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Use the following information to answer the next six exercises: The Higher Education Research Institute at UCLA collected data from 203,967 incoming first-time, full-time freshmen from 270 four-year colleges and universities in the U.S. 71.3% of those students replied that, yes, they believe that same-sex couples should have the right to legal marital status. Suppose that you randomly select freshman from the study until you find one who replies 鈥測es.鈥 You are interested in the number of freshmen you must ask. Construct the probability distribution function (PDF). Stop at \(x = 6\). $$\begin{array}{|c|c|}\hline x & {P(x)} \\ \hline 1 & {} \\ \hline 2 & {} \\\ \hline 3 & {} \\ \hline 4 & {} \\ \hline 5 & {} \\ \hline x & {P(x)} \\\ \hline 6 & {} \\ \hline\end{array}$$

Short Answer

Expert verified
The complete PDF table is: \( P(1) = 0.713, P(2) = 0.204, P(3) = 0.0586, P(4) = 0.0168, P(5) = 0.0048, P(6) = 0.0014 \).

Step by step solution

01

Identify the Probability of Success

In the context of this problem, a "success" is when a freshman replies "yes" to the belief that same-sex couples should have the right to legal marital status. The probability of this happening is given as 0.713.
02

Define the Geometric Distribution

The situation describes a geometric distribution, where the probability of success on each trial is constant at 0.713, and we are interested in the number of trials until the first success occurs.
03

Calculate Probability for X = 1

The probability that the first student you ask agrees (X=1) is equal to the probability of success, since the first trial is a success: \[ P(X = 1) = 0.713 \]
04

Calculate Probability for X = 2

For X=2, the first freshman must say "no" (failure) and the second must say "yes" (success). Use the formula for geometric distribution: \[ P(X = 2) = (1 - 0.713) imes 0.713 = 0.287 imes 0.713 = 0.204 \]
05

Calculate Probability for X = 3

For X=3, the first two freshmen must say "no" while the third says "yes": \[ P(X = 3) = (1 - 0.713)^2 imes 0.713 = 0.287^2 imes 0.713 = 0.0586 \]
06

Calculate Probability for X = 4

For X=4, the first three freshmen must say "no" while the fourth says "yes": \[ P(X = 4) = (1 - 0.713)^3 imes 0.713 = 0.287^3 imes 0.713 = 0.0168 \]
07

Calculate Probability for X = 5

For X=5, the first four freshmen must say "no" while the fifth says "yes": \[ P(X = 5) = (1 - 0.713)^4 imes 0.713 = 0.287^4 imes 0.713 = 0.0048 \]
08

Calculate Probability for X = 6

For X=6, the first five freshmen must say "no" while the sixth says "yes": \[ P(X = 6) = (1 - 0.713)^5 imes 0.713 = 0.287^5 imes 0.713 = 0.0014 \]
09

Create the Probability Distribution Table

Now that we have calculated the probabilities for each value of X from 1 to 6, we can complete the distribution table: \[ \begin{array}{|c|c|}\hlinex & P(x) \\hline1 & 0.713 \\hline2 & 0.204 \\hline3 & 0.0586 \\hline4 & 0.0168 \\hline5 & 0.0048 \\hline6 & 0.0014 \\hline\end{array} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Distribution Function
The probability distribution function (PDF) for a discrete random variable provides the probabilities of the variable assuming each possible value. In our exercise, the PDF describes the distribution of probabilities associated with the number of freshmen asked until finding one who agrees that same-sex couples should have legal marital status.
The PDF is essential for understanding the likelihood of each event's occurrence. In this context, if you set the random variable \( X \) to represent the number of freshmen asked before receiving a 'yes,' the PDF can numerically describe this scenario.
For example:
  • \( P(X = 1) \) is the probability that the first freshman asked says 'yes,' calculated to be 0.713.
  • \( P(X = 2) \) involves the first freshman saying 'no' and the second saying 'yes,' which is 0.204.
These probabilities are calculated using the formula for geometric distribution, where each step builds upon the last, considering each preceding event's failure. This helps us construct a comprehensive view of possible outcomes and their associated probabilities.
Geometric Probability
Geometric probability is a concept used to model situations where we're interested in knowing how many trials it takes to achieve the first success. In this exercise, it models asking freshmen until one says they support same-sex marriage rights.
For a geometric distribution, several properties exist:
  • The probability of success (\( p \)) is constant for each trial. Here, \( p = 0.713 \).
  • Each trial is independent; the outcome doesn't affect other trials.
  • We're counting the number of trials until the first success occurs.
Using these properties, the geometric probability expresses the chance of achieving the first success on the \( n \)-th trial using the formula: \[ P(X = n) = (1 - p)^{n-1} \times p \]
Let's decode this with examples:
If our third trial is the first success, it means two previous trials failed to yield a 'yes.' Thus, the probability is calculated as \[ P(X = 3) = (1 - 0.713)^2 \times 0.713 = 0.0586 \].
Understanding geometric probability helps in anticipating how many attempts an experiment might need before finding a positive result.
Success Probability
Success probability is the likelihood of achieving a favorable outcome in a given trial. In this problem, a 'yes' response from a freshman indicating support for same-sex marital rights is a success. The probability of obtaining a 'yes' is noted as 0.713.
This concept is integral to calculating geometric distribution probabilities, as it underlies each formula. A success probability remains constant in each trial when using geometric distributions. This stability allows us to predict likelihoods across different trials effectively.
For example,
  • \( P(X = 1) = 0.713 \) indicates success on the first attempt.
  • \( P(X = 5) = (1 - 0.713)^4 \times 0.713 = 0.0048 \) shows that success occurs on the fifth attempt after four failures.
The constant nature of success probability means it doesn't change as trials progress, offering a reliable metric to gauge various outcomes' likelihoods. Understanding the concept of success probability is crucial to working with any probability distribution, whether geometric or otherwise.

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Most popular questions from this chapter

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