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91Ó°ÊÓ

City planners wish to estimate the mean lifetime of the most commonly planted trees in urban settings. A sample of 16 recently felled trees yielded mean age 32.7 years with standard deviation 3.1 years. Assuming the lifetimes of all such trees are normally distributed, construct a \(99.8 \%\) confidence interval for the mean lifetime of all such trees.

Short Answer

Expert verified
The 99.8% confidence interval is \([29.805, 35.595]\).

Step by step solution

01

Understand the Problem

The problem asks us to calculate the confidence interval for the mean lifetime of trees given a sample. We are given the sample mean, the standard deviation, sample size and need to determine the confidence interval at a 99.8% level.
02

Identify the Formula

We will use the formula for the confidence interval of the mean: \( \bar{x} \pm t \frac{s}{\sqrt{n}} \), where \( \bar{x} \) is the sample mean, \( s \) is the sample standard deviation, \( n \) is the sample size, and \( t \) is the t-score corresponding to the desired confidence level.
03

Calculate the T-score

For a confidence level of 99.8% with 15 degrees of freedom (since \( n - 1 = 16 - 1 = 15 \)), we look up the t-distribution table and find that the t-score is approximately 3.733.
04

Compute the Margin of Error

Calculate the margin of error with \( t \frac{s}{\sqrt{n}} = 3.733 \times \frac{3.1}{\sqrt{16}} = 2.895 \).
05

Determine the Confidence Interval

Use the margin of error to calculate the confidence interval: \( 32.7 \pm 2.895 \), leading to the interval \([29.805, 35.595]\).
06

Interpret the Results

The 99.8% confidence interval for the mean lifetime of such trees is between 29.805 and 35.595 years.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

T-distribution
The t-distribution is a critical concept in statistics, especially when dealing with smaller sample sizes. Unlike the normal distribution, the t-distribution is more spread out or heavier in the tails. This characteristic makes it the go-to distribution when estimating population parameters with smaller samples (generally less than 30).
When constructing a confidence interval for a population mean using a t-distribution, we use a t-score instead of a z-score. This adjustment accounts for the extra uncertainty that comes from having a smaller sample.
  • The t-distribution is symmetric and bell-shaped, like the normal distribution.
  • As the sample size increases, the t-distribution approaches the normal distribution.
  • It is defined by "degrees of freedom", calculated as the sample size minus one.
In our exercise, with a sample size of 16, we use the t-distribution with 15 degrees of freedom to find the appropriate t-score for a 99.8% confidence interval.
Sample Size
Sample size plays a crucial role in statistics as it affects the precision of our estimates. A larger sample size gives a more accurate reflection of the population characteristic we aim to measure.
The sample size in confidence interval calculations dictates the degrees of freedom and thus influences the t-score. Typically, with larger sample sizes, we tend to use the z-distribution as the sample's estimate becomes more accurate. However, for smaller sample sizes below 30, like in our exercise, the t-distribution is used.
  • A larger sample size reduces the margin of error, leading to narrower confidence intervals.
  • Smaller sample sizes, as seen in the exercise (n=16), require the use of t-scores which reflect higher uncertainty in estimates.
  • Choosing an appropriate sample size helps balance resource constraints while obtaining reliable estimates.
Understanding the impact of sample size is key to effective statistical analysis and confident decision-making.
Margin of Error
The margin of error is a statistic that expresses the amount of random sampling error in a survey's results. It tells us how much the estimate from a sample may deviate from the true population value.
In constructing confidence intervals, the margin of error is determined by multiplying the t-score by the standard error of the sample mean, which is the sample standard deviation divided by the square root of the sample size.
  • A larger margin of error means less precision in estimating the true population parameter.
  • In our scenario, the margin of error calculates to about 2.895 years, meaning the true mean is likely within 2.895 years on either side of the sample mean of 32.7 years.
  • Factors such as confidence level, sample size, and data variability influence the margin of error.
Understanding the margin of error provides insight into the reliability and accuracy of statistical inferences.
Mean Lifetime Estimation
Estimating the mean lifetime of objects (like trees, in our case) is a common goal in research projects and policy planning. It involves determining the average lifespan and using statistical methods to provide a reasonable confidence range for this parameter.
In our example, the mean lifetime of the sampled trees was found to be 32.7 years. With the 99.8% confidence interval calculated, planners can be 99.8% sure that the true average lifetime of all similar trees lies between 29.805 and 35.595 years.
  • Mean lifetime estimation helps in resource planning and management.
  • It provides a basis for assessing the longevity and environmental impact of planting these trees.
  • The confidence interval allows decision-makers to account for variability and make well-informed plans.
Understanding mean lifetime estimation ensures effective strategy development in urban planning.

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Most popular questions from this chapter

Lines 537 through 1106 in Large Data Set 11 is a sample of 570 real estate sales in a certain region in 2010 . Those that were foreclosure sales are identified with a 1 in the second column. a. Use these data to construct a point estimate \(\hat{p}\) of the proportion \(p\) of all real estate sales in this region in 2010 that were foreclosure sales. b. Use these data to construct a \(90 \%\) confidence for \(p\).

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