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Let \(z\) denote a random variable that has a standard normal distribution. Determine each of the following probabilities: a. \(P(z<2.36)\) b. \(\quad P(z \leq 2.36)\) c. \(P(z<-1.23)\) d. \(\quad P(1.142)\) g. \(\quad P(z \geq-3.38)\) h. \(\quad P(z<4.98)\)

Short Answer

Expert verified
a. 0.9909, b. 0.9909, c. 0.1093, d. 0.1267, e. 0.0706, f. 0.0228, g. 0.9997, h. 1

Step by step solution

01

Understanding Z-Scores

Z-scores are a measure of how many standard deviations an element is from the mean. The point here is to calculate the probability that the random variable z is below or above a certain value, or between two values. This is done by calculating the area under the curve of the standard normal distribution.
02

Using Standard Normal Distribution Table

We can get the probabilities directly through a standard normal distribution table. The z-score is the row value, the second decimal point is the column value.
03

Calculation of the Probabilities

a. For \(P(z<2.36)\) look up 2.36 in the z-table which yields 0.9909, b. For \(P(z \leq 2.36)\), it's the same value as a, when z is less than or equal to certain value, which is 0.9909, c. For \(P(z<-1.23)\), look up 1.23 in the z-table which gives 0.8907. Since it's asking for the left tail (less than -1.23), subtract the value from 1, i.e., \(1-0.8907 = 0.1093\), d. For \(P(1.142)\), look up 2 in the table which yields 0.9772. Since it's asking for the right tail (greater than 2), subtract the value from 1, i.e., \(1 - 0.9772 = 0.0228\), g. For \(P(z \geq-3.38)\), take the absolute value of -3.38 which equals 3.38 and look it up in the table giving 0.9997. Since it's greater than, we don't need to subtract from 1, so it's 0.9997, h. For \(P(z<4.98)\), the table only goes until 3.99. But past 3, the probability is so close to 1 that it is standard to just say the probability is 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-scores
Z-scores are a standardized measure that tells us how far away a data point is from the mean of a distribution in terms of standard deviations. They help to compare different data points within the same distribution.
When you have a Z-score:
  • A positive Z-score means the data point is above the mean.
  • A negative Z-score indicates the data point is below the mean.
  • A Z-score of 0 signifies the data point is at the mean.
You can calculate a Z-score using the formula:\[ Z = \frac{(X - \mu)}{\sigma} \]where:
  • \(X\) is the data point,
  • \(\mu\) is the mean of the distribution,
  • \(\sigma\) is the standard deviation.
This measurement makes it easy to determine probabilities associated with different scores, using the standard normal distribution.
Probability Calculation
Finding probabilities for Z-scores involves determining the area under the standard normal distribution. This distribution is a bell-shaped curve where:
  • The mean is 0, and
  • The standard deviation is 1.
To calculate probabilities, follow these general steps:
1. **Identify the Z-score**: Determine the Z-score you are interested in.2. **Look up the Z-score in a table**: Use a standard normal distribution table, or Z-table, to find the probability.3. **Understand the context**: Depending on whether you want less than, greater than, or between probabilities, the calculations might slightly differ. For instance:
  • **Less than (\(P(z < X)\))**: This is the value found directly from the Z-table.
  • **Greater than (\(P(z > X)\))**: Subtract the Z-table value from 1 (\(1 - ext{Z-table value}\)).
  • **Between two scores (\(P(a < z < b)\))**: Subtract the Z-table value of the lower Z-score from the Z-table value of the higher Z-score.
These methods enable us to understand the likelihood of a random variable falling within a specified range.
Normal Distribution Table
The normal distribution table, commonly referred to as the Z-table, provides probabilities for different Z-scores in a standard normal distribution. This valuable tool is essential for solving problems involving probabilities for many statistical analyses.
Here's how it works:
  • Rows generally represent the whole part and first decimal of the Z-score.
  • Columns represent the second decimal of the Z-score.
To use the table effectively: 1. **Locate your Z-score**: Find the row in the table that corresponds to the Z-score's whole number and the first decimal. For example, a Z-score of 2.36 would be in the row for 2.3. 2. **Move to the correct column**: Then, look in the column that corresponds to the second decimal. For 2.36, you'll check the column for 0.06. 3. **Read probability**: The intersection gives the cumulative probability for the Z-score, indicating the area under the curve to the left of that Z-score.
With these steps, anyone can efficiently find the probability associated with any given Z-score, facilitating deeper insights into data analysis.

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Most popular questions from this chapter

An author has written a book and submitted it to a publisher. The publisher offers to print the book and gives the author the choice between a flat payment of \(\$ 10,000\) and a royalty plan. Under the royalty plan the author would receive \(\$ 1\) for each copy of the book sold. The author thinks that the following table gives the probability distribution of the variable \(x=\) the number of books that will be sold: \(\begin{array}{lrrrr}x & 1000 & 5000 & 10,000 & 20,000 \\ p(x) & .05 & .30 & .40 & .25\end{array}\) Which payment plan should the author choose? Why?

Suppose that the distribution of typing speed in words per minute (wpm) for experienced typists using a new type of split keyboard can be approximated by a normal curve with mean \(60 \mathrm{wpm}\) and standard deviation 15 wpm ("The Effects of Split Keyboard Geometry on Upper body Postures," Ergonomics [2009]: 104-1I1). a. What is the probability that a randomly selected typist's speed is at most 60 wpm? less than 60 wpm? b. What is the probability that a randomly selected typist's speed is between 45 and 90 wpm? c. Would you be surprised to find a typist in this population whose speed exceeded 105 wpm? d. Suppose that two typists are independently selected. What is the probability that both their typing speeds exceed 75 wpm? e. Suppose that special training is to be made available to the slowest \(20 \%\) of the typists. What typing speeds would qualify individuals for this training?

Sophie is a dog that loves to play catch. Unfortunately, she isn't very good, and the probability that she catches a ball is only \(.1\). Let \(x\) be the number of tosses required until Sophie catches a ball. a. Does \(x\) have a binomial or a geometric distribution? b. What is the probability that it will take exactly two tosses for Sophie to catch a ball? c. What is the probability that more than three tosses will be required?

A multiple-choice exam consists of 50 questions. Each question has five choices, of which only one is correct. Suppose that the total score on the exam is computed as $$ y=x_{1}-\frac{1}{4} x_{2} $$ where \(x_{1}=\) number of correct responses and \(x_{2}=\) number of incorrect responses. (Calculating a total score by subtracting a term based on the number of incorrect responses is known as a correction for guessing and is designed to discourage test takers from choosing answers at random.) a, It can be shown that if a totally unprepared student answers all 50 questions by just selecting one of the five answers at random, then \(\mu_{x_{1}}=10\) and \(\mu_{x_{2}}=40\). What is the mean value of the total score, \(y\) ? Does this surprise you? Explain. b. Explain why it is unreasonable to use the formulas given in this section to compute the variance or standard deviation of \(y\).

Let \(z\) denote a random variable having a normal distribution with \(\mu=0\) and \(\sigma=1 .\) Determine each of the following probabilities: a. \(P(z<0.10)\) b. \(P(z<-0.10)\) c. \(P(0.40-1.25)\) g. \(P(z<-1.50\) or \(z>2.50\) )

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