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Consider the following addition rule to find the probability of the union of two events \(A\) and \(B\) : $$ P(A \text { or } B)=P(A)+P(B)-P(A \text { and } B) $$ When and why is the term \(P(A\) and \(B\) ) subtracted from the sum of \(P(A)\) and \(P(B)\) ? Give one example where you might use this formula.

Short Answer

Expert verified
The term \(P(A \text { and } B)\) is subtracted from the sum of \(P(A)\) and \(P(B)\) to avoid double-counting the cases where both events \(A\) and \(B\) occur. In a practical scenario like flipping two coins, this rule can be used to determine the probability of getting a head on either the first or the second coin (or both). The probability is 0.75.

Step by step solution

01

Understanding the addition rule in probability theory

In probability theory, the addition rule calculates the probability of the occurrence of either of two events \(A\) or \(B\). This rule states that the probability of the occurrence of event \(A\) or \(B\) is equal to the sum of their individual probabilities, less the probability of their intersection. This can be mathematically represented as \(P(A \text { or } B)=P(A)+P(B)-P(A \text { and } B)\).
02

Explaining why we subtract \(P(A \text { and } B)\)

The term \(P(A \text { and } B)\) is subtracted to avoid double-counting. When we add \(P(A)\) and \(P(B)\), we are in a way 'over-counting' the cases where both events occur, as they are included in the calculations of both \(P(A)\) and \(P(B)\). Thus, we subtract the intersection \(P(A \text { and } B)\) once to correct this.
03

Illustrating with an example

As an example, consider flipping two coins. Here, let \(A\) be the event that the first coin shows a head and \(B\) the event that the second coin shows a head. So, \(P(A)= 0.5\), \(P(B)= 0.5\), and \(P(A \text { and } B)=0.25\) (as the two events are independent). Using the addition rule, the probability of either the first or the second coin (or both) showing a head is given by \(P(A \text { or } B)=P(A)+P(B)-P(A \text { and } B)=0.5+0.5-0.25=0.75\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability of Union
The probability of the union of two events, like events \(A\) and \(B\), refers to the likelihood that at least one of these events will happen. It's an important concept because it helps us understand and quantify situations where multiple outcomes are possible. Calculating this is straightforward with the addition rule in probability, but it's crucial to understand why and how we apply it.
In simple terms, the probability of either \(A\) or \(B\) occurring is found by adding the individual probabilities of \(A\) and \(B\). However, this approach initially includes the probability of both \(A\) and \(B\) happening together twice—once within each of the probabilities \(P(A)\) and \(P(B)\).
To correct this over-counting, we subtract the probability of the intersection, \(P(A \text{ and } B)\). This adjustment ensures that each possible outcome is only counted once, giving us a true representation of the likelihood that either event will occur.
Probability Theory
Probability theory is a branch of mathematics that deals with analyzing random events. It's a framework used to understand and predict phenomena with inherent unpredictability. Whether in weather forecasts or determining the chance of drawing a specific card from a deck, probability theory provides the tools required to compute the likelihood of events.
There are several key concepts in probability theory:
  • Experiments or Trials: These are processes that lead to one of several possible outcomes.
  • Events: Outcomes or sets of outcomes we are interested in, such as flipping a coin and getting heads.
  • Sample Space: The set of all possible outcomes, like all sides a die can land on.

Understanding these basics helps in applying more complex rules, such as the addition rule for the probability of unions or intersections. Each rule helps manage different types of calculations needed for various decision-making processes or forecasts in real life.
Intersection in Probability
In probability, the intersection of two events refers to outcomes where both events occur simultaneously. For instance, if \(A\) is the event "it rains" and \(B\) is "I wear a coat," then \(A\text{ and } B\) is when it rains and I wear a coat. Calculating the probability of both events occurring simultaneously involves understanding independent and dependent events.
When two events are independent, meaning the outcome of one does not affect the other, the calculation for their intersection is straightforward: \(P(A \text{ and } B) = P(A) \times P(B)\). However, in cases where events are dependent, additional adjustments may be necessary to account for the interconnected outcomes.
The idea of event intersection is crucial in applying the addition rule to avoid double-counting, as mentioned earlier. By accounting for intersections, we make sure we aren't mistakenly exaggerating the probability of occurrences by counting them more than once.

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Most popular questions from this chapter

Refer to Exercise 4.48. A 2010-2011 poll conducted by Gallup (www.gallup.com/poll/148994/ Emotional-Health-Higher-Among-Older- Americans.aspx) examined the emotional health of a large number of Americans. Among other things, Gallup reported on whether people had Emotional Health Index scores of 90 or higher, which would classify them as being emotionally well-off. The report was based on a survey of 65,528 people in the age group \(35-44\) years and 91,802 people in the age group \(65-74\) years. The following table gives the results of the survey, converting percentages to frequencies. $$ \begin{array}{lcc} \hline & \text { Emotionally Well-Off } & \text { Emotionally Not Well-Off } \\\ \hline \text { 35-44 Age group } & 16,016 & 49,512 \\ \text { 65-74 Age group } & 32,583 & 59,219 \\ \hline \end{array} $$ a. Suppose that one person is selected at random from this sample of 157,330 Americans. Find the following probabilities. i. \(P(35-44\) age group and emotionally not well-off \()\) ii. \(P(\) emotionally well-off and \(65-74\) age group \()\) b. Find the joint probability of the events \(35-44\) age group and \(65-74\) age group. Is this probability zero? Explain why or why not.

Twenty percent of a town's voters favor letting a major discount store move into their neighborhood, \(63 \%\) are against it, and \(17 \%\) are indifferent. What is the probability that a randomly selected voter from this town will either be against it or be indifferent? Explain why this probability is not equal to \(1.0\).

A player plays a roulette game in a casino by betting on a single number each time. Because the wheel has 38 numbers, the probability that the player will win in a single play is \(1 / 38 .\) Note that each play of the game is independent of all previous plays. a. Find the probability that the player will win for the first time on the 10 th play. b. Find the probability that it takes the player more than 50 plays to win for the first time. c. A gambler claims that because he has 1 chance in 38 of winning each time he plays, he is certain to win at least once if he plays 38 times. Does this sound reasonable to you? Find the probability that he will win at least once in 38 plays.

Determine the value of each of the following using the appropriate formula. $$ \begin{array}{llllllllll} 3 ! & (9-3) ! & 9 ! & (14-12) ! & { }_{5} C_{3} & { }_{7} C_{4} & { }_{9} C_{3} & { }_{4} C_{0} & { }_{3} C_{3} & { }_{6} P_{2} & { }_{8} P_{4} \end{array} $$

The Big Six Wheel (or Wheel of Fortune) is a casino and carnival game that is well known for being a big money maker for the casinos. The wheel has 54 equally likely slots (outcomes) on it. The slot that pays the largest amount of money is called the joker. If a player bets on the joker, the probability of winning is \(1 / 54\). The outcome of any given play of this game (a spin of the wheel) is independent of the outcomes of previous plays. a. Find the probability that a player who always bets on joker wins for the first time on the 15 th play of the game. b. Find the probability that it takes a player who always bets on joker more than 70 plays to win for the first time.

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