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91Ó°ÊÓ

You are working for a bank. The bank manager wants to know the mean waiting time for all customers who visit this bank. She has asked you to estimate this mean by taking a sample. Briefly explain how you will conduct this study. Collect data on the waiting times for 45 customers who visit a bank. Then estimate the population mean. Choose your own confidence level

Short Answer

Expert verified
Firstly, data for 45 random customers are collected. Then the sample mean, the estimate of the population mean, is calculated. After this, depending on the chosen confidence level, the confidence interval is computed which gives a range that the actual population mean is likely to fall into.

Step by step solution

01

Collect the Data

Firstly, the data for waiting times of 45 randomly chosen customers visiting the bank should be collected. Random selection helps to avoid selection bias, ensuring that the collected data is a good representation of the entire customer base.
02

Calculate the Sample Mean

Once all the data is collected, compute the mean waiting time by adding all the waiting times and dividing by the total number of observations (45). In mathematical term, if the waiting times are represented as \(X_1, X_2, ..., X_{45}\), the sample mean \(\mu\) is given by \(\mu = (X_1 + X_2 +...+ X_{45}) / 45\).
03

Choose Confidence level and Calculate Confidence Interval

After deciding upon a confidence level (let's say 95% for example), the confidence interval should be calculated next. This is a range within which the true population mean is likely to fall, based on the extracted sample data. The formula to calculate this is given by \( \mu \pm z * \(\frac{s}{\sqrt{n}}\) \), where \(\mu\) is the sample mean, \(z\) is the z-score corresponding to the chosen confidence level, \(s\) is the sample standard deviation, and \(n\) is the number of observations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean Calculation
Calculating the sample mean provides a snapshot of the average waiting time from the selected customers. Simple yet effective, this calculation starts by summing all individual waiting times and dividing by the number of customers sampled. For instance, if you have waiting times such as 5, 10, and 15 minutes, your sample mean calculation would involve:
  • Add: 5 + 10 + 15 = 30
  • Divide by Total Observations: 30/3 = 10
This results in a sample mean of 10 minutes. In statistics, the term used to denote each observation is typically \(X\), where \(X_1\), \(X_2\), ..., \(X_{45}\) represent individual waiting times for 45 customers. Your formula becomes \[ \bar{X} = \frac{(X_1 + X_2 +...+ X_{45})}{45} \] This sample mean endeavors to accurately reflect the average waiting time for the broader customer base.
Confidence Interval
A confidence interval provides a range that likely contains the true population mean. Once you have your sample mean, the next step is to create this interval, which helps you gauge the reliability of your sample mean.Choosing a confidence level, such as 95%, means that you are 95% sure the interval contains the population mean. This requires calculating the standard error, which combines the standard deviation and sample size.The formula to obtain the confidence interval is \[ \bar{X} \pm z \times \frac{s}{\sqrt{n}} \] where
  • \(\bar{X}\) is the sample mean
  • \(z\) is the z-score linked to the selected confidence level (e.g., 1.96 for 95%)
  • \(s\) is the sample standard deviation
  • \(n\) is the sample size, in this case, 45 customers
This interval reflects the reliability of your sample mean and offers a more comprehensive picture of the population mean, providing essential context for your manager's decision-making.
Random Selection
Random selection is key to ensuring your sample truly represents the general customer base. By selecting customers randomly, you remove biases that might skew the results, such as only choosing customers during certain times of day or those visiting specific branches. This process ensures that
  • Each customer has an equal chance of being selected
  • The sample data will better imitate the diversity of the entire customer pool
Imagine placing all customer names into a hat and drawing 45 names at random. This illustration mirrors the essence of random selection. This randomness is elemental in statistics, as it enhances the validity of the results, providing a more genuine reflection of the overall population.
Population Mean Estimation
Estimating the population mean is the final goal of conducting a sampling study. Using your calculated sample mean and confidence interval, you make an informed prediction about the average waiting time for the whole customer base. The underlying assumption here is that your sample is a microcosm of the entire population. Thus, data gathered from your sample allows you to estimate this broader "true" mean. Keep in mind:
  • Sample size affects accuracy. Larger samples usually provide more reliable estimates.
  • Randomness in selection boosts credibility and relevance of your estimates.
In this particular bank study, the estimate presents potential average customer waiting times. A precise estimate becomes a valuable tool in service improvement strategies and future decision-making processes.

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Most popular questions from this chapter

Refer to Exercise \(8.116\). Assume that a preliminary sample has shown that \(63 \%\) of the adults in this city favor legalized casino gambling. How large should the sample size be so that the \(95 \%\) confidence interval for the population proportion has a margin of error of \(.05 ?\)

The express check-out lanes at Wally's Supermarket are limited to customers purchasing 12 or fewer items. Cashiers at this supermarket have complained that many customers who use the express lanes have more than 12 items. A recently taken random sample of 200 customers entering express lanes at this supermarket found that 74 of them had more than 12 items. a. Construct a \(98 \%\) confidence interval for the percentage of all customers at this supermarket who enter express lanes with more than 12 items. b. Suppose the confidence interval obtained in part a is too wide. How can the width of this interval be reduced? Discuss all possible alternatives. Which alternative is the best?

A company randomly selected nine office employees and secretly monitored their computers for one month. The times (in hours) spent by these employees using their computers for non-job-related activities (playing games, personal communications, etc.) during this month are given below. \(\begin{array}{lllllllll}7 & 1 & 29 & 8 & 1 & 14 & 1 & 41 & 6\end{array}\) Assuming that such times for all employees are normally distributed, make a \(95 \%\) confidence interval for the corresponding population mean for all employees of this company.

For each of the following, find the area in the appropriate tail of the \(t\) distribution. a. \(t=2.467\) and \(d f=28\) b. \(t=-1.672\) and \(d f=58\) c. \(t=-2.670\) and \(n=55\) d. \(t=2.383\) and \(n=23\)

Tony's Pizza guarantees all pizza deliveries within 30 minutes of the placement of orders. An agency wants to estimate the proportion of all pizzas delivered within 30 minutes by Tony's. What is the most conservative estimate of the sample size that would limit the margin of error to within \(.02\) of the population proportion for a \(99 \%\) confidence interval?

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