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Given that \(A, B\), and \(C\) are three independent events, find their joint probability for the following. a. \(P(A)=.20, \quad P(B)=.46\), and \(P(C)=.25\) b. \(P(A)=.44, \quad P(B)=.27\), and \(P(C)=.43\)

Short Answer

Expert verified
The joint probability for the first case: \(P(A \cap B \cap C)\) is the result of multiplying \(0.20 \cdot 0.46 \cdot 0.25\). And the joint probability for the second case: \(P(A \cap B \cap C)\) is the result of multiplying \(0.44 \cdot 0.27 \cdot 0.43\).

Step by step solution

01

Understand Independent Events

In probability, events are considered independent if the occurrence of one does not affect the probability of the other(s). Therefore, to calculate the joint probability of independent events, just multiply their individual probabilities together.
02

Calculating Joint Probability for A, B, and C in the first case

Given the probabilities: \(P(A)=.20\), \(P(B)=.46\), and \(P(C)=.25\). The joint probability is calculated as: \[P(A \cap B \cap C) = P(A) \cdot P(B) \cdot P(C) = 0.20 \cdot 0.46 \cdot 0.25\]. Calculate this multiplication.
03

Calculating Joint Probability for A, B, and C in the second case

Given the probabilities: \(P(A)=.44\), \(P(B)=.27\), and \(P(C)=.43\). Again, the joint probability is calculated as: \[P(A \cap B \cap C) = P(A) \cdot P(B) \cdot P(C) = 0.44 \cdot 0.27 \cdot 0.43\]. Calculate this multiplication.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Independent Events
In probability theory, independent events are crucial as they simplify how we assess outcomes. Two or more events are independent if the occurrence of one does not affect the probability of the others. For instance, tossing a coin and rolling a die are independent events because the result of one does not influence the outcome of the other.
To determine whether events are independent, consider these characteristics:
  • If event A and event B are independent, then the probability of both events occurring, denoted as \( P(A \cap B) \), is the product of their individual probabilities: \( P(A) \cdot P(B) \).
  • Independent events don't share any cause-and-effect relationship.
  • Knowing the outcome of one event provides no information about the other.
Understanding this concept allows us to easily calculate joint probabilities when dealing with multiple independent events.
Exploring the Probability Multiplication Rule
The probability multiplication rule is an essential concept when calculating the joint probability of multiple independent events. This rule states that if we have n independent events, the probability of all events occurring together (joint probability) is simply the product of their individual probabilities.
Using the multiplication rule, given three independent events A, B, and C, the joint probability can be calculated as:\[P(A \cap B \cap C) = P(A) \cdot P(B) \cdot P(C)\]This rule is particularly helpful because it allows mathematicians and statisticians to handle complex probability problems more efficiently.
  • Helps in situations where multiple independent events occur simultaneously.
  • Simplifies calculations by only requiring multiplication of probabilities.
  • Useful in fields like statistics, machine learning, and risk assessment.
By applying this rule, solving the given exercise becomes straightforward as it involves simple multiplication of given probabilities.
Diving into Probability Theory
Probability theory forms the backbone of how we understand and predict various phenomena using mathematical principles. At its core, probability theory provides a framework for quantifying the uncertainty of events.
When tackling probability problems, it's useful to understand several fundamental principles:
  • Sample Space: The set of all possible outcomes in a probability experiment.
  • Probability of an Event: Quantified as a number between 0 and 1, representing the likelihood of an event occurring.
  • Joint Probability: Involves the likelihood of two or more events happening at once.
Probability theory is used in diverse areas ranging from game theory to financial models. It equips us with the tools to make informed predictions and decisions based on data.
These principles not only apply to theoretical scenarios but are practical in everyday problems. Understanding probability helps in critical thinking, statistical analysis, and formulating strategic plans.

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Most popular questions from this chapter

According to a survey of 2000 home owners, 800 of them own homes with three bedrooms, and 600 of them own homes with four bedrooms. If one home owner is selected at random from these 2000 home owners, find the probability that this home owner owns a house that has three or four bedrooms. Explain why this probability is not equal to \(1.0 .\)

Powerball is a game of chance that has generated intense interest because of its large jackpots. To play this game, a player selects five different numbers from 1 through 59 , and then picks a Powerball number from 1 through 39 . The lottery organization randomly draws 5 different white balls from 59 balls numbered 1 through 59 , and then randomly picks a Powerball number from 1 through \(39 .\) Note that it is possible for the Powerball number to be the same as one of the first five numbers. a. If the player's first five numbers match the numbers on the five white balls drawn by the lottery organization and the player's Powerball number matches the Powerball number drawn by the lottery organization, the player wins the jackpot. Find the probability that a player who buys one ticket will win the jackpot. (Note that the order in which the five white balls are drawn is unimportant.) b. If the player's first five numbers match the numbers on the five white balls drawn by the lottery organization, the player wins about \(\$ 200,000\). Find the probability that a player who buys one ticket will win this prize.

Terry \& Sons makes bearings for autos. The production system involves two independent processing machines so that each bearing passes through these two processes. The probability that the first processing machine is not working properly at any time is \(.08\), and the probability that the second machine is not working properly at any time is \(.06\). Find the probability that both machines will not be working properly at any given time.

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In a sample survey, 1800 senior citizens were asked whether or not they have ever been victimized by a dishonest telemarketer. The following table gives the responses by age group. $$\begin{array}{l|llcc} & & & \begin{array}{c} \text { Have Been } \\ \text { Victimized } \end{array} & \begin{array}{c} \text { Have Never } \\ \text { Been Victimized } \end{array} \\ \hline & 60-69 & \text { (A) } & 106 & 698 \\ \text { Age } & 70-79 & \text { (B) } & 145 & 447 \\ & 80 \text { or over (C) } & 61 & 343 \\ \hline \end{array}$$ Suppose one person is randomly selected from these senior citizens. Find the following probabilities a. \(P(\) have been victimized or \(\mathrm{B}\) ) b. \(P(\) have never been victimized or \(\mathrm{C}\) )

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