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The chance of having an extra fortune in a fortune cookie is about 3%. Given a bag of 144 fortune cookies, we are interested in the number of cookies with an extra fortune. Two distributions may be used to solve this problem, but only use one distribution to solve the problem. a. In words, define the random variable X. b. List the values that X may take on. c. Give the distribution of \(X, X \sim\) _____(_____,_____) d. How many cookies do we expect to have an extra fortune? e. Find the probability that none of the cookies have an extra fortune. f. Find the probability that more than three have an extra fortune. g. As n increases, what happens involving the probabilities using the two distributions? Explain in complete sentences.

Short Answer

Expert verified
X is the number of cookies with an extra fortune; values 0-144; \(X \sim \text{Binomial}(144, 0.03)\); expect about 4.32 cookies; probability none is extra is 1.97%; more than three is 70.74%; for large n, binomial approximates normal distribution.

Step by step solution

01

Defining the Random Variable

The random variable \(X\) is defined as the number of fortune cookies with an extra fortune in a bag of 144 cookies.
02

Identifying Values of X

The values that \(X\) may take on are integers from 0 to 144, since it represents the count of cookies with an extra fortune.
03

Choosing a Distribution

Since we have a fixed number of trials (144), a constant probability of success (3%), and independent trials, \(X\) follows a binomial distribution: \[X \sim \text{Binomial}(n=144, p=0.03)\]
04

Calculating Expected Value

The expected number of cookies with an extra fortune is given by the formula \(E(X) = np\): \(E(X) = 144 \times 0.03 = 4.32\). Therefore, we expect about 4 to 5 cookies to have an extra fortune.
05

Finding Probability of Zero Extra Fortunes

The probability that none of the 144 cookies have an extra fortune is: \(P(X=0) = (1-p)^{n} = (0.97)^{144} \approx 0.0197\), or about 1.97%.
06

Finding Probability of More Than Three Extra Fortunes

To find this probability, calculate: \(P(X > 3) = 1 - P(X \leq 3)\). Using the binomial cumulative distribution function: \(P(X \leq 3) = \text{BinomialCDF}(144, 0.03, 3)\). Subtract from 1 to get \(P(X > 3) \approx 1 - 0.2926 = 0.7074\), so about 70.74%.
07

Analyzing Effects as n Increases

As \(n\) increases, the binomial distribution approaches a normal distribution due to the Central Limit Theorem, making the normal approximation appropriate for large \(n\). The probability of occurrences also stabilizes, making calculations with a normal distribution more convenient.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variable
In our exercise, the random variable is denoted by \(X\). This signifies the number of fortune cookies in a bag of 144 cookies that contain an extra fortune. A random variable is a fundamental concept in statistics and probability, representing a numerical outcome of a random phenomenon. Here, each cookie can either have an extra fortune or not.
Random variables can be classified into discrete or continuous types. Discrete random variables, like \(X\) in this exercise, take on a countable number of values. Here, \(X\) can be any integer from 0 to 144, which corresponds to the possible number of cookies with an extra fortune in the bag. Understanding the nature of the random variable is crucial as it helps in determining the appropriate distribution model to use for calculations.
  • The random variable \(X\) measures the count of a specific outcome.
  • Discrete random variables take on countable values, which in this case is from 0 to 144.
Expected Value
The expected value, often denoted as \(E(X)\), is a key concept in probability and statistics that represents the long-term average or mean value of a random variable. It gives a single summary figure representing the central tendency of a set of possible outcomes.
For a binomial distribution, like in this fortune cookie exercise, the expected value is calculated using the formula \(E(X) = np\), where \(n\) is the number of trials, and \(p\) is the probability of success on an individual trial. Here, with \(n = 144\) and \(p = 0.03\), the expected value is \(E(X) = 144 \times 0.03 = 4.32\). This means, on average, we expect about 4 or 5 cookies to have an extra fortune.
  • The expected value is the average outcome of a random variable over many trials.
  • It provides a central tendency, giving insight into the most likely number of extra fortunes.
Central Limit Theorem
The Central Limit Theorem (CLT) is a pivotal theorem in statistics that describes how, under certain conditions, the distribution of a sum of many independent random variables tends toward a normal distribution as the number of variables grows. Even if the original variables themselves are not normally distributed, their sum can be.This theorem becomes particularly useful in our fortune cookie exercise as we analyze the binomial distribution of \(X\), the random variable, when the number of trials \(n\) is large. As \(n\) increases, the binomial distribution of \(X\) starts resembling a normal distribution. This makes it more convenient to perform probability calculations using the properties of the normal distribution due to its simplicity, especially since tools like the normal cumulative distribution function can simplify complex calculations.
  • The CLT allows us to use normal distribution as an approximation for large sample sizes.
  • It simplifies probability calculations by relying on the properties of the normal distribution.
Probability
Probability is a measure of the likelihood of a specific outcome or event occurring. In the context of our exercise with fortune cookies, probability addresses the chances of particular numbers of cookies having an extra fortune out of the total 144.
The probability that none of the cookies have an extra fortune is calculated using the formula \(P(X=0) = (1-p)^{n}\), resulting in \((0.97)^{144} \approx 0.0197\) or 1.97%. This tells us how likely it is to end up with no extra fortunes at all. Additionally, the probability that more than three cookies include an extra fortune is found by calculating \(P(X > 3) = 1 - P(X \leq 3)\). With the cumulative distribution function, we find \(P(X > 3) \approx 0.7074\), indicating a 70.74% chance.
  • Probability quantifies the likelihood of different outcomes.
  • It involves formulas and functions to calculate the chances of various potential scenarios.

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