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Prior to a special advertising campaign, \(23 \%\) of all adults recognized a particular company's logo. At the close of the campaign the marketing department commissioned a survey in which 311 of 1,200 randomly selected adults recognized the logo. Determine, at the \(1 \%\) level of significance, whether the data provide sufficient evidence to conclude that more than \(23 \%\) of all adults now recognize the company's logo.

Short Answer

Expert verified
Yes, more than 23% of all adults now recognize the logo, based on the test.

Step by step solution

01

Define the Null and Alternative Hypotheses

The null hypothesis, denoted as \( H_0 \), is that the proportion of adults who recognize the company's logo is still 23%, or \( p = 0.23 \). The alternative hypothesis, \( H_1 \), is that the proportion has increased, meaning \( p > 0.23 \). This sets the framework for conducting a one-tailed hypothesis test.
02

Collect the Sample Data

The sample data given is that 311 out of 1,200 adults recognized the logo. We calculate the sample proportion \( \hat{p} \) as \( \hat{p} = \frac{311}{1200} = 0.2592 \).
03

Calculate the Test Statistic

Use the formula for the z-test statistic for proportions: \[ z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}} \] where \( \hat{p} = 0.2592 \), \( p_0 = 0.23 \), and \( n = 1200 \). Substituting these in gives: \[ z = \frac{0.2592 - 0.23}{\sqrt{\frac{0.23(1-0.23)}{1200}}} \].
04

Perform the Calculations

First, calculate the standard error: \[ \sqrt{\frac{0.23(1-0.23)}{1200}} = \sqrt{\frac{0.1771}{1200}} \approx 0.012\].Then, compute the z-test statistic: \[ z = \frac{0.2592 - 0.23}{0.012} \approx 2.433\].
05

Determine the Critical Value and Compare

For a 1% level of significance for a one-tailed test, the critical z-value is approximately 2.33. Since the calculated z-value of 2.433 is greater than 2.33, we reject the null hypothesis.
06

Conclusion

Since the z-statistic exceeds the critical value, there is sufficient evidence, at the 1% level of significance, to conclude that more than 23% of all adults now recognize the company's logo.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Test for Proportions
The z-test for proportions is a statistical test used to determine if there is a significant difference between two proportions. In this case, it helps assess whether the proportion of adults recognizing a company's logo has increased after a campaign. This test is especially useful when dealing with large samples.
To conduct the z-test for proportions, the following steps are involved:
  • Identify the null and alternative hypotheses: Decide what you are testing. Usually, the null hypothesis (H_0) is that there is no effect or no difference, while the alternative (H_1) suggests a change or effect.

  • Calculate the sample proportion: This is done by dividing the number of favorable outcomes by the total number of trials. In our example, 311 people recognized the logo out of 1200 surveyed. So, the sample proportion (\hat{p}) is 0.2592.

  • Compute the z-statistic: Utilize the formula \[ z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}} \], where \( p_0 \) is the null hypothesis proportion, and \( n \) is the sample size.
This statistic tells us how many standard deviations our sample proportion is from the assumed proportion. Depending on your z value and the level of significance, you'll decide whether to reject the null hypothesis.
Null and Alternative Hypotheses
Null and alternative hypotheses are the foundation for conducting hypothesis testing. A null hypothesis (H_0) is a statement that there is no effect or no difference in what you are testing. It's something to test against.
For the logo recognition example, the null hypothesis states that 23% of all adults recognize the logo, or \( p = 0.23 \).
The alternative hypothesis (H_1) is what we want to prove or test for. It suggests there is an effect or a difference. In this situation, it states that more than 23% of adults recognize the logo, \( p > 0.23 \).
  • One-tailed vs. Two-tailed Tests: A one-tailed test checks for an increase or decrease only in one direction, while a two-tailed test assesses for changes in both directions. Here, we're conducting a one-tailed test to see if there's an increase.

  • Rejection of H_0: If our test results are significant, meaning the calculated statistic falls beyond a critical value, we reject the null hypothesis in favor of the alternative.
Simply put, the null hypothesis serves as the default claim, while the alternative hypothesis stands as the new claim that needs evidence to be proven.
Level of Significance
The level of significance defines the threshold for determining whether a hypothesis test result is statistically significant or not. It is denoted by \( \alpha \), and commonly set at values like 0.05, 0.01, or 0.10.
In the context of our example, a 1% level of significance means there's only a 1% risk of rejecting the null hypothesis when it is actually true.
This level implies a high degree of confidence in the result, as you are allowing for a very strict rejection criterion.
  • Critical Value: For a one-tailed test at a 1% level of significance, the critical z-value is approximately 2.33. This is the cut-off point that determines whether you reject H_0.

  • Interpretation: If your computed z-statistic exceeds this critical value, you consider your findings significant, indicating enough evidence to support the alternative hypothesis.
Thus, the level of significance is key in deciding whether to accept or reject the null hypothesis, based on the critical region determined by \( \alpha \). It provides a margin for error that you're willing to accept in your findings.

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Most popular questions from this chapter

An automobile manufacturer recommends oil change intervals of 3,000 miles. To compare actual intervals to the recommendation, the company randomly samples records of 50 oil changes at service facilities and obtains sample mean 3,752 miles with sample standard deviation 638 miles. Determine whether the data provide sufficient evidence, at the \(5 \%\) level of significance, that the population mean interval between oil changes exceeds 3,000 miles.

Describe the two types of errors that can be made in a test of hypotheses.

A calculator has a built-in algorithm for generating a random number according to the standard normal distribution. Twenty-five numbers thus generated have mean 0.15 and sample standard deviation 0.94 . Test the null hypothesis that the mean of all numbers so generated is 0 versus the alternative that it is different from 0 , at the \(20 \%\) level of significance. Assume that the numbers do follow a normal distribution.

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Authors of a computer algebra system wish to compare the speed of a new computational algorithm to the currently implemented algorithm. They apply the new algorithm to 50 standard problems; it averages 8.16 seconds with standard deviation 0.17 second. The current algorithm averages 8.21 seconds on such problems. Test, at the \(1 \%\) level of significance, the alternative hypothesis that the new algorithm has a lower average time than the current algorithm.

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