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Suppose that the distribution of typing speed in words per minute (wpm) for experienced typists using a new type of split keyboard can be approximated by a normal curve with mean \(60 \mathrm{wpm}\) and standard deviation 15 wpm ("The Effects of Split Keyboard Geometry on Upper body Postures," Ergonomics [2009]: 104-1I1). a. What is the probability that a randomly selected typist's speed is at most 60 wpm? less than 60 wpm? b. What is the probability that a randomly selected typist's speed is between 45 and 90 wpm? c. Would you be surprised to find a typist in this population whose speed exceeded 105 wpm? d. Suppose that two typists are independently selected. What is the probability that both their typing speeds exceed 75 wpm? e. Suppose that special training is to be made available to the slowest \(20 \%\) of the typists. What typing speeds would qualify individuals for this training?

Short Answer

Expert verified
a. The probability that a typist's speed is at most or less than 60 wpm is 50%. b. The probability that a typist's speed is between 45 and 90 wpm is 81.85%. c. The probability that a typist's speed exceeding 105 wpm is 0.13%, so one would be surprised to find such a typist. d. The probability that both typists' speed exceeds 75 wpm is approximately 2.52%. e. Typing speeds below 47 wpm would qualify individuals for the special training.

Step by step solution

01

Calculate the Probability for Typist's Speed is at most 60 wpm

Since 60 wpm is equal to the mean, a randomly selected typist's speed being at most 60 wpm is equal to P(Z ≤ 0) = 0.5 or 50%. P(Z < 0) is also equal to 0.5 or 50%.
02

Calculate the Probability for Typist's Speed is between 45 and 90 wpm

First standardize these scores using the z-score formula, \( z = (x - \mu)/\sigma\). For 45, \( z = (45 - 60)/15 = -1 \) and for 90, \( z = (90 - 60)/15 = 2 \). Now, find the probabilities associated with these z-scores from a standard normal distribution table, \(P(-1 \leq Z \leq 2)\), or we need to find \(P(Z \leq 2) - P(Z \leq -1) = 0.9772 - 0.1587 = 0.8185 \) or 81.85%.
03

Discuss about Typist with Speed exceeding 105 wpm

Standardize 105 to z-score, \( z = (105 - 60)/15 = 3 \). From the standard normal distribution table, \( P(Z \leq 3) = 0.9987 \) or \~99.87%. \(P(Z > 3) = 1 - 0.9987 = 0.0013 \) or 0.13%. This means the probability that a typist from this population typing faster than 105 wpm is extremely small, so one would indeed be surprised to find such a typist.
04

Probability that both Typists typing speed exceeds 75 wpm

The speed of 75 wpm corresponds to \( z = (75 - 60)/15 = 1 \). The probability that a single typist types faster than 75 wpm is \( P(Z > 1) = 1 - P(Z \leq 1) = 1 - 0.8413 = 0.1587 \) or 15.87%. Since two typists are selected independently, the needed probability is \(0.1587 * 0.1587 = 0.0252 \) or \~2.52%.
05

Typing speeds qualifying individuals for the training

We need to find the typing speed that marks the cutoff for slowest 20% typists. We need to find the z-score associated with the 20th percentile in the standard normal distribution. From the tables, the z-score for 0.20 is approximately -0.8416. We then convert this to a typing speed using the formula: \( X = Z * \sigma + \mu = -0.8416 * 15 + 60 = 47.4 \approx 47 \) wpm. Therefore, typing speeds of under 47 wpm would qualify for the training.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
Normal distribution is a fundamental concept in statistics that describes how data points are spread out. It is often called a "bell curve" because of its symmetrical, bell-shaped appearance when graphed.
This distribution is characterized by two parameters:
  • The mean (\(\mu\)) which determines the center of the curve.
  • The standard deviation (\(\sigma\)), which controls the width of the curve.
In a normal distribution, most of the data points tend to cluster around the mean, with fewer and fewer data points appearing as you move away from the mean in both directions. This property allows us to make statements about probabilities and how likely it is to find values within a certain range. For example, around 68% of data falls within one standard deviation of the mean in a normal distribution.
Z-Score
A z-score is a statistical measurement that describes a value's relationship to the mean of a group of values. It is expressed in terms of standard deviations from the mean.
The formula to calculate a z-score is:
  • \(z = \frac{x - \mu}{\sigma}\)
where:
  • \(x\) is the value you want to convert.
  • \(\mu\) is the mean of the distribution.
  • \(\sigma\) is the standard deviation of the distribution.
A z-score indicates how many standard deviations an element is from the mean. A z-score of 0 indicates that the data point's score is identical to the mean. Positive z-scores indicate values above the mean, while negative z-scores indicate values below the mean. Z-scores are crucial in identifying outliers and understanding probabilities in a normal distribution.
Probability
Probability refers to the measure of the likelihood that an event will occur. It is always expressed as a number between 0 and 1, where 0 means the event is impossible, and 1 indicates certainty.
In the context of statistics and normal distribution, we often want to find the probability of a particular outcome or range of outcomes occurring. This is done using the standard normal distribution table (z-table), which helps us to find the probability that a statistic is less than or equal to a specific z-score.
The rules of probability can be intuitive:
  • The probability of any single event is the sum of the probabilities of all possible outcomes.
  • Non-overlapping events' probabilities will add up.
For instance, if you know the probability that a typist's speed is below a certain wpm, then the probability of it being above is simply the complement that adds up to 1.
Percentiles
Percentiles are a way of expressing statistics that tell us about the relative standing of a particular value within a dataset. If a score is in the 75th percentile, it means it is higher than 75% of the other scores in the dataset.
To find what percentile a specific value corresponds to, we use the z-score and refer to the standard normal distribution table to find the area to the left of that z-score. This area directly corresponds to the percentile.
The key points about percentiles:
  • They range from 0 to 100, representing the full distribution of data.
  • Percentiles help to understand how a particular value compares to the rest of the data.
When it comes to making decisions, like identifying the slowest typists for extra training, percentiles are very useful. By knowing the cutoff for the 20th percentile, you know which typists fall in the bottom 20% of speeds.

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Most popular questions from this chapter

Let \(z\) denote a random variable having a normal distribution with \(\mu=0\) and \(\sigma=1 .\) Determine each of the following probabilities: a. \(P(z<0.10)\) b. \(P(z<-0.10)\) c. \(P(0.40-1.25)\) g. \(P(z<-1.50\) or \(z>2.50\) )

Suppose that a computer manufacturer receives computer boards in lots of five. Two boards are selected from each lot for inspection. We can represent possible outcomes of the selection process by pairs. For example, the pair \((1,2)\) represents the selection of Boards 1 and 2 for inspection. a. List the 10 different possible outcomes. b. Suppose that Boards 1 and 2 are the only defective boards in a lot of five. Two boards are to be chosen at random. Define \(x\) to be the number of defective boards observed among those inspected. Find the probability distribution of \(x\).

A grocery store has an express line for customers purchasing at most five items. Let \(x\) be the number of items purchased by a randomly selected customer using this line. Give examples of two different assignments of probabilities such that the resulting distributions have the same mean but quite different standard deviations.

A machine that cuts corks for wine bottles operates in such a way that the distribution of the diameter of the corks produced is well approximated by a normal distribution with mean \(3 \mathrm{~cm}\) and standard deviation \(0.1 \mathrm{~cm}\). The specifications call for corks with diameters between \(2.9\) and \(3.1 \mathrm{~cm}\). A cork not meeting the specifications is considered defective. (A cork that is too small leaks and causes the wine to deteriorate; a cork that is too large doesn't fit in the bottle.) What proportion of corks produced by this machine are defective?

A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday's mail. In actuality, each one could arrive on Wednesday (W), Thursday (I), Friday (F), or Saturday (S). Suppose that the two magazines arrive independently of one another and that for each magazine \(P(\mathrm{~W})\) \(=.4, P(\mathrm{~T})=.3, P(\mathrm{~F})=.2\), and \(P(S)=.1 .\) Define a random variable \(y\) by \(y=\) the number of days beyond Wednesday that it takes for both magazines to arrive. For example, if the first magazine arrives on Friday and the second magazine arrives on Wednesday, then \(y=2\), whereas \(y=1\) if both magazines arrive on Thursday. Obtain the probability distribution of \(y\). (Hint: Draw a tree diagram with two generations of branches, the first labeled with arrival days for Magazine 1 and the second for Magazine 2.)

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