned: \(P(NR \cap NR)\) which calculates to 0.9025.
These calculations are achieved by multiplying the related probabilities of each independent event. This approach helps avoid counting overlap or missing combinations, ensuring that your calculations reflect the true complexity of real-world scenarios.

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Most popular questions from this chapter

Consider the following addition rule to find the probability of the union of two events \(A\) and \(B\) : $$ P(A \text { or } B)=P(A)+P(B)-P(A \text { and } B) $$ When and why is the term \(P(A\) and \(B\) ) subtracted from the sum of \(P(A)\) and \(P(B)\) ? Give one example where you might use this formula.

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