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Use the following information to answer the next twelve exercises. In the recent Census, three percent of the U.S. population reported being of two or more races. However, the percent varies tremendously from state to state. Suppose that two random surveys are conducted. In the first random survey, out of 1,000 North Dakotans, only nine people reported being of two or more races. In the second random survey, out of 500 Nevadans, 17 people reported being of two or more races. Conduct a hypothesis test to determine if the population percents are the same for the two states or if the percent for Nevada is statistically higher than for North Dakota. Which distribution (normal or Student's t) would you use for this hypothesis test?

Short Answer

Expert verified
Use the normal distribution for a two-proportion z-test.

Step by step solution

01

Determine Hypothesis Test Type

We need to determine which hypothesis test to use by considering the sample sizes and the conditions for a normal distribution approximation in a hypothesis test for proportions.
02

Check Distribution Conditions for Normal Approximation

For a two-proportion z-test, each group must meet the condition that both \( np \geq 5 \) and \( nq \geq 5 \), where \( n \) is the sample size, \( p \) is the sample proportion, and \( q = 1 - p \). Calculate these values for both North Dakota and Nevada.
03

Calculate Sample Proportions

For North Dakota, the sample proportion is \( \hat{p}_1 = \frac{9}{1000} = 0.009 \). For Nevada, the sample proportion is \( \hat{p}_2 = \frac{17}{500} = 0.034 \).
04

Calculate Expected Values

For North Dakota: \( n_1 \hat{p}_1 = 1000 \times 0.009 = 9 \) and \( n_1 \hat{q}_1 = 1000 \times 0.991 = 991 \). For Nevada: \( n_2 \hat{p}_2 = 500 \times 0.034 = 17 \) and \( n_2 \hat{q}_2 = 500 \times 0.966 = 483 \). Both states meet the criteria for being approximated by a normal distribution.
05

Conclusion on Distribution Choice

Since both groups meet the criteria of having their expected counts of successes and failures greater than 5, we can use the normal distribution to perform a two-proportion z-test.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Two-Proportion Z-Test
A two-proportion z-test is a statistical method used to determine if there is a significant difference between the proportions of two independent groups. Here, we are interested in comparing the proportions of individuals identifying as two or more races in North Dakota and Nevada using their respective survey results.

To perform this test, both groups need to satisfy certain conditions. Specifically, the expected numbers of successes and failures in each sample must be 5 or greater. This ensures that the distribution can be approximated to a normal one, making the z-test applicable. In this exercise:
  • The first group is North Dakota: 9 out of 1000 people reported as being of two or more races.
  • The second group is Nevada: 17 out of 500 people reported as being of two or more races.
By conducting the test, we can determine if there's a statistically significant difference between the two states' proportions. If Nevada's proportion is significantly higher, it supports the claim made in the hypothesis test.
Normal Distribution
The normal distribution is paramount in hypothesis testing due to its unique properties. When sample sizes are large enough, the distribution of sample proportions will approximate a normal distribution.

Why Use Normal Distribution?

Normal distribution allows us to use z-tests, making it easier to calculate probabilities and p-values. It's a symmetric distribution where most data points fall close to the mean.

Application in This Exercise

In this problem, both sample groups met the thresholds for using a normal distribution. For both North Dakota and Nevada, the number of expected successes and failures exceed 5, making the normal approximation valid. This enables us to utilize the two-proportion z-test effectively.
Sample Proportions
Sample proportions are essential when comparing the characteristics of two groups through hypothesis testing. They give a snapshot of what is observed in the sample compared to what may exist in the broader population.
Sample proportions are calculated by dividing the number of observed successes by the total sample size. In this scenario:
  • The North Dakota sample proportion: \( \hat{p}_1 = \frac{9}{1000} = 0.009 \).
  • The Nevada sample proportion: \( \hat{p}_2 = \frac{17}{500} = 0.034 \).
These figures help set up the hypothesis test by quantifying the observed differences. The larger difference in sample proportions suggests a potential difference in the population proportions which the hypothesis test seeks to affirm or refute.
Normal Approximation
Normal approximation simplifies the process of hypothesis testing by enabling the application of normal distribution properties. This approximation is particularly useful for large sample sizes where the Central Limit Theorem applies.
For a valid normal approximation of sample proportions, both sample's expected number of successes and failures should be 5 or greater. In our case:
  • North Dakota: 9 successes (\( n_1 \hat{p}_1 = 9 \)) and 991 failures (\( n_1 \hat{q}_1 = 991 \)).
  • Nevada: 17 successes (\( n_2 \hat{p}_2 = 17 \)) and 483 failures (\( n_2 \hat{q}_2 = 483 \)).
Both samples meet the criteria; thus, the normal approximation can be confidently used. This simplifies the test computation and enables the direct application of z-scores to assess the hypothesis.

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Most popular questions from this chapter

Use the following information to answer the next three exercises. Neuroinvasive West Nile virus is a severe disease that affects a person鈥檚 nervous system . It is spread by the Culex species of mosquito. In the United States in 2010 there were 629 reported cases of neuroinvasive West Nile virus out of a total of 1,021 reported cases and there were 486 neuroinvasive reported cases out of a total of 712 cases reported in 2011. Is the 2011 proportion of neuroinvasive West Nile virus cases more than the 2010 proportion of neuroinvasive West Nile virus cases? Using a 1% level of significance, conduct an appropriate hypothesis test. 鈥 鈥2011鈥 subscript: 2011 group. 鈥 鈥2010鈥 subscript: 2010 group This is: a. a test of two proportions b. a test of two independent means c. a test of a single mean d. a test of matched pairs.

Joan Nguyen recently claimed that the proportion of college-age males with at least one pierced ear is as high as the proportion of college-age females. She conducted a survey in her classes. Out of 107 males, 20 had at least one pierced ear. Out of 92 females, 47 had at least one pierced ear. Do you believe t at the proportion of males has reached the proportion of females?

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Use the following information to answer the next 15 exercises: Indicate if the hypothesis test is for a. independent group means, population standard deviations, and/or variances known b. independent group means, population standard deviations, and/or variances unknown c. matched or paired samples d. single mean e. two proportions f. single proportion It is thought that teenagers sleep more than adults on average. A study is done to verify this. A sample of 16 teenagers has a mean of 8.9 hours slept and a standard deviation of 1.2. A sample of 12 adults has a mean of 6.9 hours slept and a standard deviation of 0.6.

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