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In how many ways can a sample (without replacement) of 5 items be selected from a population of 15 items?

Short Answer

Expert verified
The number of ways a sample of 5 items can be selected from a population of 15 items is \( C(15, 5) = 3,003 \).

Step by step solution

01

Understand the Problem

We are given a population of 15 items, and we need to select a sample of 5 items without replacement (meaning each item can only be selected once). The important thing to remember here is that the order of chosen items is not important, meaning it's a combination, not permutation.
02

Use Combination Formula

In mathematics, the combination formula is used when we need to determine the number of ways to choose r objects from a set of n objects, which is represented as \( C(n, r) \). Here, the 'n' is the total number of objects (in this case 15 items), and 'r' is the number of objects we select (in this case 5 items). The combination formula is \( C(n, r) = \frac{n!}{r!(n-r)!} \), where '!' denotes factorial, which is the product of all positive integers up to that number.
03

Substitute the Values

By substituting n=15, r=5 into the combination formula, we want to find the value of \( C(15, 5)= \frac{15!}{5!(15-5)!} \).
04

Simplify the Expression

To calculate this expression, first calculate the values of 15!, 5! and 10!(15-5), and then perform the division. This will give us our final answer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combination formula
The combination formula is a tool used in combinatorics to find out how many ways you can choose a subset of items from a larger set. When we're talking about combinations, remember that the order in which you choose the items doesn't matter.
  • For example, choosing a team of 3 players out of 5 is the same if you pick A, B, C or C, A, B.
To use the combination formula, which is expressed as \( C(n, r) = \frac{n!}{r!(n-r)!} \), where:
  • \(n\) is the total number of items in your set.
  • \(r\) is the number of items you want to select.
  • \(!\) denotes factorial, the product of all positive integers up to that number.
This formula helps us calculate the possible ways to choose \(r\) items from a set of \(n\) items without caring about the order of selection.
Factorial
A factorial, denoted by an exclamation mark \(!\), represents the product of all positive integers up to a given number. Factorials are a key concept in permutations and combinations, as they help find the total number of ways to arrange a set of items.For example, to calculate 5! (5 factorial), you multiply all whole numbers from 1 to 5:\[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \]The factorial function grows very quickly. For instance, 0! is defined to be 1 because there's exactly one way to arrange zero items: do nothing!Understanding how to compute factorials is essential when using the combination and permutation formulas, as they are embedded in the mathematical equations for calculating choice and arrangement possibilities.
Sample without replacement
"Sample without replacement" is a concept where each item in a population is selected once and cannot be chosen again. This method affects how combinations and probabilities are calculated. In our example, we take a sample of 5 items from a group of 15. Once an item is selected, it can't be chosen again. This fact highlights why combinations, rather than permutations, are used.
  • In permutations, the order matters, and you can select the same item multiple times.
  • Here, once an item is picked, it can't be included in any further selections, reducing the total number of choices with each pick.
This approach ensures that our calculation remains accurate to real-world scenarios where repetition is not allowed.
Permutation vs Combination
Understanding the difference between permutation and combination is crucial in combinatorics.
  • Permutations are arrangements where the order of items matters. For example, the sequences ABC and BAC are different permutations of the letters A, B, and C.
  • Combinations, on the other hand, focus on selection, where the order does not matter. For instance, choosing teams from a pool of candidates is a classic combination problem because it doesn't matter which order team members are picked.
In combination, the goal is to identify how many ways you can select a group of items, not how you can arrange them. In permutation, it's all about how you can organize a set of items once they're chosen. Thus, when the order doesn't matter, combinations are the go-to method of calculation. When order is essential, like in arranging books on a shelf, permutations are needed. Distinguishing between these scenarios is vital for solving combinatorial problems accurately.

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Most popular questions from this chapter

Powerball is a game of chance that has generated intense interest because of its large jackpots. To play this game, a player selects five different numbers from 1 through 59, and then picks a Powerball number from 1 through \(39 .\) The lottery organization randomly draws 5 different white balls from 59 balls numbered 1 through 59 , and then randomly picks a Powerball number from 1 through \(39 .\) Note that it is possible for the Powerball number to be the same as one of the first five numbers. a. If a player's first five numbers match the numbers on the five white balls drawn by the lottery organization and the player's Powerball number matches the Powerball number drawn by the lottery organization, the player wins the jackpot. Find the probability that a player who buys one ticket will win the jackpot. (Note that the order in which the five white balls are drawn is unimportant.) b. If a player's first five numbers match the numbers on the five white balls drawn by the lottery organization, the player wins about \(\$ 200,000\). Find the probability that a player who buys one ticket will win this prize.

Briefly explain the three approaches to probability. Give one example of each approach.

A box contains three items that are labeled \(\mathrm{A}, \mathrm{B}\), and \(\mathrm{C}\). Two items are selected at random (without replacement) from this box. List all the possible outcomes for this experiment. Write the sample space \(S .\)

The probability that a randomly selected college student attended at least one major league baseball game last year is .12. What is the complementary event? What is the probability of this complementary event?

Five hundred employees were selected from a city's large private companies, and they were asked whether or not they have any retirement benefits provided by their companies. Based on this information, the following two-way classification table was prepared. $$ \begin{array}{lcc} & {\text { Have Retirement Benefits }} \\ \hline & \text { Yes } & \text { No } \\ \hline \text { Men } & 225 & 75 \\ \text { Women } & 150 & 50 \\ \hline \end{array} $$ Suppose one employee is selected at random from these 500 employees. Find the following probabilities. a. The probability of the union of events "woman" and "yes" b. The probability of the union of events "no" and "man"

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