/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 115 Twenty percent of a town's voter... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Twenty percent of a town's voters favor letting a major discount store move into their neighborhood, \(63 \%\) are against it, and \(17 \%\) are indifferent. What is the probability that a randomly selected voter from this town will either be against it or be indifferent? Explain why this probability is not equal to \(1.0\).

Short Answer

Expert verified
The probability that a randomly selected voter from this town will either be against the discount store moving in or be indifferent is \(0.80\) or \(80\%\). The reason this probability is not equal to \(1.0\) is because there is a \(20\%\) probability that a voter is in favor of the move, as probabilities must total to \(1\) when considering all possible outcomes.

Step by step solution

01

Understand The Probabilities Provided

We have been told that \(63\%\) of the voters are against the store moving into their neighborhood and \(17\%\) are indifferent. These are the individual probabilities of the two groups.
02

Combine The Probabilities

Since the question asks for the combined probability of a voter either being against the store opening or indifferent, we simply add the two individual probabilities: \(63\% + 17\% = 80\%\)
03

Express The Result As A Decimal

In probability theory, probabilities are often expressed as a decimal between 0 and 1. We convert \(80\%\) to a decimal by dividing by 100: \(80\% = 0.80\)
04

Discuss Why The Probability Is Not Equal To 1.0

Though we've calculated the combined probability of a voter being against the store opening or indifferent, this value does not equal 1. This is because the overall population is divided into three groups: those against, those indifferent, and those in favor. The latter group accounts for \(20\%\) of the population, or a probability of \(0.2\). Thus, the sum of all probabilities equals 1: \(63\% + 17\% + 20\% = 100\%\), or \(0.63 + 0.17 + 0.20 = 1\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combined probability
Probability theory allows us to calculate the likelihood of multiple outcomes happening at the same time. In some situations, you are interested in knowing whether one event or another will occur. This is referred to as a **combined probability**.

A great way to determine the **combined probability** is to add together the probability of each individual event that is included. In our exercise, we know that 63% of voters are against the store moving in, and 17% are indifferent. To find the probability that a randomly selected voter is either against or indifferent, we take these two probabilities and sum them up:
  • Probability of being against: 63%
  • Probability of being indifferent: 17%
  • Combined probability: 63% + 17% = 80%
By adding these probabilities, we find that there is an 80% chance a voter falls into one of these categories. It's important to ensure events are mutually exclusive in this context, meaning a voter cannot be both for and against at the same time.
Decimal conversion
In probability theory, expressing probabilities as decimals rather than percentages makes calculations simpler and more standard across different problems. A probability can be expressed as a decimal by dividing the percentage by 100.

Let's convert the 80% combined probability of being against or indifferent to a decimal:
  • Start with 80%
  • Convert percentage to decimal: \( \frac{80}{100} = 0.80 \)
This conversion helps streamline statistical calculations, making the numbers easier to work with without the potential confusion of percentages. Always remember that the probability as a decimal should always fall between 0 and 1, where 0 indicates an impossibility and 1 a certainty.
Probability not equal to one
When calculating probabilities, the sum of all potential outcomes should equal 1, representing 100%. In this context of voters, not all are against the move or indifferent. Some do support the store’s move. This is why the combined probability of 0.80 is not equal to 1.

Here's the breakdown of probabilities:
  • Voters against: 0.63
  • Voters indifferent: 0.17
  • Voters favoring: 0.20
Adding them together we get: \(0.63 + 0.17 + 0.20 = 1.00\). If you've accounted for every possibility, the probabilities should indeed sum up to 1.0, indicating a comprehensive look at all potential outcomes. This confirms that our calculated probabilities were correct, by including every section of the voter population.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A company is to hire two new employees. They have prepared a final list of eight candidates, all of whom are equally qualified. Of these eight candidates, five are women. If the company decides to select two persons randomly from these eight candidates, what is the probability that both of them are women? Draw a tree diagram for this problem.

A thief has stolen Roger's automatic teller machine (ATM) card. The card has a four-digit personal identification number (PIN). The thief knows that the first two digits are 3 and 5 , but he does not know the last two digits. Thus, the PIN could be any number from 3500 to \(3599 .\) To protect the customer, the automatic teller machine will not allow more than three unsuccessful attempts to enter the PIN. After the third wrong PIN, the machine keeps the card and allows no further attempts. a. What is the probability that the thief will find the correct PIN within three tries? (Assume that the thief will not try the same wrong PIN twice.) b. If the thief knew that the first two digits were 3 and 5 and that the third digit was either 1 or 7 , what is the probability of the thief guessing the correct PIN in three attempts?

A trimotor plane has three engines-a central engine and an engine on each wing. The plane will crash only if the central engine fails and at least one of the two wing engines fails. The probability of failure during any given flight is \(.005\) for the central engine and \(.008\) for each of the wing engines. Assuming that the three engines operate independently, what is the probability that the plane will crash during a flight?

A player plays a roulette game in a casino by betting on a single number each time. Because the wheel has 38 numbers, the probability that the player will win in a single play is \(1 / 38 .\) Note that each play of the game is independent of all previous plays. a. Find the probability that the player will win for the first time on the 10 th play. b. Find the probability that it takes the player more than 50 plays to win for the first time. c. A gambler claims that because he has 1 chance in 38 of winning each time he plays, he is certain to win at least once if he plays 38 times. Does this sound reasonable to you? Find the probability that he will win at least once in 38 plays.

Given that \(P(B \mid A)=.70\) and \(P(A\) and \(B)=.35\), find \(P(A)\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.