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What is the shape of the sampling distribution of \(\hat{p}_{1}-\hat{p}_{2}\) for two large samples? What are the mean and standard deviation of this sampling distribution?

Short Answer

Expert verified
The shape of the sampling distribution of \(\hat{p}_{1}-\hat{p}_{2}\) for two large samples is a normal distribution. The mean of the sampling distribution is \(p_{1} - p_{2}\), which is the difference between the population proportions. The standard deviation can be obtained via \(\sqrt{\frac{{p_{1}(1-p_{1})}}{{n_{1}}}+ \frac{{p_{2}(1-p_{2})}}{{n_{2}}}}\).

Step by step solution

01

Shape of the sampling distribution

Under the condition that the sample sizes are large, the Central Limit Theorem assures that the distribution of \(\hat{p}_{1}-\hat{p}_{2}\) will be a normal distribution.
02

Calculation of the Mean

The mean (expected value) of the sampling distribution \(\hat{p}_{1}-\hat{p}_{2}\) is equal to the difference between the population proportions, \(p_{1} - p_{2}\).
03

Calculation of the Standard Deviation

The standard deviation of the sampling distribution \(\hat{p}_{1}-\hat{p}_{2}\) can be calculated using the formula: \(\sqrt{\frac{{p_{1}(1-p_{1})}}{{n_{1}}}+ \frac{{p_{2}(1-p_{2})}}{{n_{2}}}}\), where \(p_{1}\) and \(p_{2}\) are the population proportions, and \(n_{1}\) and \(n_{2}\) are the sizes of the samples respectively.

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Most popular questions from this chapter

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