/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 66 Let \(z\) denote a random variab... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(z\) denote a random variable having a normal distribution with \(\mu=0\) and \(\sigma=1 .\) Determine each of the following probabilities: a. \(P(z<0.10)\) b. \(P(z<-0.10)\) c. \(P(0.40-1.25)\) g. \(P(z<-1.50\) or \(z>2.50\) )

Short Answer

Expert verified
The exact probabilities will depend on the exact values provided by the normal distribution table used. They should approximately be: \n a. 0.5398 for \(P(z<0.10)\), \n b. 0.4602 for \(P(z<-0.10)\), \n c. 0.1554 for \(P(0.40-1.25)\), and \n g. 0.1335 for \(P(z<-1.50\) or \(z>2.50)\).

Step by step solution

01

Understand the z-score

A z-score tells you how many standard deviations away a data point is from the mean. In this problem, the given scores are already z-scores, as they are expressed in terms of how many standard deviations they fall above or below the mean (0). The standard deviation here is one, and scores are exactly the z-values you need to use.
02

Use Standard Normal Distribution Table

Using a Standard Normal Distribution Table (or a calculator with this capability), probabilities related to the provided z-scores are as follows: \n\n a. \(P(z<0.10)\): Look up the value corresponding to 0.10 in the z-table. This is the desired probability. \n\n b. \(P(z<-0.10)\): This is the same as subtracting \(P(z<0.10)\) from 0.5 (because the total probability below the mean, \(z=0\), is 0.5). \n\n c. \(P(0.40-1.25)\): This is the same as 1 minus the probability that \(z<-1.25\). \n\n g. \(P(z<-1.50\) or \(z>2.50\)): This equals the sum of \(P(z<-1.50)\) and \(P(z>2.50)\).
03

Find actual probabilities

Substitute the step 2 results into a standard normal distribution table or in a calculator with standard distribution capability to calculate the actual probabilities

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Z-Score
A z-score is a measure that describes a data point's position relative to the mean of a set of data, measured in terms of standard deviations. In simpler terms, it tells us how far and in which direction something deviates from the mean:
  • If a z-score is 0, it indicates that the data point is exactly at the mean.
  • A positive z-score means the data point is above the mean.
  • A negative z-score means the data point is below the mean.
In a standard normal distribution, the mean is 0 and the standard deviation is 1, which means the z-score represents how many "1 standard deviation steps" you are away from the mean. Understanding z-scores allows us to easily compare different data points from different normal distributions. For example, a z-score of 1.25 means a data point is 1.25 standard deviations above the mean. This foundational concept makes z-values essential for interpreting statistical data. When working with z-scores, it simplifies various statistical calculations, especially when you have large data sets.
Probability Calculation with Z-Scores
Probability calculation with z-scores relates to finding the area under the curve of the normal distribution, which tells us the likelihood of a data point falling within a particular range. This is important when assessing real-world data, as it allows predictions and decisions to be made based on the probability. When you know the z-score, you can determine the probability that a value will occur below, above, or between specific z-scores. For instance:
  • To find the probability of a score less than a specific z-value, look it up in a standard normal distribution table or use software tools.
  • To find the probability between two z-scores, calculate the difference between their cumulative probabilities.
  • If looking for the probability of a score greater than a specific z-value, subtract the cumulative probability of that z-value from 1.
By using z-scores in these ways, you can effectively turn raw scores into probabilities, making data meaningful and accessible for analysis.
The Role of the Normal Distribution Table
The normal distribution table, sometimes referred to also as a z-table, is a mathematical table that shows the cumulative probability values for a standard normal distribution. This table helps you quickly find the probability that a random variable is less than or equal to a certain z-score. The symmetry of the normal distribution means you only need to calculate half of the distribution and can deduce the rest by symmetry. To use the table:
  • Find the row that corresponds to the first decimal place of your z-score (like z = 0.1 would be row 0.1).
  • Then, follow the column that aligns with the second decimal point of your z-score (like z = 0.12 would be in the second column across from row 0.1).
The table value shows the probability of a z-score being less than or equal to that value, covering the area under the curve from the left side up to that point. If you need the probability for a range or above a z-score, you may need some additional calculations, as discussed in previous sections. In essence, the normal distribution table is a crucial tool for translating z-scores into easily understandable probability metrics, enabling you to harness these probabilities for effective statistical analysis.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose that the probability is \(.1\) that any given citrus tree will show measurable damage when the temperature falls to \(30^{\circ} \mathrm{F}\). If the temperature does drop to \(30^{\circ} \mathrm{F}\), what is the expected number of citrus trees showing damage in orchards of 2000 trees? What is the standard deviation of the number of trees that show damage?

State whether each of the following random variables is discrete or continuous: a. The number of defective tires on a car b. The body temperature of a hospital patient c. The number of pages in a book d. The number of draws (with replacement) from a deck of cards until a heart is selected e. The lifetime of a lightbulb

A company that manufactures mufflers for cars offers a lifetime warranty on its products, provided that ownership of the car does not change. Suppose that only \(20 \%\) of its mufflers are replaced under this warranty. a. In a random sample of 400 purchases, what is the approximate probability that between 75 and 100 (inclusive) mufflers are replaced under warranty? b. Among 400 randomly selected purchases, what is the probability that at most 70 mufflers are ultimately replaced under warranty? c. If you were told that fewer than 50 among 400 randomly selected purchases were ever replaced under warranty, would you question the \(20 \%\) figure? Explain.

According to the paper "Commuters' Exposure to Particulate Matter and Carbon Monoxide in Hanoi. Vietnam" (Transportation Research [2008]: 206-211), the carbon monoxide exposure of someone riding a motorbike for \(5 \mathrm{~km}\) on a highway in Hanoi is approximately normally distributed with a mean of \(18.6\) ppm. Suppose that the standard deviation of carbon monoxide exposure is \(5.7\) ppm. Approximately what proportion of those who ride a motorbike for \(5 \mathrm{~km}\) on a Hanoi highway will experience a carbon monoxide exposure of more than 20 ppm? More than 25 ppm?

Let \(y\) denote the number of broken eggs in a randomly selected carton of one dozen eggs. Suppose that the probability distribution of \(y\) is as follows: \(\begin{array}{cccccc}y & 0 & 1 & 2 & 3 & 4 \\ p(y) & .65 & .20 & .10 & .04 & ?\end{array}\) a. Only \(y\) values of \(0,1,2,3\), and 4 have positive probabilities. What is \(p(4)\) ? b. How would you interpret \(p(1)=.20\) ? c. Calculate \(P(y \leq 2)\), the probability that the carton contains at most two broken eggs, and interpret this probability. d. Calculate \(P(y<2)\), the probability that the carton contains fewer than two broken eggs. Why is this smaller than the probability in Part (c)? e. What is the probability that the carton contains exactly 10 unbroken eggs? f. What is the probability that at least 10 eggs are unbroken?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.