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91Ó°ÊÓ

In a sample survey, 1800 senior citizens were asked whether or not they have ever been victimized by a dishonest telemarketer. The following table gives the responses by age group. $$\begin{array}{l|llcc} & & & \begin{array}{c} \text { Have Been } \\ \text { Victimized } \end{array} & \begin{array}{c} \text { Have Never } \\ \text { Been Victimized } \end{array} \\ \hline & 60-69 & \text { (A) } & 106 & 698 \\ \text { Age } & 70-79 & \text { (B) } & 145 & 447 \\ & 80 \text { or over (C) } & 61 & 343 \\ \hline \end{array}$$ Suppose one person is randomly selected from these senior citizens. Find the following probabilities a. \(P(\) have been victimized or \(\mathrm{B}\) ) b. \(P(\) have never been victimized or \(\mathrm{C}\) )

Short Answer

Expert verified
The probabilities are as follows:\na. \(P(\) have been victimized or \(\mathrm{B}\) ) = \(759 / 1800\).\nb. \(P(\) have never been victimized or \(\mathrm{C}\) ) = \(1549 / 1800\).

Step by step solution

01

Organize and Understand the Data

First, organize the data into a more understandable format. The total number of surveyed senior citizens is 1800. For age groups A (60-69), B (70-79), and C (80 or over), the counts of those who have and have not been victimized by telemarketers are given respectively.
02

Compute Total Probabilities

Calculate the total numbers for each category. Total number of victimized people across all age groups is \(106+145+61 = 312\). Total number of people in group B is \(145 + 447 = 592\). The total number of people who have never been victimized is \(698 + 447 + 343 = 1488\). Total number of people in group C is \(61 + 343 = 404\).
03

Calculation for Part a

To find \(P(\) have been victimized or \(\mathrm{B}\) ), sum the total number of people who have been victimized and the total number of people in group B, then subtract the number of people in group B who have been victimize (to avoid double counting). So, \(P(\) have been victimized or \(\mathrm{B}\) ) = \((312 + 592 - 145) / 1800 = 759 / 1800\).
04

Calculation for Part b

To find \(P(\) have never been victimized or \(\mathrm{C}\) ), sum the total number of people who have never been victimized and the total number of people in group C, then subtract the number of people in group C who have never been victimize (to avoid double counting). So, \(P(\) have never been victimized or \(\mathrm{C}\) ) = \((1488 + 404 - 343) / 1800 = 1549 / 1800\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability is a fundamental concept in statistics and probability theory, focusing on finding the probability of an event given that another event has already occurred. In simpler words, it's about narrowing down probabilities based on known information.
For example, in our exercise, you have to determine probabilities involving being victimized or belonging to a certain age group. The probability of being victimized or being in age group B is an example where one must consider overlapping events, also known as non-mutually exclusive events.
  • To calculate this type of probability, sum the probabilities of individual events.
  • Then, subtract the probability of both events occurring at the same time, to avoid counting it twice.
This method shines when dealing with complex, dependent events, making it a trusted tool in scenarios like sample surveys and contingency tables.
Sample Survey
A sample survey is a research method used to gather information from a part of a population, aiming to make inferences about the entire population. In this case, our sample consists of senior citizens. By sampling only 1800 people from a potentially larger population, this survey captures a snapshot of how many have been victimized by telemarketers across different age groups. The significance lies in the survey design:
  • It ensures a representative sample, allowing results to reflect the broader population.
  • It provides data useful for estimating probabilities and detecting trends.
Sample surveys are valuable for collecting qualitative and quantitative information. They are efficient and insightful for studies requiring significant data collection over broad demographics.
Age Groups
Age groups are distinct categories within a population, based on age ranges. They help stratify data for detailed analysis.
In our exercise, age groups are divided into three: 60-69, 70-79, and 80 or over. These divisions are critical:
  • They provide insight into different behavioral or statistical trends among various age demographics.
  • Help identify variations in how often individuals within these groups fall victim to telemarketers.
Analyzing data by distinct age groups allows researchers to observe age-specific patterns that might remain hidden in aggregated data, enriching the study outcome by providing more granulated context.
Contingency Table
A contingency table is a statistical tool used to showcase the frequency distribution of variables. It organizes the given data, making analysis more straightforward. In this exercise, the contingency table shows responses regarding victimization across different age groups.
  • Rows represent different age groups.
  • Columns represent whether individuals have been victimized or not.
This tool not only simplifies data visualization but is instrumental in calculating joint probabilities like the ones we dealt with in the exercise. It aids in understanding relationships between categorical variables, making it a staple in data analysis and probability estimation.

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Most popular questions from this chapter

A telephone poll conducted of 1000 adult Americans for the Washington Post in March 2009 asked about current events in the United States. Suppose that of the 1000 respondents, 629 stated that they were cutting back on their daily spending. Suppose that 322 of the 629 people who stated that they were cutting back on their daily spending said that they were cutting back "somewhat" and 97 stated that they were cutting back "somewhat" and delaying the purchase of a new car by at least 6 months. If one of the 629 people who are cutting back on their spending is selected at random, what is the probability that he/she is delaying the purchase of a new car by at least 6 months given that he/she is cutting back on spending "somewhat?"

A car rental agency currently has 44 cars available, 28 of which have a GPS navigation system. One of the 44 cars is selected at random. Find the probability that this car a. has a GPS navigation system b. does not have a GPS navigation system

Find \(P(A\) or \(B\) ) for the following. a. \(P(A)=.58, \quad P(B)=.66\), and \(P(A\) and \(B)=.57\) b. \(P(A)=.72, \quad P(B)=.42\), and \(P(A\) and \(B)=.39\)

Consider the following addition rule to find the probability of the union of two events \(A\) and \(B\) : $$P(A \text { or } B)=P(A)+P(B)-P(A \text { and } B)$$ When and why is the term \(P(A\) and \(B)\) subtracted from the sum of \(P(A)\) and \(P(B)\) ? Give one example where you might use this formula.

The probability that a randomly selected college student attended at least one major league baseball game last year is .12. What is the complementary event? What is the probability of this complementary event?

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