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Use the following information to answer the next seven exercises: The U.S. Census Bureau conducts a study to determine the time needed to complete the short form. The Bureau surveys 200 people. The sample mean is 8.2 minutes. There is a known standard deviation of 2.2 minutes. The population distribution is assumed to be normal. Construct a 90% confidence interval for the population mean time to complete the forms. State the confidence interval, sketch the graph, and calculate the error bound.

Short Answer

Expert verified
The 90% confidence interval for the population mean is (7.9444, 8.4556). The error bound is 0.2556.

Step by step solution

01

Identify Known Values

Begin by identifying the known values from the problem. We have:\[ \bar{x} = 8.2 \text{ minutes (sample mean)} \]\[ \sigma = 2.2 \text{ minutes (population standard deviation)} \]\[ n = 200 \text{ (sample size)} \]We need to construct a 90% confidence interval for the population mean time.
02

Determine the Z-Score

Since the population standard deviation is known and the sample size is large (n > 30), we use the Z-distribution. For a 90% confidence interval, the Z-score for the critical value is 1.645. This value can be found from a Z-table corresponding to the cumulative probability of 0.95.
03

Calculate the Standard Error

Calculate the standard error (SE) using \[ SE = \frac{\sigma}{\sqrt{n}} \]Substitute the known values:\[ SE = \frac{2.2}{\sqrt{200}} \approx 0.1555 \]
04

Calculate the Error Bound (E)

Calculate the margin of error (E) using the formula:\[ E = Z \times SE \]Substitute the values:\[ E = 1.645 \times 0.1555 \approx 0.2556 \]
05

Construct the Confidence Interval

Use the sample mean and the error bound to calculate the confidence interval.\[ (\bar{x} - E, \bar{x} + E) \]Plug in the values:\[ (8.2 - 0.2556, 8.2 + 0.2556) \]\[ (7.9444, 8.4556) \]
06

Sketch the Graph

Draw a normal distribution curve centered at the mean \(\bar{x} = 8.2\). Mark the bounds of the confidence interval at 7.9444 and 8.4556 on the horizontal axis. Shade the region between these bounds to represent the 90% confidence interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Mean
The population mean, often denoted by the symbol \( \mu \), is a measure of the average value of a given characteristic in an entire population. In statistical terms, it represents the central point or the "average" around which data values fluctuate.

In many cases, especially when dealing with large populations, it is impractical to calculate the population mean due to cost and time constraints. Therefore, researchers use a sample mean as an estimate. By extracting a smaller, manageable sample from the population, they calculate the average of this sample (denoted by \( \bar{x} \)) to make inferences about the population mean.

For instance, the U.S. Census Bureau surveyed 200 people to estimate the average time it takes to complete a particular form. The sample mean was found to be 8.2 minutes, which is used to estimate the population mean. Even when using this sample mean, our ultimate aim is to get an accurate "middle point" that approximates the population mean.
Z-Distribution
The Z-distribution is a normal distribution used in statistics to understand how individual data points relate to the overall data set. It helps in determining how many standard deviations a data point is from the mean. A key feature of the Z-distribution is that it is symmetrical around the mean and follows a bell-shaped curve.

When the population standard deviation is known and we want to estimate a population mean from a large sample size, we apply the Z-distribution. This was the case for the surveyed time needed to complete a form. Since the sample size was 200 (a large number) and the population standard deviation was given, we leveraged the Z-distribution for calculations.

For a 90% confidence level, the critical Z-score is 1.645. This value can be obtained from a Z-table, showing that at this critical point, the cumulative probability is 0.95 (since you include the 5% in the tails for two tails combined in a 90% interval). The use of the Z-distribution allows researchers to construct confidence intervals around the sample mean that are highly likely to capture the population mean.
Margin of Error
The margin of error is a crucial concept in statistics that reflects the amount of random sampling error in the result of a survey. It shows how "off" the estimated sample mean might be from the true population mean.

In simple terms, the margin of error is calculated by multiplying the Z-score by the standard error (SE). It represents the range within which we expect the true population mean to lie, given our sample mean.

From the U.S. Census Bureau exercise, the margin of error was calculated to be approximately 0.2556. This value indicates that the actual average time to complete the form is likely not more than 0.2556 minutes above or below the sample mean of 8.2 minutes.

Including the margin of error provides a buffer around the sample mean, giving us a "confidence interval" where we suspect the actual population mean resides.
Standard Error
The standard error (SE) is a concept that quantifies the variability or precision of a sample statistic鈥攊n this case, the sample mean. It is important as it influences how wide the confidence interval around a sample mean will be.

While the standard deviation measures variation within a single set of data, the standard error is more focused on how much variability we can expect between the sample mean and the population mean.

To calculate the standard error, you use the formula \( SE = \frac{\sigma}{\sqrt{n}} \), where \( \sigma \) is the population standard deviation and \( n \) is the sample size. In the example provided by the U.S. Census Bureau, the standard error was calculated as approximately 0.1555.

This relatively small standard error indicates that the sample mean is a precise estimate of the population mean. As the sample size increases or the variability among the population decreases, the standard error usually becomes smaller, leading to more precise estimates.

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Most popular questions from this chapter

Use the following information to answer the next five exercises: A poll of \(1,200\) voters asked what the most significant issue was in the upcoming election. Sixty-five percent answered the economy. We are interested in the population proportion of voters who feel the economy is the most important. What would happen to the confidence interval if the level of confidence were 95\(\% ?\)

A national survey of 1,000 adults was conducted on May 13,2013 by Rasmussen Reports. It concluded with \(95 \%\) confidence that \(49 \%\) to \(55 \%\) of Americans believe that big-time college sports programs corrupt the process of higher education. a. Find the point estimate and the error bound for this confidence interval. b. Can we (with \(95 \%\) confidence) conclude that more than half of all American adults believe this? c. Use the point estimate from part a and \(n=1,000\) to calculate a \(75 \%\) confidence interval for the proportion of American adults that believe that major college sports programs corrupt higher education. d. Can we (with \(75 \%\) confidence) conclude that at least half of all American adults believe this?

Use the following information to answer the next six exercises: One hundred eight Americans were surveyed to determine the number of hours they spend watching television each month. It was revealed that they watched an average of 151 hours each month with a standard deviation of 32 hours. Assume that the underlying population distribution is normal. Define the random variable \(\overline{X}\) in words.

Construct a 95\(\%\) Confidence Interval for the true mean age of winter Foothill College students by working out then answering the next seven exercises. Using the same mean, standard deviation, and sample size, how would the error bound change if the confidence level were reduced to 90%? Why?

In a recent Zogby International Poll, nine of 48 respondents rated the likelihood of a terrorist attack in their community as likely or very likely. Use the plus four鈥 method to create a 97% confidence interval for the proportion of American adults who believe that a terrorist attack in their community is likely or very likely. Explain what this confidence interval means in the context of the problem.

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