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Use the following information to answer the next ten exercises. Forty-eight percent of all Californians registered voters prefer life in prison without parole over the death penalty for a person convicted of first degree murder. Among Latino California registered voters, 55% prefer life in prison without parole over the death penalty for a person convicted of first degree murder. 37.6% of all Californians are Latino. In this problem, let: • C = Californians (registered voters) preferring life in prison without parole over the death penalty for a person convicted of first degree murder. • L = Latino Californians Suppose that one Californian is randomly selected. Find P(C).

Short Answer

Expert verified
P(C) = 0.48

Step by step solution

01

Define Events

In this problem, we need to identify the events we are working with. We have: - Event C: A Californian prefers life in prison without parole over the death penalty. - Event L: A Californian is Latino.
02

Identify Given Probabilities

From the problem statement, we know: - The probability a Californian voter prefers life in prison without parole, conditioned on being Latino, is 0.55 or 55%. - The probability of a Californian voter being Latino is 0.376 or 37.6%. - The probability a Californian voter prefers life in prison without parole, without any condition, is 0.48 or 48%.
03

Apply the Law of Total Probability

To find the unconditional probability P(C), we use the law of total probability:\[ P(C) = P(C | L)P(L) + P(C | L')P(L') \]where L' is the event of being non-Latino.
04

Calculate Complementary Probability

First, calculate the probability of not being Latino, which is the complement of being Latino:\[ P(L') = 1 - P(L) = 1 - 0.376 = 0.624 \]
05

Apply Given Probabilities

Insert the given probabilities into the formula:\[ P(C) = (0.55 \times 0.376) + (P(C|L') \times 0.624) \]You need to find \( P(C | L') \), which is given implicitly by the fact that 48% of all Californians prefer life in prison without parole:
06

Solve for Missing Probability

Since 48% of all Californians prefer life in prison without parole, the distribution can be expressed as:\[ 0.48 = (0.55 \times 0.376) + (P(C|L') \times 0.624) \]Calculate \( P(C|L') \).
07

Calculate P(C | L')

Solve the equation:\[ 0.48 = (0.55 \times 0.376) + (P(C|L') \times 0.624) \]First, calculate \( 0.55 \times 0.376 = 0.2068 \).Then, rearrange and solve: \( 0.48 - 0.2068 = P(C|L') \times 0.624 \).Thus, \( 0.2732 = P(C|L') \times 0.624 \).Finally, \( P(C|L') = \frac{0.2732}{0.624} \approx 0.4385 \).
08

Confirm Result Using Equation

Now verify using the equation:\[ P(C) = (0.55 \times 0.376) + (0.4385 \times 0.624) \]Calculate \( 0.4385 \times 0.624 \approx 0.2734 \).Add them: \( 0.2068 + 0.2734 \approx 0.48 \).
09

Conclusion

Therefore, the probability that a randomly selected Californian registered voter prefers life in prison without parole is indeed 0.48.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Law of Total Probability
The Law of Total Probability is a fundamental concept in probability theory. It provides a way to calculate the probability of an outcome by considering all possible scenarios that can lead to that outcome. In this case, we want to determine the probability, \( P(C) \), that a Californian prefers life in prison without parole over the death penalty. To apply the law, we first divide the scenarios into two mutually exclusive events: the person is a Latino \( (L) \) or not a Latino \( (L') \). Each scenario contributes to the total probability proportionally based on its own likelihood and the conditioned probability of the outcome in that scenario.The formula is:\[ P(C) = P(C | L)P(L) + P(C | L')P(L') \]Where:- \( P(C | L) \) is the probability that a Latino prefers life in prison without parole.- \( P(C | L') \) is the similar probability for non-Latinos.- \( P(L) \) and \( P(L') \) are the probabilities of the voter being Latino or not, respectively.This approach ensures that all possible pathways contributing to preferring life in prison are considered, resulting in a comprehensive probability calculation.
Complementary Probability
Complementary Probability is a simple yet crucial concept in probability. It represents the idea that the probability of an event not occurring is equal to the total probability minus the probability of the event occurring.To use complementary probability in our problem, we need to find \( P(L') \), the probability that a Californian voter is not Latino. Since only two possibilities exist—being Latino or not being Latino—their probabilities must sum to 1:\[ P(L') = 1 - P(L) \]In this example:- \( P(L) = 0.376 \)So, \( P(L') = 1 - 0.376 = 0.624 \)This step is vital for accurately applying the Law of Total Probability, allowing us to incorporate both Latino and non-Latino scenarios effectively.
Probability Calculation
Probability Calculation involves determining the likelihood of a certain outcome by appropriately applying probabilities for different conditions. Here, after defining our relevant probabilities and events, we sum up the contributions from different groups based on their conditional probabilities.For Latino voters:- \( P(C | L) = 0.55 \) and \( P(L) = 0.376 \)- So, \( P(C | L) \times P(L) = 0.55 \times 0.376 = 0.2068 \)For Non-Latino voters:- We use the overall probability \( P(C) = 0.48 \)- Then solve for \( P(C | L') \) using \( P(C) = 0.48 \) in the formula:\[ 0.48 = 0.2068 + P(C | L') \times 0.624 \]- Rearrange to find:\( P(C | L') = \frac{0.2732}{0.624} \approx 0.4385 \)Combining both:- Verify by computing \( 0.4385 \times 0.624 \approx 0.2734 \)- Adding up contributions: \( 0.2068 + 0.2734 \approx 0.48 \)The result confirms the probability \( P(C) = 0.48 \) is correctly calculated, encompassing all registered voters appropriately.

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Most popular questions from this chapter

A box of cookies contains three chocolate and seven butter cookies. Miguel randomly selects a cookie and eats it. Then he randomly selects another cookie and eats it. (How many cookies did he take?) a. Draw the tree that represents the possibilities for the cookie selections. Write the probabilities along each branch of the tree. b. Are the probabilities for the flavor of the SECOND cookie that Miguel selects independent of his first selection? Explain. c. For each complete path through the tree, write the event it represents and find the probabilities. d. Let S be the event that both cookies selected were the same flavor. Find P(S). e. Let T be the event that the cookies selected were different flavors. Find P(T) by two different methods: by using the complement rule and by using the branches of the tree. Your answers should be the same with both methods. f. Let U be the event that the second cookie selected is a butter cookie. Find P(U).

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