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Given events J and K: P(J) = 0.18; P(K) = 0.37; P(J OR K) = 0.45 a. Find P(J AND K). b. Find the probability of the complement of event (J AND K). c. Find the probability of the complement of event (J AND K).

Short Answer

Expert verified
a. P(J AND K) = 0.10; b. Complement of P(J AND K) = 0.90.

Step by step solution

01

Understand the formula for P(J OR K)

The probability of either event J or event K occurring is given by the formula: \[ P(J \text{ OR } K) = P(J) + P(K) - P(J \text{ AND } K) \]. We will use this to find \( P(J \text{ AND } K) \).
02

Insert known values into the formula

Substitute \( P(J) = 0.18 \), \( P(K) = 0.37 \), and \( P(J \text{ OR } K) = 0.45 \) into the formula: \[ 0.45 = 0.18 + 0.37 - P(J \text{ AND } K) \].
03

Solve for P(J AND K)

Rearrange the equation to solve for \( P(J \text{ AND } K) \): \[ P(J \text{ AND } K) = 0.18 + 0.37 - 0.45 \]. Calculate this to find \( P(J \text{ AND } K) = 0.10 \).
04

Calculate the complement of P(J AND K)

The complement of \( P(J \text{ AND } K) \) is \( 1 - P(J \text{ AND } K) \). Substitute the value found in Step 3: \[ 1 - 0.10 = 0.90 \]. Thus, the complement is \( 0.90 \).
05

Confirm understanding

Make sure that computations match the logical steps and verify correctness. The probability of the complement, calculated in Step 4, is confirmed as consistent with initial values.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complement of an Event
Probability offers a way to understand how likely an event is to occur. But sometimes, we are more interested in when it does not. This is where the **complement of an event** comes into play. For any event, the complement refers to scenarios where the event does not happen. Mathematically, the probability of the complement of an event is calculated by subtracting the probability of the event from 1.
\( P(\text{Not A}) = 1 - P(A) \).
This formula works because probabilities for all possible outcomes sum to 1. For example, if the probability of rainfall (Event R) is 0.30, the probability of no rainfall is \( 1 - 0.30 = 0.70 \). This has practical uses like planning for scenarios where the preferred event does not occur. In the exercise, we found the complement of \( P(J \text{ AND } K) \) as 0.90, which means there is a 90% chance that either event J or event K, or both, DO NOT occur simultaneously.
Intersection of Events
The **intersection of events** is a probability concept that identifies when two or more events occur at the same time. Think of this as finding a common area where events overlap. This is represented symbolically by 鈥淎ND鈥 (e.g., \( J \text{ AND } K \)) which means both events J and K happen simultaneously.
Mathematically, it's often denoted as \( P(J \cap K) \) where \( \cap \) is the intersection symbol.
To find the probability of this intersection, we used the formula:
  • \( P(J \text{ OR } K) = P(J) + P(K) - P(J \text{ AND } K) \)
This formula ensures we don't double count the intersection when adding probabilities of multiple events. From the exercise, using given values, this provided \( P(J \text{ AND } K) = 0.10 \). So, there is a 10% chance that both events J and K happen at the same time.
Union of Events
The **union of events** relates to any scenario where one or more of the events occur. This is visualized as combining event outcomes to create a broader possibility space where at least one event takes place. In probability terms, the union of events is represented with 鈥淥R鈥 (e.g., \( J \text{ OR } K \)), meaning either event J occurs, event K occurs, or both.
Representing this mathematically, we use the formula:
  • \( P(J \cup K) = P(J) + P(K) - P(J \text{ AND } K) \)
Here, \( \cup \) indicates union, and the formula ensures that any overlapping probability (\( P(J \text{ AND } K) \)) isn't counted twice.
In our exercise, \( P(J \text{ OR } K) = 0.45 \) was given, meaning there's a 45% probability that either one or both of the events J and K will happen. This concept is used widely in scenarios where outcomes are large, such as in risk management or predictive modeling.

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Most popular questions from this chapter

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