/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Use the following information to... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the following information to answer the next four exercises. A box is filled with several party favors. It contains 12 hats, 15 noisemakers, ten finger traps, and five bags of confetti. Let H = the event of getting a hat. Let N = the event of getting a noisemaker. Let F = the event of getting a finger trap. Let C = the event of getting a bag of confetti. Find P(F).

Short Answer

Expert verified
P(F) = \( \frac{5}{21} \)

Step by step solution

01

Understand the Problem

We need to find the probability of selecting a finger trap from the box. There are several types of party favors in the box, and we are interested in the finger traps.
02

Identify the Total Number of Items

Add up all the party favors in the box. There are 12 hats, 15 noisemakers, 10 finger traps, and 5 bags of confetti. The total number of party favors is calculated by:\[ 12 + 15 + 10 + 5 = 42 \]
03

Identify the Number of Favorable Outcomes

The favorable outcomes are the number of finger traps in the box. According to the problem, there are 10 finger traps.
04

Calculate the Probability of Getting a Finger Trap

The probability \( P(F) \) of selecting a finger trap is calculated using the formula:\[ P(F) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{10}{42} \]
05

Simplify the Probability Fraction

Simplify the fraction \( \frac{10}{42} \) by finding the greatest common divisor (GCD) of 10 and 42, which is 2. Simplifying the fraction gives:\[ \frac{10}{42} = \frac{10 \div 2}{42 \div 2} = \frac{5}{21} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Probability is the likelihood or chance of a specific event occurring. In our scenario, we want to know the odds of choosing a finger trap from a box full of various party favors. To do this, we need to use the probability formula. The formula to calculate probability is: \[ P( ext{Event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]

To apply this to our problem:
  • The total number of outcomes refers to all party favors combined in the box. After summing them up, it's clear there are 42 items in total (12 hats, 15 noisemakers, 10 finger traps, and 5 bags of confetti).
  • The number of favorable outcomes is the number of finger traps (the event we are interested in), which is 10.
This gives us the probability of pulling out a finger trap as:\[ P(F) = \frac{10}{42} \]

Probability is a useful concept for predicting outcomes and making decisions based on available data.
Favorable Outcomes
Understanding what constitutes a favorable outcome is key to calculating probability. In the context of our party favors problem, a favorable outcome is defined as the event of selecting a finger trap from the box.

Here's how we determine and count favorable outcomes:
  • We look at all the different types of items in the box (hats, noisemakers, finger traps, confetti bags) and identify the specific event we are interested in.
  • In this exercise, we are interested in just one type: finger traps. Thus, the number of favorable outcomes is the number of finger traps, which totals 10.
Your outcome of interest could be anything else depending on your goal — for example, choosing a hat would represent a different favorable outcome. In probability exercises, clearly identifying the event you are interested in is fundamental.

This understanding allows you to correctly plug the numbers into the probability formula and make accurate predictions.
Fraction Simplification
In many probability problems, you end up with a fraction that represents the probability of an event occurring. Simplifying fractions not only makes the number easier to interpret but also ensures clarity in your final answer.

After calculating the fraction for our probability exercise, we end up with:\[ \frac{10}{42} \]

To simplify this, we need to find the greatest common divisor (GCD) of the numerator and the denominator. Here’s the step-by-step:
  • The GCD of 10 and 42 is 2. We divide both the numerator (10) and the denominator (42) by this number to reduce the fraction.
  • This simplifies our fraction to: \[ \frac{10 \div 2}{42 \div 2} = \frac{5}{21} \]
The fraction \( \frac{5}{21} \) is now in its simplest form. Simplifying fractions is an essential skill in probability as it gives you a cleaner and more digestible result, and it is especially useful if you need to compare probabilities or carry out additional calculations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the following information to answer the next ten exercises. On a baseball team, there are infielders and outfielders. Some players are great hitters, and some players are not great hitters. Let I = the event that a player in an infielder. Let O = the event that a player is an outfielder. Let H = the event that a player is a great hitter. Let N = the event that a player is not a great hitter Write the symbols for the probability that a player is not an outfielder.

After Rob Ford, the mayor of Toronto, announced his plans to cut budget costs in late 2011, the Forum Research polled 1,046 people to measure the mayor’s popularity. Everyone polled expressed either approval or disapproval. These are the results their poll produced: • In early 2011, 60 percent of the population approved of Mayor Ford’s actions in office. • In mid-2011, 57 percent of the population approved of his actions. • In late 2011, the percentage of popular approval was measured at 42 percent. a. What is the sample size for this study? b. What proportion in the poll disapproved of Mayor Ford, according to the results from late 2011? c. How many people polled responded that they approved of Mayor Ford in late 2011? d. What is the probability that a person supported Mayor Ford, based on the data collected in mid-2011? e. What is the probability that a person supported Mayor Ford, based on the data collected in early 2011?

Use the following information to answer the next ten exercises. Forty-eight percent of all Californians registered voters prefer life in prison without parole over the death penalty for a person convicted of first degree murder. Among Latino California registered voters, 55% prefer life in prison without parole over the death penalty for a person convicted of first degree murder. 37.6% of all Californians are Latino. In this problem, let: • C = Californians (registered voters) preferring life in prison without parole over the death penalty for a person convicted of first degree murder. • L = Latino Californians Suppose that one Californian is randomly selected. Find P(C).

In a box of assorted cookies, 36% contain chocolate and 12% contain nuts. Of those, 8% contain both chocolate and nuts. Sean is allergic to both chocolate and nuts. a. Find the probability that a cookie contains chocolate or nuts (he can't eat it). b. Find the probability that a cookie does not contain chocolate or nuts (he can eat it).

The following table of data obtained from www.baseball-almanac.com shows hit information for four players. Suppose that one hit from the table is randomly selected. $$\begin{array}{|l|l|l|l|l|}\hline \text { Name } & {\text { single }} & {\text { Double }} & {\text { Triple }} & {\text { Home Run }} & {\text { Total Hits }} \\ \hline \text { Babe Ruth } & {1,517} & {506} & {136} & {714} & {2,873} \\ \hline \text { Jackie Robinson } & {1,054} & {273} & {54} & {137} & {1,518} \\ \hline \text { Ty Cobb } & {3,603} & {174} & {295} & {114} & {4,189} \\ \hline \text { Hank Aaron } & {2,294} & {624} & {98} & {755} & {3,771} \\ \hline\end{array}$$ Are "the hit being made by Hank Aaron" and "the hit being a double" independent events? a. Yes, because P(hit by Hank Aaron|hit is a double) = P(hit by Hank Aaron) b. No, because P(hit by Hank Aaron|hit is a double) ? P(hit is a double) c. No, because P(hit is by Hank Aaron|hit is a double) ? P(hit by Hank Aaron) d. Yes, because P(hit is by Hank Aaron|hit is a double) = P(hit is a double)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.