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Perform the following tests of hypotheses, assuming that the populations of paired differences are normally distributed. a. \(H_{0} \cdot \mu_{d f}=0, \quad H_{1}: \mu_{d} \neq 0, \quad n=9, \quad \bar{d}=6.7, \quad s_{d}=2.5, \quad \alpha=.10\) b. \(H_{0}: \mu_{d}=0, \quad H_{1}: \mu_{d}>0, \quad n=22, \quad \bar{d}=14.8, \quad s_{d}=6.4, \quad \alpha=.05\) c. \(H_{0}=\mu_{d}=0, \quad H_{1}: \mu_{d}<0, \quad n=17, \quad \bar{d}=-9.3, \quad s_{d}=4.8, \quad \alpha=.01\)

Short Answer

Expert verified
Based on the given parameters and completion of the hypothesis testing: For (a) we reject \(H_{0}\) in favour of \(H_{1}: \mu_{d} \neq 0\). For (b) we reject \(H_{0}\) in favour of \(H_{1}: \mu_{d}>0\), and for (c) we reject \(H_{0}\) in favour of \(H_{1}: \mu_{d}<0\). This suggests that there is a significant difference in the mean of the differences for all scenarios.

Step by step solution

01

Determine the Type of Test

For (a), since we have \(H_{1}: \mu_{d} \neq 0\), we are dealing with a two-tailed test. For (b), as we have \(H_{1}: \mu_{d}>0\), it is a right-tailed test. In (c), with \(H_{1}: \mu_{d}<0\), we have a left-tailed test.
02

Calculate the Test Statistic for Each Hypothesis Test

Next, the test statistic (t-score) needs to be calculated using the formula: \(t = \frac{\bar{d} - \mu_{d}}{s_{d} / \sqrt{n}}\). For (a), we substitute the given values into this formula to get \(t = \frac{6.7 - 0}{2.5 / \sqrt{9}} = 8.04\). For (b), we get \(t = \frac{14.8 - 0}{6.4 / \sqrt{22}} = 10.56\). For (c), we compute \(t = \frac{-9.3 - 0}{4.8 / \sqrt{17}} = -8.62\).
03

Compare the Test Statistic with the Critical Value

The next step is to find the critical value for each test from the t-distribution table. We compare the test statistic calculated in Step 2 with the critical value(s). For a two-tailed test, calculate \(\alpha / 2\) and for one-tailed tests use \(\alpha\) to find the critical value. As our test statistics in all cases exceed the critical values, we reject the null hypothesis for each test.
04

Draw Conclusions

For each test, rejecting the null hypothesis means accepting the alternative hypothesis, and hence we can conclude that the population mean of differences \(\mu_{d}\) is significantly different from 0 for all.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Paired Differences
Paired differences come into play when comparing two related groups. Think of them as differences in measurements taken on the same subject before and after a certain event. For example, measuring students' test scores before and after a special training course. By focusing on the change, rather than individual scores, you get clearer insights.

It's important because it helps eliminate other variables that might affect results, ensuring your test focuses on the actual impact. The mean of these differences is denoted as \( \bar{d} \) and provides insights into overall trends in your data. Paired differences are crucial in hypothesis testing to determine if a significant change has occurred.
All About the T-Distribution
The t-distribution is a bit like a normal distribution but thicker at the tails. It’s perfect for small sample sizes, especially when the population standard deviation isn't known. Why is it used here? Because it provides a more accurate estimate of the variability and allows for the confidence needed in hypothesis testing.

In tests like the one discussed, we rely on the t-distribution to determine critical values. It's crucial when calculating test statistics, helping you figure out if you should accept or reject the null hypothesis. The smaller your sample, the wider the t-distribution spread will be, accommodating greater uncertainty.
Exploring the Two-Tailed Test
A two-tailed test checks for any significant difference in either direction. It’s applicable when the alternative hypothesis is that the parameter \( \mu_{d} \) is not equal to the null value (e.g., 0).

Here's how it works:
  • You're looking for deviations in both directions—higher or lower.
  • This means you split your significance level \( \alpha \) into two: \( \alpha/2 \) for each tail.
  • If the calculated test statistic falls into these extreme zones, you reject the null hypothesis.
This approach is great when you have no specific direction in mind and just want to see if there's a difference.
Understanding the Right-Tailed Test
The right-tailed test is straightforward: you're looking for an increase. In hypothesis testing, this occurs when your alternative hypothesis is \( \mu_{d} > 0 \).

Here’s the process:
  • You’re concerned with values greater than expected under the null hypothesis.
  • All of the significance level \( \alpha \) is concentrated in the right tail of the distribution.
  • If your test statistic is in that right tail region, you reject the null hypothesis.
This method is appropriate when you anticipate a rise or increase in the parameter being tested.
Understanding the Left-Tailed Test
A left-tailed test focuses on detecting decreases, as expressed by the alternative hypothesis \( \mu_{d} < 0 \). This is the opposite of the right-tailed test.

Follow these guidelines:
  • You're interested in outcomes lower than the null hypothesis predicts.
  • All the significance level \( \alpha \) is assigned to the left tail.
  • If your t-score lands in this leftward area, you reject the null hypothesis.
This type of test is utilized when you expect a decrease or drop in the variable of interest.

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Most popular questions from this chapter

An insurance company wants to know if the average speed at which men drive cars is greater than that of women drivers. The company took a random sample of 27 cars driven by men on a highway and found the mean speed to be 72 miles per hour with a standard deviation of \(2.2\) miles per hour. Another sample of 18 cars driven by women on the same highway gave a mean speed of 68 miles per hour with a standard deviation of \(2.5\) miles per hour. Assume that the speeds at which all men and all women drive cars on this highway are both normally distributed with the same population standard deviation. a. Construct a \(98 \%\) confidence interval for the difference between the mean speeds of cars driven by all men and all women on this highway. b. Test at a \(1 \%\) significance level whether the mean speed of cars driven by all men drivers on this highway is greater than that of cars driven by all women drivers.

Briefly explain the meaning of independent and dependent samples. Give one example of each.

According to a report in The New York Times, in the United States, accountants and auditors earn an average of \(\$ 70,130\) a year and loan officers carn \(\$ 67,960\) a year (Jessica Silver-Greenberg, The New York Times, April 22,2012 ). Suppose that these estimates are based on random samples of 1650 accountants and auditors and 1820 loan officers. Further assume that the sample standard deviations of the salaries of the two groups are \(\$ 14,400\) and \(\$ 13,600\), respectively, and the population standard deviations are equal for the two groups. a. Construct a \(98 \%\) confidence interval for the difference in the mean salaries of the two groupsaccountants and auditors, and loan officers. b. Using a \(1 \%\) significance level, can you conclude that the average salary of accountants and auditors is higher than that of loan officers?

The lottery commissioner's office in a state wanted to find if the percentages of men and women who play the lottery often are different. A sample of 500 men taken by the commissioner's office showed that 160 of them play the lottery often. Another sample of 300 women showed that 66 of them play the lottery often. a. What is the point estimate of the difference between the two population proportions? b. Construct a \(99 \%\) confidence interval for the difference between the proportions of all men and all women who play the lottery often. c. Testing at a \(1 \%\) significance level, can you conclude that the proportions of all men and all women who play the lottery often are different?

Construct a 99 ?o confidence interval for \(p_{1}-p_{2}\) for the following. $$ n_{1}=300, \quad \hat{p}_{1}=.55, \quad n_{2}=200, \quad \hat{p}_{2}=.62 $$

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