/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 Use the following information to... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the following information to answer the next twelve exercises. In the recent Census, three percent of the U.S. population reported being of two or more races. However, the percent varies tremendously from state to state. Suppose that two random surveys are conducted. In the first random survey, out of 1,000 North Dakotans, only nine people reported being of two or more races. In the second random survey, out of 500 Nevadans, 17 people reported being of two or more races. Conduct a hypothesis test to determine if the population percents are the same for the two states or if the percent for Nevada is statistically higher than for North Dakota. What is the random variable of interest for this test?

Short Answer

Expert verified
The random variable is the difference in the proportion of people of two or more races between North Dakota and Nevada.

Step by step solution

01

Define the Research Question

The exercise asks us to compare the proportion of people identifying as being of two or more races in North Dakota to that in Nevada. Specifically, we are tasked with determining if this proportion is higher in Nevada.
02

Define the Random Variable

The random variable of interest for this test is the difference in the proportion of people identifying as being of two or more races between the two states, North Dakota (ND) and Nevada (NV).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variable
In hypothesis testing, the concept of a random variable is crucial. It represents a numerical outcome of a random phenomenon. Here, our random variable of interest is the difference in the proportions of individuals identifying as two or more races between North Dakota (ND) and Nevada (NV). This random variable helps us quantify what we are investigating. The random variable is used to measure, predict, and understand the difference between two groups based on collected data.
  • For North Dakota, the proportion is derived from 9 out of 1,000 people.
  • For Nevada, it’s from 17 out of 500 people.
The difference in these proportions is what we will analyze using hypothesis testing, allowing us to infer if any observed difference is statistically significant or due to random chance.
Population Proportion
The population proportion refers to the fraction of individuals in a population with a certain characteristic. In this exercise, it looks at those who report being of two or more races.Understanding population proportion is essential in hypothesis testing as it helps us set up equations to test our hypotheses. For instance:
  • In North Dakota, the sample proportion is calculated as \( \frac{9}{1000} = 0.009 \).
  • In Nevada, it's \( \frac{17}{500} = 0.034 \).
By comparing these sample proportions to what might be expected if the two populations truly have the same proportion, we can begin to make inferences about whether the differences are significant or not.
Census Data
Census data provides comprehensive insights into demographic characteristics of populations. In hypothesis testing, census data can serve as a reference point or benchmark for comparison. In this context, we are looking at census data to establish the background rate of individuals who identify as being of two or more races within the entire U.S. population. It's an important parameter that helps to set expectations for what proportions might look like within any given state. When conducting such research investigations, the reliability, and accuracy of census data are fundamental. Despite potential variations in state-specific reporting, the overall census provides a critical point of comparison aiding in the exploration of whether certain states vary significantly from the nation-wide demographic proportions.
State Comparison
Hypothesis testing often involves comparing two different groups to understand if a statistically significant difference exists. In our exercise, we are comparing the respective proportions of people who identify as being of two or more races in North Dakota and Nevada. The focus is on whether the observed sample data for these states are representative of true differences in population proportions. Are Nevadans statistically more likely to identify with two or more races compared to North Dakotans? These comparisons require careful consideration of:
  • Sample sizes from each state (e.g., 1,000 from ND and 500 from NV)
  • The actual counts and calculated sample proportions
By analyzing these factors, we form a better understanding of the demographic dynamics between these states, potentially informing policies or further sociological studies.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Adults aged 18 years old and older were randomly selected for a survey on obesity. Adults are considered obese if their body mass index (BMI) is at least 30. The researchers wanted to determine if the proportion of women who are obese in the south is less than the proportion of southern men who are obese. The results are shown in Table 10.27. Test at the 1% level of significance. $$\begin{array}{|c|c|}\hline &{ \text{ Number who are obese} } & {\text { Sample size }} \\ \hline \text { Men } & {42,769} & {155,525} \\ \hline \text { women } & {67,169} & {248,775} \\ \hline\end{array}$$

A student at a four-year college claims that mean enrollment at four–year colleges is higher than at two–year colleges in the United States. Two surveys are conducted. Of the 35 two–year colleges surveyed, the mean enrollment was 5,068 with a standard deviation of 4,777. Of the 35 four-year colleges surveyed, the mean enrollment was 5,466 with a standard deviation of 8,191.

Use the following information to answer the next five exercises. A doctor wants to know if a blood pressure medication is effective. Six subjects have their blood pressures recorded. After twelve weeks on the medication, the same six subjects have their blood pressure recorded again. For this test, only systolic pressure is of concern. Test at the 1% significance level. $$ \begin{array}{|l|l|l|l|l|l|}\hline \text { Patient } & {\mathbf{A}} & {\mathbf{B}} & {\mathbf{C}} & {\mathbf{D}} & {\mathbf{E}} & {\mathbf{F}} \\\ \hline \text { Before } & {161} & {162} & {165} & {162} & {166} & {171} \\\ \hline \text { After } & {158} & {159} & {166} & {160} & {167} & {169} \\\ \hline\end{array} $$ What is the sample mean difference?

Use the following information to answer the next 12 exercises: The U.S. Center for Disease Control reports that the mean life expectancy was 47.6 years for whites born in 1900 and 33.0 years for nonwhites. Suppose that you randomly survey death records for people born in 1900 in a certain county. Of the 124 whites, the mean life span was 45.3 years with a standard deviation of 12.7 years. Of the 82 nonwhites, the mean life span was 34.1 years with a standard deviation of 15.6 years. Conduct a hypothesis test to see if the mean life spans in the county were the same for whites and nonwhites. Does it appear that the means are the same? Why or why not?

We are interested in whether children’s educational computer software costs less, on average, than children’s entertainment software. Thirty-six educational software titles were randomly picked from a catalog. The mean cost was \(31.14 with a standard deviation of \)4.69. Thirty-five entertainment software titles were randomly picked from the same catalog. The mean cost was \(33.86 with a standard deviation of \)10.87. Decide whether children’s educational software costs less, on average, than children’s entertainment software.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.