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91Ó°ÊÓ

The probability that a randomly selected college student attended at least one major league baseball game last year is .12. What is the complementary event? What is the probability of this complementary event?

Short Answer

Expert verified
The complementary event is a college student did not attend any major league baseball games last year, and the probability of this occurring is 0.88.

Step by step solution

01

Define the Event

The given event is that a college student attended at least one major league baseball game last year, with a probability of 0.12.
02

Define the Complementary Event

The complementary event is the opposite of the given event, which means that the complementary event in question is a college student who did not attend any major league baseball games last year.
03

Calculate the Probability of the Complementary Event

The sum of the probabilities of an event and its complement is 1, therefore, to find the probability of the complementary event, subtract the probability of the given event from 1. That will be \( 1 - 0.12 = 0.88 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is the likelihood or chance of an event occurring. It's often expressed as a number between 0 and 1. Here, 0 means the event will not happen, and 1 means the event is certain to happen. The concept allows us to predict how likely it is for a specific occurrence, like a college student attending a baseball game. In our context, the probability given is 0.12. This means there is a 12% chance that a randomly selected college student attended at least one major league baseball game last year.
Probabilities are beneficial in many fields, including finance, healthcare, and everyday decisions. They help estimate uncertainties and make informed predictions about future events. Recognizing the basics of probability can enhance critical thinking and decision-making skills.
Complementary Events
Complementary events represent an intriguing concept in probability theory. They are essentially pairs of outcomes that together encompass all possible scenarios of an event. If one outcome happens, the other cannot, and vice versa. If we know the probability of an event, the probability of its complementary event can be easily calculated as they both sum to 1.
In the given problem, the complementary event to a student attending a baseball game is the student not attending any game. The probability of not attending is calculated by subtracting the probability of attending from 1, which yields 0.88. This means there is an 88% chance that a college student did not attend a game last year.
  • Event: Attending a game (probability: 0.12)
  • Complementary Event: Not attending (probability: 0.88)
Understanding complementary events is critical because it helps us consider all potential outcomes, providing a complete perspective on the analysis of probabilities.
Random Selection
Random selection is an essential process in statistics. It involves choosing individuals or items from a larger population in such a manner that each has an equal chance of being selected. This technique is important because it minimizes bias and ensures that the sample represents the entire population fairly.
When analyzing probability, like in our example, random selection helps ensure that the conclusions we draw about college students attending baseball games are reliable. By randomly selecting, the results are likely to reflect the true habits and preferences of all students.
Here’s why random selection is crucial:
  • It prevents bias in selecting participants.
  • Ensures that every member has a fair chance of being included.
  • Helps to make generalizations about larger populations.
Thus, the probability obtained from a randomly selected sample is more trustworthy and applicable to the entire group.
College Students
In this context, college students are the focus group whose attendance behavior at major league baseball games is analyzed through probability concepts. Understanding this group's habits is crucial for both marketing strategies for sports events and educational insights.
College students often differ from the general population due to their unique lifestyles and schedules. Hence, recognizing specific probability patterns in their behavior can aid decision-makers in forming strategies that are better tailored to their interests. For instance, knowing that 12% of students attended at least one baseball game might influence how universities or sports franchises target promotional efforts.
  • Unique lifestyle habits.
  • Potential target for marketing strategies.
  • Valuable data for understanding youth trends in sports engagement.
Analyzing college students’ behaviors using probability offers significant insights, illustrating the power of combining probability with demographics.

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Most popular questions from this chapter

Suppose that \(20 \%\) of all adults in a small town live alone, and \(8 \%\) of the adults live alone and have at least one pet. What is the probability that a randomly selected adult from this town has at least one pet given that this adult lives alone?

Consider the following addition rule to find the probability of the union of two events \(A\) and \(B\) : $$ P(A \text { or } B)=P(A)+P(B)-P(A \text { and } B) $$ When and why is the term \(P(A\) and \(B\) ) subtracted from the sum of \(P(A)\) and \(P(B)\) ? Give one example where you might use this formula.

Recent uncertain economic conditions have forced many people to change their spending habits. In a recent telephone poll of 1000 adults, 629 stated that they were cutting back on their daily spending. Suppose that 322 of the 629 people who stated that they were cutting back on their daily spending said that they were cutting back "somewhat" and 97 stated that they were cutting back "somewhat" and "delaying the purchase of a new car by at least 6 months". If one of the 629 people who are cutting back on their spending is selected at random, what is the probability that he/she is delaying the purchase of a new car by at least 6 months given that he/she is cutting back on spending "somewhat?"

Given that \(A\) and \(B\) are two mutually exclusive events, find \(P(A\) or \(B\) ) for the following. a. \(P(A)=.71\) and \(P(B)=.03\) b. \(P(A)=.44\) and \(P(B)=.38\)

A man just bought 4 suits, 8 shirts, and 12 ties. All of these suits, shirts, and ties coordinate with each other. If he is to randomly select one suit, one shirt, and one tie to wear on a certain day, how many different outcomes (selections) are possible?

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