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Use the following information to answer the next eight exercises: The Higher Education Research Institute at UCLA collected data from 203,967 incoming first-time, full-time freshmen from 270 four year colleges and universities in the U.S. 71.3% of those students replied that, yes, they believe that same-sex couples should have the right to legal marital status. Suppose that you randomly pick eight first-time, full-time freshmen from the survey. You are interested in the number that believes that same sex-couples should have the right to legal marital status. What is the standard deviation \((\sigma) ?\)

Short Answer

Expert verified
The standard deviation is approximately 1.2797.

Step by step solution

01

Identify the Parameters

From the given problem, we see that the number of trials, \( n \), is 8 since we are picking 8 freshmen. The probability \( p \) of a single freshman believing in the right to legal marital status for same-sex couples is 0.713.
02

Recall the Formula for Standard Deviation

In a binomial distribution, the standard deviation \( \sigma \) can be calculated using the formula \( \sigma = \sqrt{n \cdot p \cdot (1-p)} \).
03

Calculate the Complement Probability

The complement probability \( q \) of not believing in the right to legal marital status for same-sex couples is \( 1 - p = 1 - 0.713 = 0.287 \).
04

Substitute Values into the Formula

Substitute \( n = 8 \), \( p = 0.713 \), and \( q = 0.287 \) into the standard deviation formula: \( \sigma = \sqrt{8 \cdot 0.713 \cdot 0.287} \).
05

Perform the Calculation

Calculate the expression inside the square root: \( 8 \cdot 0.713 \cdot 0.287 = 1.637944 \). Then, take the square root to find \( \sigma = \sqrt{1.637944} \approx 1.2797 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
The standard deviation is a measure of how spread out numbers are in a data set. In a binomial distribution, it helps us understand the variability of outcomes. When working with binomial distributions, we use a specific formula to compute this value.

The standard deviation for a binomial distribution is calculated using the formula:
  • \(\sigma = \sqrt{n \cdot p \cdot (1-p)}\)
Here:
  • \(n\) is the number of trials, or how many times the experiment is repeated.
  • \(p\) is the probability of success on each trial.
  • \(1 - p\) represents the probability of failure, also known as the complement probability.
The value obtained represents the average distance of each outcome from the mean, giving us insights into how likely the outcomes are to deviate from the expected number of successes. For large deviations, the distribution of outcomes is more spread out.
Probability Distribution
A probability distribution outlines all the possible outcomes of a random process and assigns each outcome a probability. In the context of a binomial distribution, we focus on two outcomes: success and failure. Each trial has a fixed probability of success \(p\) and a corresponding complement probability \(q = 1 - p\).

Binomial probability distribution is particularly useful when we have a fixed number of trials \(n\), and we're interested in the number of successes in those trials. The probability of obtaining exactly \(k\) successes is given by the formula:
  • \( P(X = k) = \binom{n}{k} \cdot p^k \cdot (1-p)^{n-k} \)
In this formula, \(\binom{n}{k}\) represents the number of ways to choose \(k\) successes from \(n\) trials. By using this formula, we make a probability distribution table that captures the likelihood of obtaining any number of successes from 0 to \(n\).

Understanding this distribution helps us identify expected patterns and make predictions, maintaining the crucial balance of probability across different outcomes.
Complement Probability
Complement probability refers to the probability of the opposite of a certain event occurring. In a binomial setting, if an event has a probability \(p\) of occurring, the complement probability \(q\) would be \(1 - p\). This concept allows us to consider not only the likelihood of an event happening but also the likelihood of it not happening.

For example, given probability \(p = 0.713\) of a student supporting legal marital status for same-sex couples, the complement probability \(q\), representing those who do not support this, would be \(0.287\).

Complement probability is crucial in calculating outcomes like the variance and standard deviation in a binomial distribution as it completes the probability framework. It also helps ensure that all potential outcomes are considered when examining probabilities, since together with \(p\), they cover all possible scenarios, ensuring that the total probability sums up to 1.

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Most popular questions from this chapter

Use the following information to answer the next two exercises: The probability that the San Jose Sharks will win any given game is 0.3694 based on a 13-year win history of 382 wins out of 1,034 games played (as of a certain date). An upcoming monthly schedule contains 12 games. What is the probability that the San Jose Sharks win six games in that upcoming month? a. 0.1476 b. 0.2336 c. 0.7664 d. 0.8903

Find the standard deviation. $$\begin{array}{|c|c|c|c|}\hline x & {P(x)} & {x^{*} P(x)} & {(x-\mu)^{2} P(x)} \\ \hline 2 & {0.1} & {2(0.1)=0.2} & {(2-5.4)^{2}(0.1)=1.156} \\\ \hline 4 & {0.3} & {4(0.3)=1.2} & {(4-5.4)^{2}(0.3)=0.588} \\ \hline 6 & {0.4} & {6(0.4)=2.4} & {(6-5.4)^{2}(0.4)=0.144} \\ \hline 8 & {0.2} & {8(0.2)=1.6} & {(8-5.4)^{2}(0.2)=1.352} \\ \hline \end{array}$$

Use the following information to answer the next six exercises: The Higher Education Research Institute at UCLA collected data from 203,967 incoming first-time, full-time freshmen from 270 four-year colleges and universities in the U.S. 71.3% of those students replied that, yes, they believe that same-sex couples should have the right to legal marital status. Suppose that you randomly select freshman from the study until you find one who replies 鈥測es.鈥 You are interested in the number of freshmen you must ask. In words, define the random variable \(X.\)

Approximately 8% of students at a local high school participate in after- school sports all four years of high school. A group of 60 seniors is randomly chosen. Of interest is the number that participated in after-school sports all four years of high school. a. In words, define the random variable X. b. List the values that X may take on. c. Give the distribution of \(X, X \sim\) _____(_____,_____) d. How many seniors are expected to have participated in after-school sports all four years of high school? e. Based on numerical values, would you be surprised if none of the seniors participated in after school sports all four years of high school? Justify your answer numerically. f. Based on numerical values, is it more likely that four or that five of the seniors participated in after-school sports all four years of high school? Justify your answer numerically.

Suppose that nine Massachusetts athletes are scheduled to appear at a charity benefit. The nine are randomly chosen from eight volunteers from the Boston Celtics and four volunteers from the New England Patriots. We are interested in the number of Patriots picked. a. In words, define the random variable X. b. List the values that X may take on. C. Give the distribution of \(X . X \sim\) ____ (___,____) d. Are you choosing the nine athletes with or without replacement?

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