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A random sample is drawn from a normally distributed population of unknown standard deviation. Construct a \(99 \%\) confidence interval for the population mean based on the information given. a. \(n=18, \bar{x}-386, s=24\) b. \(n=7, \bar{x}-386, s=24\)

Short Answer

Expert verified
a. [369.62, 402.38], b. [349.41, 422.59]

Step by step solution

01

Determine the Right Formula

Since the population standard deviation is unknown, we use the t-distribution. The formula for a confidence interval based on the t-distribution is \( \bar{x} \pm t_{\alpha / 2} \left( \frac{s}{\sqrt{n}} \right) \), where \( \bar{x} \) is the sample mean, \( s \) is the sample standard deviation, \( n \) is the sample size, and \( t_{\alpha/2} \) is the t-score corresponding to \( \alpha/2 \) for a given confidence level and degrees of freedom \( n-1 \).
02

Calculate the t-Score for Part a

For a 99% confidence interval and \( n = 18 \), the degrees of freedom is \( 17 \). From the t-distribution table, \( t_{0.005, 17} \approx 2.898 \).
03

Calculate the Margin of Error for Part a

Calculate the margin of error using the formula \( t_{0.005, 17} \times \frac{s}{\sqrt{n}} \). Thus, it is \( 2.898 \times \frac{24}{\sqrt{18}} \approx 16.38 \).
04

Construct the Confidence Interval for Part a

Using the formula \( \bar{x} \pm \text{Margin of Error} \), we have \( 386 \pm 16.38 \). Therefore, the confidence interval is approximately \([369.62, 402.38]\).
05

Calculate the t-Score for Part b

For a 99% confidence interval and \( n = 7 \), the degrees of freedom is \( 6 \). From the t-distribution table, \( t_{0.005, 6} \approx 4.032 \).
06

Calculate the Margin of Error for Part b

Calculate the margin of error with \( t_{0.005, 6} \times \frac{s}{\sqrt{n}} \). Thus, it is \( 4.032 \times \frac{24}{\sqrt{7}} \approx 36.59 \).
07

Construct the Confidence Interval for Part b

Using the formula \( \bar{x} \pm \text{Margin of Error} \), we have \( 386 \pm 36.59 \). Therefore, the confidence interval is approximately \([349.41, 422.59]\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

t-distribution
When constructing a confidence interval for a population mean and the population standard deviation is unknown, the t-distribution is used. This is because it accounts for additional uncertainty when estimating the population standard deviation from a sample. Unlike the normal distribution, the t-distribution is wider and has heavier tails, which means there's a greater chance of observing values far from the mean. This characteristic becomes especially important with smaller sample sizes.
The shape of the t-distribution depends on the "degrees of freedom," which is related to the sample size. As the sample size increases, the t-distribution becomes more like the normal distribution. This is why for larger samples, you might find the estimates quite similar when using either distribution.
The use of the t-distribution in this context ensures that the confidence interval is reliable despite the added uncertainty from a small sample.
sample mean
The sample mean, denoted by \( \bar{x} \), is a critical component in constructing a confidence interval. It serves as a point estimate of the population mean. The sample mean is calculated by summing all the observed values in the sample and dividing by the number of observations. This simple measure provides a central value around which the confidence interval is constructed.
In the context of constructing a confidence interval, the sample mean is the center of the interval. It helps to understand that the sample mean is just an estimate and is likely close to the true population mean but rarely exactly equal. Therefore, the confidence interval provides a range of values within which the actual population mean is expected to lie with a certain level of confidence, such as 99% in this case.
sample standard deviation
The sample standard deviation, represented as \( s \), measures the amount of variation or dispersion in a sample. It is critical when constructing confidence intervals since it determines the variability of the sample mean. The formula used for the sample standard deviation is:\[ s = \sqrt{ \frac{1}{n-1} \sum_{i=1}^{n} (x_i - \bar{x})^2} \]where \( x_i \) represents each data point in the sample, \( \bar{x} \) is the sample mean, and \( n \) is the sample size.
The sample standard deviation is used to calculate the margin of error in the confidence interval formula. A larger standard deviation indicates more dispersion in the data, resulting in a wider confidence interval. Conversely, a smaller standard deviation suggests less variability and leads to a narrower confidence interval.
degrees of freedom
Degrees of freedom, often abbreviated as \( df \) or \( u \), is a key concept when using the t-distribution for statistical estimates. In the scenario of constructing a confidence interval for a mean, the degrees of freedom are calculated as the sample size minus one, \( n - 1 \). This is because one parameter (the sample mean) is estimated from the data.
Degrees of freedom account for the number of values in the final calculation that are free to vary. They influence the shape of the t-distribution, especially affecting its tails. Fewer degrees of freedom result in wider tails, indicating more variability and a wider confidence interval. As the degrees of freedom increase, the t-distribution resembles the normal distribution more closely.

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Most popular questions from this chapter

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