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For each of the following, find the area in the appropriate tail of the \(t\) distribution. a. \(t=2.467\) and \(d f=28\) b. \(t=-1.672\) and \(d f=58\) c. \(t=-2.670\) and \(n=55\) d. \(t=2.383\) and \(n=23\)

Short Answer

Expert verified
The areas in the tail of the t-distribution for the given values can be obtained by examining the t-table or using a statistical calculator. The specific values are determined by considering the sign of the 't' value (which tail to examine) and the degrees of freedom.

Step by step solution

01

Understand t-distribution and tails

The t-distribution is a type of probability distribution that is symmetric and bell-shaped, like the standard normal distribution, but has heavier tails. A tail of a t-distribution refers to the end part of the distribution, left or right of the mean.
02

Identify the tail

For positive 't' values, we are dealing with the right tail of the distribution, as the value lies to the right of the mean. For negative 't' values, we are dealing with the left tail of the distribution, as the value lies to the left of the mean.
03

Consider degrees of freedom

Degrees of freedom (df or n) refer to the number of independent observations in a set of data. Generally, the larger the degrees of freedom, the closer the t-distribution is to the normal distribution.
04

Use t-table or statistical calculator

Most statistical textbooks have t-tables that provide t-values for various degrees of freedom and significance levels. Alternatively, a statistical calculator can also be used to directly compute the area.
05

Find the area under the curve

Locate the appropriate 'df' and 't' value in the t-table or insert these values in the statistical calculator. The result will be the area in the tail, which corresponds to the probability of getting a value greater than the given 't' value. Repeat this step for each set of values.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
Degrees of freedom (often abbreviated as "df") play a crucial role in the context of a t-distribution. They represent the number of independent values or quantities that can vary in a statistical calculation while keeping others constant. For example, if you have data from 29 people and are trying to estimate a parameter's value, you might remove some restrictions until you have 28 "free" observations. That's where the degrees of freedom would be 28. The larger the degrees of freedom, the closer the t-distribution approximates the standard normal distribution. This means with more samples or observations, our estimates get more precise. Larger samples give us more "freedom" and thus a t-distribution that looks more like the bell curve of the normal distribution.
Right Tail
When we talk about the right tail of a t-distribution, we are focusing on the area that lies to the right of a given t-value. This area represents the probability of getting a t-value as extreme or more extreme than the given value, assuming that the null hypothesis is true. In hypothesis testing, if you calculate a t-value and find it in the right tail, this means you are dealing with higher t-values. For instance, in a right-tailed test, researchers often use this area to assess how likely an observed effect would be if there were no actual effect. If this area is very small (often less than 0.05), they may reject the null hypothesis, suggesting a significant finding.
Left Tail
The left tail of a t-distribution refers to the area to the left of a given t-value. This area signifies the probability of obtaining a t-value as extreme or more extreme in the negative direction, when assuming the null hypothesis is true. In testing scenarios, a negative t-value leads us to the left tail, focusing on evidence against the null hypothesis in the opposite direction to that of the right tail. Like the right tail, the left tail area is also critical for determining statistical significance in one-tailed tests. A small left tail area could indicate a significant negative effect, prompting rejection of the null hypothesis. It's the counterpart to the right tail's focus on high t-values, but here geared toward significant negative deviations.
T-Table
The t-table, a helpful tool in statistics, lists critical t-values for different degrees of freedom and significance levels. Browsing the t-table allows you to find the corresponding t-value that matches a specific probability or area in the tail and a given degree of freedom. This table is essential for determining whether to accept or reject a null hypothesis. You may consult it during hypothesis testing to see if your calculated t-value falls in the critical region of the table. For example, with 28 degrees of freedom and a right tail test, you locate the row and column that correspond to your results to understand the probability. It's like a map—guiding you through determining the significance of your statistical results.

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Most popular questions from this chapter

Lazurus Steel Corporation produces iron rods that are supposed to be 36 inches long. The machine that makes these rods does not produce each rod exactly 36 inches long. The lengths of the rods vary slightly. It is known that when the machine is working properly, the mean length of the rods made on this machine is 36 inches. The standard deviation of the lengths of all rods produced on this machine is always equal to \(.10\) inch. The quality control department takes a sample of 20 such rods every week, calculates the mean length of these rods, and makes a \(99 \%\) confidence interval for the population mean. If either the upper limit of this confidence interval is greater than \(36.05\) inches or the lower limit of this confidence interval is less than \(35.95\) inches, the machine is stopped and adjusted. A recent sample of 20 rods produced a mean length of \(36.02\) inches. Based on this sample, will you conclude that the machine needs an adjustment? Assume that the lengths of all such rods have a normal distribution.

A consumer agency wants to estimate the proportion of all drivers who wear seat belts while driving. Assume that a preliminary study has shown that \(76 \%\) of drivers wear seat belts while driving. How large should the sample size be so that the \(99 \%\) confidence interval for the population proportion has a margin of error of \(.03\) ?

KidPix Entertainment is in the planning stages of producing a new computer- animated movie for national release, so they need to determine the production time (labor-hours necessary) to produce the movie. The mean production time for a random sample of 14 big-screen computer-animated movies is found to be 53,550 labor-hours. Suppose that the population standard deviation is known to be 7462 labor-hours and the distribution of production times is normal. a. Construct a \(98 \%\) confidence interval for the mean production time to produce a big-screen computer-animated movie. b. Explain why we need to make the confidence interval. Why is it not correct to say that the average production time needed to produce all big-screen computer-animated movies is 53,550 labor-hours?

It is said that happy and healthy workers are efficient and productive. A company that manufactures exercising machines wanted to know the percentage of large companies that provide on-site health club facilities. A sample of 240 such companies showed that 96 of them provide such facilities on site. a. What is the point estimate of the percentage of all such companies that provide such facilities on site? b. Construct a \(97 \%\) confidence interval for the percentage of all such companies that provide such facilities on site. What is the margin of error for this estimate?

A company randomly selected nine office employees and secretly monitored their computers for one month. The times (in hours) spent by these employees using their computers for non-job-related activities (playing games, personal communications, etc.) during this month are given below. \(\begin{array}{lllllllll}7 & 1 & 29 & 8 & 1 & 14 & 1 & 41 & 6\end{array}\) Assuming that such times for all employees are normally distributed, make a \(95 \%\) confidence interval for the corresponding population mean for all employees of this company.

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