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Given that \(A\) and \(B\) are two mutually exclusive events, find \(P(A\) or \(B\) ) for the following. a. \(P(A)=.25\) and \(P(B)=.27\) b. \(P(A)=.58\) and \(P(B)=.09\)

Short Answer

Expert verified
a. The probability of either event A or B occurring is .52, b. The probability of either event A or B occurring is .67

Step by step solution

01

Understand the concept of mutually exclusive events

Mutually exclusive events are events that cannot occur at the same time. In other words, the occurrence of one event excludes the occurrence of the other. In this scenario, events A and B are mutually exclusive.
02

Use the probability rule for mutually exclusive events for part A

If two events are mutually exclusive, the probability of either event A or B occurring is the sum of their individual probabilities. Here, \(P(A)=.25\) and \(P(B)=.27\). Hence, for either A or B happening, \(P(A \text{ or } B)=P(A)+P(B)=.25+.27=.52\)
03

Repeat the use of rule for part B

On similar lines, for the case where \(P(A)= .58\) and \(P(B)= .09\), the probability of either A or B occurring is \(P(A \text{ or } B)=P(A)+P(B)=.58 + .09 = .67\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Rule
Probability rules help us determine the chances of an event happening. For mutually exclusive events, there is a special rule to find the probability of one event or another happening. If events A and B are mutually exclusive, meaning they cannot happen at the same time, the probability that either A or B will happen is the sum of their individual probabilities. This is expressed mathematically as:
  • \(P(A \text{ or } B) = P(A) + P(B)\)
This rule simplifies the process of calculation because we don't have to consider the possibility of both events happening together. In our exercise, we applied this rule to different sets of probabilities for events A and B. It’s important to remember, this rule only applies when the events in question are mutually exclusive.
Event A or B
When tackling problems involving probabilities, understanding what it means for event A or B to occur is crucial. "Event A or B" refers to either one, or potentially both (if not mutually exclusive), of the events happening. However, with mutually exclusive events, you only need to consider one event happening at a time.
For instance, in the initial exercise, we are given two scenarios where events A and B have certain probabilities. Since they are mutually exclusive, when event A happens, event B cannot, and vice versa. When asked to find \(P(A \text{ or } B)\), the question essentially is about finding the collective probability of either one happening, but not both. It's this clear understanding that makes calculating their probabilities straightforward.
Individual Probabilities
The concept of individual probabilities deals with finding the chance of a single event occurring, separate from others. When we know the probability of events A and B individually, we can use this information to find the probability of compound events.
  • In the exercise, \(P(A)=0.25\) and \(P(B)=0.27\) for one case, and \(P(A)=0.58\) and \(P(B)=0.09\) for another.
These probabilities are the foundational elements needed when applying the rule for mutually exclusive events. Understanding each event’s individual probability is essential before moving on to combine them using probability rules. This is a key step in statistics, as it transforms raw probability measures into actionable insights for broader decision-making.
Introductory Statistics
Statistics is all about making sense of data and uncertainty. In introductory statistics, students begin exploring the basics of probability, which is a core component of the field.
Understanding the probability of events, especially concepts like mutually exclusive events, sets the groundwork for deeper statistical analysis.
  • Through exercises like the one discussed here, students learn fundamental rules of probability, such as how to handle scenarios where events cannot happen simultaneously.
  • Grasping these basic concepts aids in building the critical thinking skills necessary to analyze and interpret data in various real-world contexts.
Being adept at these foundational ideas allows learners to progress into more complex statistical methodologies with confidence.

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Most popular questions from this chapter

A random sample of 400 college students was asked if college athletes should be paid. The following table gives a two-way classification of the responses. $$\begin{array}{lcc} \hline & \text { Should Be Paid } & \text { Should Not Be Paid } \\ \hline \text { Student athlete } & 90 & 10 \\ \text { Student nonathlete } & 210 & 90 \end{array}$$ a. If one student is randomly selected from these 400 students, find the probability that this student i. is in favor of paying college athletes ii. favors paying college athletes given that the student selected is a nonathlete iii. is an athlete and favors paying student athletes iv. is a nonathlete or is against paying student athletes b. Are the events "student athlete" and "should be paid" independent? Are they mutually exclusive? Explain why or why not.

Briefly explain the difference between the marginal and conditional probabilities of events. Give one example of each.

Briefly explain the three approaches to probability. Give one example of each approach.

A gambler has given you two jars and 20 marbles. Of these 20 marbles, 10 are red and 10 are green You must put all 20 marbles in these two jars in such a way that each jar must have at least one marble in it. Then a friend of yours, who is blindfolded, will select one of the two jars at random and then will randomly select a marble from this jar. If the selected marble is red, you and your friend win \(\$ 100\) a. If you put 5 red marbles and 5 green marbles in each jar, what is the probability that your friend selects a red marble? b. If you put 2 red marbles and 2 green marbles in one jar and the remaining marbles in the other jar, what is the probability that your friend selects a red marble? c. How should these 20 marbles be distributed among the two jars in order to give your friend the highest possible probability of selecting a red marble?

Many states have a lottery game, usually called a Pick-4, in which you pick a four-digit number such as 7359 . During the lottery drawing, there are four bins, each containing balls numbered 0 through 9\. One ball is drawn from each bin to form the four-digit winning number. a. You purchase one ticket with one four-digit number. What is the probability that you will win this lottery game? b. There are many variations of this game. The primary variation allows you to win if the four digits in your number are selected in any order as long as they are the same four digits as obtained by the lottery agency. For example, if you pick four digits making the number 1265, then you will win if \(1265,2615,5216,6521\), and so forth, are drawn. The variations of the lottery game depend on how many unique digits are in your number. Consider the following four different versions of this game. i. All four digits are unique (e.g., 1234 ) ii. Exactly one of the digits appears twice (e.g., 1223 or 9095 ) iii. Two digits each appear twice (e.g., 2121 or 5588 ) iv. One digit appears three times (e.g., 3335 or 2722 ) Find the probability that you will win this lottery in each of these four situations.

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