/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 69 Use the following information to... [FREE SOLUTION] | 91Ó°ÊÓ

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Use the following information to answer the next two exercises: The following data are the distances between 20 retail stores and a large distribution center. The distances are in miles. 29; 37; 38; 40; 58; 67; 68; 69; 76; 86; 87; 95; 96; 96; 99; 106; 112; 127; 145; 150 Use a graphing calculator or computer to find the standard deviation and round to the nearest tenth.

Short Answer

Expert verified
The standard deviation is approximately 32.2 miles.

Step by step solution

01

Find the Mean

First, find the mean (average) of the data set. Add all the distances together and divide by the number of data points. \[\text{Mean} = \frac{29 + 37 + 38 + 40 + 58 + 67 + 68 + 69 + 76 + 86 + 87 + 95 + 96 + 96 + 99 + 106 + 112 + 127 + 145 + 150}{20} = \frac{1716}{20} = 85.8\]
02

Find Deviations from the Mean

Subtract the mean from each data point to find the deviation of each point. For example, the deviation for the first point is \(29 - 85.8 = -56.8\). Calculate this for all data points.
03

Square Each Deviation

Square each of the deviations obtained in Step 2 to ensure they are positive. For instance, \((-56.8)^2 = 3226.24\). Repeat for all deviations.
04

Calculate the Average of the Squares

Sum all the squared deviations and divide by the number of data points (20) to find the variance. \[\text{Variance} = \frac{3226.24 + 2377.24 + \,..., + 4146.24}{20}\]
05

Find the Square Root of the Variance

Take the square root of the variance to find the standard deviation. If the variance, for example, is found to be 1034.3, then the standard deviation \( \sigma = \sqrt{1034.3} \approx 32.2 \). Round to the nearest tenth.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
Finding the mean is a fundamental step in many statistical calculations, including the standard deviation. The mean provides a central point of reference for the data set. It is calculated by summing up all the observations and dividing by the number of observations. This process helps us understand the average value of the data set. In our example, we have a set of distances: 29, 37, 38, ..., 150. We add them all together to get 1716. Since there are 20 data points, we divide 1716 by 20, giving us an average, or mean, of 85.8 miles.
This mean serves as a typical value around which the other distances are spread.
Variance
Variance measures how much the data points deviate from the mean. It's crucial for understanding the dispersion in data. To calculate it, we first find how far each data point is from the mean (this is the deviation), and then we square each deviation. Squaring the deviations eliminates negative values and gives weight to larger deviations, thereby indicating how spread out the values are.
After obtaining these squared deviations, we sum them up and divide by the number of data points to get the average of the squared deviations, known as the variance. In our exercise, this step is key as it helps quantify the level of variation among store distances to the distribution center.
Deviation from Mean
Deviation from the mean shows the difference between each data point and the mean value. This concept helps in identifying how far off each point is from the average. In our data set, this calculation involves subtracting the mean (85.8) from each data point.
For instance, with a first point of 29, the calculation is 29 - 85.8, resulting in a deviation of -56.8. This process is repeated for all data points, giving us an array of deviations that tell us exactly how much each distance varies around the mean. These deviations are critical for further calculations, such as variance and standard deviation.
Data Analysis
Data analysis involves using statistical methods to interpret data sets critically. In our problem, it includes calculating the mean, deviations, variance, and standard deviation. By understanding these calculations, one can derive insights into the data's spread and central tendency.
This kind of analysis helps identify patterns or anomalies in the distances between the stores and the distribution center. It also aids in effective decision-making, as it provides quantitative measures of data spread, like the standard deviation which reflects how much individual data points differ from the mean. Such analysis is not just theoretical but practical, impacting logistics, resource allocation, and strategic planning in business contexts.

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Most popular questions from this chapter

Use the following information to answer the next three exercises: Sixty-five randomly selected car salespersons were asked the number of cars they generally sell in one week. Fourteen people answered that they generally sell three cars; nineteen generally sell four cars; twelve generally sell five cars; nine generally sell six cars; eleven generally sell seven cars. Calculate the following: sample mean \(=\overline{x}=\)____

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