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Given that \(A, B\), and \(C\) are three independent events, find their joint probability for the following a. \(P(A)=.49, \quad P(B)=.67\), and \(P(C)=.75\) b. \(P(A)=.71, \quad P(B)=.34\), and \(P(C)=.45\)

Short Answer

Expert verified
The joint probabilities for parts a and b are approximately .245175 and .10869, respectively.

Step by step solution

01

Calculate the joint probability for question a

Firstly, we need to calculate the joint probability for question a. The individual probabilities are \(P(A)=.49\), \(P(B)=.67\) and \(P(C)=.75\). Since these are independent events, the joint probability is found by calculating the product of the probabilities: \(P(A \cap B \cap C)=P(A)P(B)P(C) = .49 \times .67 \times .75 = .245175\).
02

Calculate the joint probability for question b

Secondly, let's calculate the joint probability for question b. This time, we have \(P(A)=.71\), \(P(B)=.34\) and \(P(C)=.45\). Therefore the joint probability is: \(P(A \cap B \cap C)=P(A)P(B)P(C) = .71 \times .34 \times .45 = .10869.\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
Understanding independent events is crucial in probability theory. Two or more events are considered independent if the occurrence of one event does not affect the occurrence of the other events. For example, flipping a fair coin twice results in two independent events. The result of the first flip doesn't change the possible outcomes of the second flip. This type of independence is vital when calculating joint probabilities in situations such as the given exercise.
When you determine that events are independent, it means the occurrence of each event is isolated. Thus, any event neither depends on nor affects the outcome of other events involved. Identifying independence simplifies the process of calculating joint probabilities, especially when dealing with multiple events.
Probability Calculation
The probability calculation is the process of determining the likelihood of different outcomes occurring in an experiment. In probability theory, each outcome of an event is assigned a probability, which is a number between 0 and 1 that indicates how likely it is to occur.
For the given exercise, individual probabilities were provided for the events A, B, and C. In real-world applications, probabilities can be determined through experiments, historical data, or logical reasoning.
There are a few key points to remember when calculating probabilities:
  • Probabilities close to 1 imply that an event is very likely to happen.
  • Probabilities close to 0 suggest that an event is unlikely to happen.
  • The sum of probabilities for all possible outcomes of an event equals 1.

These principles guide us in assessing individual possibilities and preparing us to handle more complex probability scenarios like joint probabilities.
Multiplication Rule
When dealing with independent events, the multiplication rule is a powerful tool. It allows us to calculate the probability of all events occurring together, known as the joint probability. The rule states that the joint probability of independent events is the product of their individual probabilities.
For our problem, if we have three independent events A, B, and C with probabilities \(P(A)\), \(P(B)\), and \(P(C)\), the joint probability \(P(A \cap B \cap C)\) is calculated as:

\[P(A \cap B \cap C) = P(A) \times P(B) \times P(C)\]

This rule simplifies complex probability calculations. The absence of dependence among the events turns complicated questions into simpler multiplication problems.
  • Always ensure events are independent before applying the multiplication rule. This rule does not hold for dependent events.
Probability Theory
Probability theory is a branch of mathematics that deals with the analysis of random phenomena. It helps us predict the likelihood of various outcomes and understand the underlying patterns in seemingly random events. In our exercise, we utilize probability theory to assess how different independent events combine to form a joint probability.
This theory provides the foundation for essential concepts such as random variables, distributions, and events. It plays a fundamental role in various fields such as finance, science, engineering, and social sciences.
Key elements of probability theory include:
  • Probabilities: Quantifying how likely it is for different events to occur.
  • Random Variables: Variables that take on different numerical outcomes depending on random phenomena.
  • Distributions: Mathematical functions that describe the likelihood of different outcomes for a random variable.

Being adept at probability theory equips you with the tools to navigate uncertainties effectively, making complex decisions more data-driven and less speculative.

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Most popular questions from this chapter

Two thousand randomly selected adults were asked if they are in favor of or against cloning. The following table gives the responses. $$\begin{array}{lccc} \hline & \text { In Favor } & \text { Against } & \text { No Opinion } \\ \hline \text { Male } & 395 & 405 & 100 \\ \text { Female } & 300 & 680 & 120 \\ \hline \end{array}$$ a. If one person is selected at random from these 2000 adults, find the probability that this person is i. in favor of cloning ii. against cloning iii. in favor of cloning given the person is a female iv. a male given the person has no opinion b. Are the events "male" and "in favor" mutually exclusive? What about the events "in favor" and "against?" Why or why not? c. Are the events "female" and "no opinion" independent? Why or why not?

Five percent of all items sold by a mail-order company are returned by customers for a refund. Find the probability that, of two items sold during a given hour by this company, a. both will be returned for a refund b. neither will be returned for a refund Draw a tree diagram for this problem.

Given that \(A, B\), and \(C\) are three independent events, find their joint probability for the following. a. \(P(A)=.20, \quad P(B)=.46\), and \(P(C)=.25\) b. \(P(A)=.44, \quad P(B)=.27\), and \(P(C)=.43\)

What is meant by the joint probability of two or more events? Give one example.

A consumer agency randomly selected 1700 flights for two major airlines, \(\mathrm{A}\) and \(\mathrm{B}\). The following table gives the two-way classification of these flights based on airline and arrival time. Note that "less than 30 minutes late" includes flights that arrived early or on time. $$\begin{array}{lccc} \hline & \begin{array}{c} \text { Less Than 30 } \\ \text { Minutes Late } \end{array} & \begin{array}{c} \text { 30 Minutes to } \\ \text { 1 Hour Late } \end{array} & \begin{array}{c} \text { More Than } \\ \text { 1 Hour Late } \end{array} \\ \hline \text { Airline A } & 429 & 390 & 92 \\ \text { Airline B } & 393 & 316 & 80 \\ \hline \end{array}$$ a. If one flight is selected at random from these 1700 flights, find the probability that this flight is \(\mathrm{i}\), more than 1 hour late ii. less than 30 minutes late iii. a flight on airline A given that it is 30 minutes to 1 hour late iv. more than 1 hour late given that it is a flight on airline \(\mathrm{B}\) b. Are the events "airline A" and "more than 1 hour late" mutually exclusive? What about the events "less than 30 minutes late" and "more than 1 hour late?" Why or why not? c. Are the events "airline \(\mathrm{B}\) " and " 30 minutes to 1 hour late" independent? Why or why not?

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