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The following information was obtained from two independent samples selected from two normally distributed populations with unknown but equal standard deviations. $$ \begin{array}{llllllllllllll} \text { Sample 1: } & 47.7 & 46.9 & 51.9 & 34.1 & 65.8 & 61.5 & 50.2 & 40.8 & 53.1 & 46.1 & 47.9 & 45.7 & 49.0 \\ \text { Sample 2: } & 50.0 & 47.4 & 32.7 & 48.8 & 54.0 & 46.3 & 42.5 & 40.8 & 39.0 & 68.2 & 48.5 & 41.8 & \end{array} $$ a. Let \(\mu_{1}\) be the mean of population 1 and \(\mu_{2}\) be the mean of population \(2 .\) What is the point estimate of \(\mu_{1}-\mu_{2} ?\) b. Construct a \(98 \%\) confidence interval for \(\mu_{1}-\mu_{2}\). c. Test at the \(1 \%\) significance level if \(\mu_{1}\) is greater than \(\mu_{2}\).

Short Answer

Expert verified
a. The point estimate of \(\mu_{1} - \mu_{2}\) is the difference between the sample means. b. The 98% confidence interval for \(\mu_{1} - \mu_{2}\) would be calculated using sample means, sample sizes, and sample variances. c. Based on hypothesis testing, decide whether \(\mu_{1}\) is greater than \(\mu_{2}\) at the 1% significance level.

Step by step solution

01

Calculate Sample Means

Calculate the sample means of the two samples. This can be done by adding up all the sample observations and dividing by the sample size. Let's denote them as \(\bar{X}_{1}\) for Sample 1 and \(\bar{X}_{2}\) for Sample 2.
02

Calculate the Point Estimate

The point estimate of \(\mu_{1} - \(\mu_{2}\) is simply the difference of the sample means, \(\bar{X}_{1} - \(\bar{X}_{2}\). Calculate this value.
03

Calculate Sample Variances

Calculate the sample variances of the two samples. This can be done by subtracting the sample mean from each individual observation, squaring the result, adding these squared results, and dividing by the sample size minus one. Denote them as \(s_{1}^{2}\) and \(s_{2}^{2}\) for Samples 1 and 2, respectively.
04

Calculate Confidence Interval

Construct a 98% confidence interval for \(\mu_{1}-\mu_{2}\) using the formula \(\bar{X}_{1} - \bar{X}_{2} \pm Z_{\frac{\alpha}{2}} \sqrt{\frac{s_{1}^{2}}{n_{1}} + \frac{s_{2}^{2}}{n_{2}}}\), where \(Z_{\frac{\alpha}{2}}\) is the z-score for the desired confidence level, and \(n_{1}\) and \(n_{2}\) are the sample sizes of Samples 1 and 2.
05

Hypothesis Testing

Form the null and alternative hypotheses. The null hypothesis (H0) is \(\mu_{1}\) - \(\mu_{2}=0\), and the alternative hypothesis (H1) is \(\mu_{1}\) - \(\mu_{2} > 0\). If the calculated t-score is greater than the critical value at the 1% significance level, then we reject the null hypothesis and conclude that \(\mu_{1}\) is greater than \(\mu_{2}\). Calculate the t-score using the formula \((\bar{X}_{1} - \bar{X}_{2})/ \sqrt{\frac{s_{1}^{2}}{n_{1}} + \frac{s_{2}^{2}}{n_{2}}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

confidence interval
Whenever we're working with samples and trying to make inferences about a population, the confidence interval is an incredibly useful concept. It gives us a range of values which is likely to include the true difference between two population means. In our example, it helps us understand the possible range that \( \mu_{1} - \mu_{2} \) might lie within.
To construct a confidence interval, we calculate it around the point estimate of the difference in population means, using the formula:
  • \[ \bar{X}_{1} - \bar{X}_{2} \pm Z_{\frac{\alpha}{2}} \sqrt{\frac{s_{1}^{2}}{n_{1}} + \frac{s_{2}^{2}}{n_{2}}} \]
This formula includes the z-score, which is tied to the confidence level we are working with. A 98% confidence level translates into a z-score that determines the margin of error around our point estimate.
A higher confidence level implies a wider confidence interval, reflecting greater uncertainty about \( \mu_{1} - \mu_{2} \).Understanding confidence intervals is key for interpreting the range in which the true difference of population means might be found, with a certain degree of certainty.
point estimate
A point estimate is a single value that serves as our best guess for a population parameter. In the context of our problem, it's the estimate of the difference between the means of two populations, denoted as \( \mu_{1} - \mu_{2} \).
The formula to find this point estimate involves straightforward arithmetic, where you simply subtract the sample mean of the second sample from the sample mean of the first sample:
  • \[ \bar{X}_{1} - \bar{X}_{2} \]
This value gives us an insight into how much one population might differ from another, based on the sample data. It's at the heart of many statistical analyses because it provides a direct, interpretable measure of effect size.
In practice, the point estimate acts as the foundation for further exploration, like hypothesis testing or constructing confidence intervals. It's crucial for initial conclusions about population differences.
sample mean
The sample mean is a fundamental statistical measure that embodies the average of all data points within a sample. It's denoted as \( \bar{X} \), representing a central tendency for the dataset. To compute the sample mean, you sum all the observations and divide by the total number of observations.
In our case, two separate sample means are calculated for Samples 1 and 2:
  • \[ \bar{X}_{1} \text{ for Sample 1 and } \bar{X}_{2} \text{ for Sample 2} \]
The sample mean gives us a glimpse of the population mean, \( \mu \),even though we know it won't match it exactly, unless by coincidence. It simplifies the data into a single number and is a crucial input for calculating the point estimate of the population mean differences.
Overall, understanding the sample mean prepares us for higher-level statistical endeavors, like calculating variances or hypothesis testing.
sample variance
Sample variance is a metric of how spread out the data points in a sample are around the mean. It's a way of quantifying variability or diversity within the dataset. The sample variance can be calculated as follows:
  • First, subtract the sample mean from each observation in the sample.
  • Square these differences to ensure all values are positive and exaggerate larger deviations.
  • Sum all these squared values.
  • Divide this sum by the number of observations minus one, which corrects the bias in the estimate of a population variance from a sample.\[ s^2 = \frac{\sum (X_i - \bar{X})^2}{n-1} \]
You will have two separate variances, \( s_{1}^2 \text{ and } s_{2}^2 \), for Samples 1 and 2. Understanding sample variance is vital because it feeds into most statistical analyses, such as calculating the standard error used in confidence intervals.
At its core, variance reflects how much individuals within a sample differ from each other and their mean, offering a tangible measure of uncertainty or variation in the data.

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Most popular questions from this chapter

Find the following confidence intervals for \(\mu_{d}\), assuming that the populations of paired differences are normally distributed. a. \(n=11, \quad d=25.4, \quad s_{d}=13.5\), confidence level \(=99 \%\) b. \(n=23, \quad \bar{d}=13.2, \quad s_{d}=4.8, \quad\) confidence level \(=95 \%\) c. \(n=18, \quad \bar{d}=34.6, \quad s_{d}=11.7, \quad\) confidence level \(=90 \%\)

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