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Use the following information to answer the next 12 exercises: The U.S. Center for Disease Control reports that the mean life expectancy was 47.6 years for whites born in 1900 and 33.0 years for nonwhites. Suppose that you randomly survey death records for people born in 1900 in a certain county. Of the 124 whites, the mean life span was 45.3 years with a standard deviation of 12.7 years. Of the 82 nonwhites, the mean life span was 34.1 years with a standard deviation of 15.6 years. Conduct a hypothesis test to see if the mean life spans in the county were the same for whites and nonwhites. In symbols, what is the random variable of interest for this test?

Short Answer

Expert verified
The random variable of interest is \( \bar{X}_w - \bar{X}_{nw} \), the difference between the sample means of life spans for whites and nonwhites.

Step by step solution

01

Understand the Problem

We are tasked with determining if there is a difference in the mean life spans of whites and nonwhites born in 1900 in a specific county. This calls for a hypothesis test for the difference in two means.
02

Define the Random Variable

The random variable of interest in this hypothesis test is the difference between the mean life spans of whites and nonwhites in this county. Specifically, it is \( \bar{X}_w - \bar{X}_{nw} \), where \( \bar{X}_w \) is the sample mean lifespan for whites, and \( \bar{X}_{nw} \) is the sample mean lifespan for nonwhites.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Life Expectancy
Life expectancy at birth is a measure that gives an overview of how long people born in a specific year are expected to live, on average. For the exercise provided, it indicates how long whites and nonwhites were expected to live on average if born in 1900. The mean life expectancy is calculated by summing the lifespans of a group and dividing by the number of individuals in that group. In simpler terms:\[ \text{Mean life expectancy} = \frac{\text{Total years lived by all individuals}}{\text{Number of individuals}} \]In statistics, the mean life expectancy serves as a central measure to represent the dataset's average. This value is crucial for understanding the general life condition across a population. In our problem, we focus on comparing mean life expectancies of whites and nonwhites to identify any significant differences. Such analyses are often important for identifying disparities in health outcomes and living conditions among different demographic groups.
Standard Deviation
Standard deviation is an important concept in statistics, representing the amount of variation or dispersion from the average (mean) in a set of values. A low standard deviation indicates that the values tend to be close to the mean, while a high standard deviation indicates a wide range of values. Mathematically, the standard deviation is calculated as the square root of the variance, which is the average of the squared differences from the mean:\[ s = \sqrt{\frac{1}{n - 1} \sum_{i=1}^{n} (x_i - \bar{x})^2} \]Where:- \(x_i\) are the individual values- \(\bar{x}\) is the mean- \(n\) is the number of observationsIn the context of the exercise, the standard deviation allows us to determine how spread out the lifespans of whites and nonwhites are from their respective means in the sample. The higher standard deviation for nonwhites (15.6 years) suggests a greater variability in life spans compared to whites (12.7 years). Understanding the standard deviation helps in assessing the certainty of our mean life expectancy calculation and plays a crucial role in hypothesis testing.
Random Variable
In probability and statistics, a random variable is a numerical description of the outcome of a statistical experiment. For the hypothesis test in this exercise, the random variable of interest is the difference between the mean life spans of two different groups: whites and nonwhites born in 1900 in a certain county. This random variable is symbolically represented as:\[ \bar{X}_w - \bar{X}_{nw} \]Where:- \(\bar{X}_w\) is the sample mean lifespan for whites- \(\bar{X}_{nw}\) is the sample mean lifespan for nonwhitesThis difference is the quantity we are testing to determine if it is statistically significant, meaning that any observed difference might not just be due to random chance, but due to actual differences between these two groups. The hypothesis test evaluates whether this difference is large enough to conclude that there might be a distinction in mean life span based on race in the given population.
Difference in Means
In statistics, comparing the difference in means between two groups is common, especially when we want to understand if one group differs significantly from another. In our exercise, we are interested in knowing if there exists a statistically significant difference in mean life spans between whites and nonwhites in a specific county. To perform this analysis, we conduct a hypothesis test. Here:- The null hypothesis (\(H_0\)) posits that there is no difference in means, symbolically represented as: \[ H_0: \mu_w - \mu_{nw} = 0 \]- The alternative hypothesis (\(H_a\)) suggests that there is a difference: \[ H_a: \mu_w - \mu_{nw} eq 0 \]Where \(\mu_w\) and \(\mu_{nw}\) are the population means for whites and nonwhites, respectively.Once we calculate and compare the sample mean differences against what would be expected under the null hypothesis (considering the sample sizes and standard deviations), we can determine the probability of observing a difference as extreme as the one in our data. This probability is crucial to deciding whether to accept or reject the null hypothesis, and thus conclude if a true difference in means exists.

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Most popular questions from this chapter

Use the following information to answer the next ten exercises. indicate which of the following choices best identifies the hypothesis test. a. independent group means, population standard deviations and/or variances known b. independent group means, population standard deviations and/or variances unknown c. matched or paired samples d. single mean e. two proportions f. single proportion A powder diet is tested on 49 people, and a liquid diet is tested on 36 different people. The population standard deviations are two pounds and three pounds, respectively. Of interest is whether the liquid diet yields a higher mean weight loss than the powder diet.

Use the following information to answer the next twelve exercises. In the recent Census, three percent of the U.S. population reported being of two or more races. However, the percent varies tremendously from state to state. Suppose that two random surveys are conducted. In the first random survey, out of 1,000 North Dakotans, only nine people reported being of two or more races. In the second random survey, out of 500 Nevadans, 17 people reported being of two or more races. Conduct a hypothesis test to determine if the population percents are the same for the two states or if the percent for Nevada is statistically higher than for North Dakota. Calculate the test statistic.

Researchers interviewed street prostitutes in Canada and the United States. The mean age of the 100 Canadian prostitutes upon entering prostitution was 18 with a standard deviation of six. The mean age of the 130 United States prostitutes upon entering prostitution was 20 with a standard deviation of eight. Is the mean age of entering prostitution in Canada lower than the mean age in the United States? Test at a 1% significance level.

Use the following information to answer the next twelve exercises. In the recent Census, three percent of the U.S. population reported being of two or more races. However, the percent varies tremendously from state to state. Suppose that two random surveys are conducted. In the first random survey, out of 1,000 North Dakotans, only nine people reported being of two or more races. In the second random survey, out of 500 Nevadans, 17 people reported being of two or more races. Conduct a hypothesis test to determine if the population percents are the same for the two states or if the percent for Nevada is statistically higher than for North Dakota. Which distribution (normal or Student's t) would you use for this hypothesis test?

Suppose a statistics instructor believes that there is no significant difference between the mean class scores of statistics day students on Exam 2 and statistics night students on Exam 2. She takes random samples from each of the populations. The mean and standard deviation for 35 statistics day students were 75.86 and 16.91, respectively. The mean and standard deviation for 37 statistics night students were 75.41 and 19.73. The 鈥渄ay鈥 subscript refers to the statistics day students. The 鈥渘ight鈥 subscript refers to the statistics night students. An appropriate alternative hypothesis for the hypothesis test is: a. \(\mu_{\text { day }}>\mu_{\text { night }}\) b. \(\mu_{\text { day }}<\mu_{\text { night }}\) c. \(\mu\) day \(=\mu_{\text { night }}\) d. \(\mu_{\text { day }} \neq \mu_{\text { night }}\)

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