/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 To assemble a piece of furniture... [FREE SOLUTION] | 91Ó°ÊÓ

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To assemble a piece of furniture, a wood peg must be inserted into a predrilled hole. Suppose that the diameter of a randomly selected peg is a random variable with mean \(0.25\) inch and standard deviation \(0.006\) inch and that the diameter of a randomly selected hole is a random variable with mean \(0.253\) inch and standard deviation \(0.002\) inch. Let \(x_{1}=\) peg diameter, and let \(x_{2}=\) denote hole diameter. a. Why would the random variable \(y\), defined as \(y=\) \(x_{2}-x_{1}\), be of interest to the furniture manufacturer? b. What is the mean value of the random variable \(y\) ? c. Assuming that \(x_{1}\) and \(x_{2}\) are independent, what is the standard deviation of \(y\) ? d. Is it reasonable to think that \(x_{1}\) and \(x_{2}\) are independent? Explain. e. Based on your answers to Parts (b) and (c), do you think that finding a peg that is too big to fit in the predrilled hole would be a relatively common or a relatively rare occurrence? Explain.

Short Answer

Expert verified
a. \(y\) represents the fit between the peg and hole. b. The mean value of \(y\) is \(0.003\) inch. c. The standard deviation of \(y\) is \(0.0063\) inch, assuming \(x_{1}\) and \(x_{2}\) are independent. d. Yes, it's reasonable to think so. e. Finding a peg that is too big to fit in the hole would be a relatively rare occurrence based on the calculated mean and standard deviation.

Step by step solution

01

Understanding the Variables

This problem talks about two random variables \(x_{1}\) which represents the peg diameter and \(x_{2}\) which represents the hole diameter. The random variable \(y\) is defined as the difference between hole diameter and peg diameter, \(y=x_{2}-x_{1}\). This variable is of interest to the furniture manufacturer because it signifies the fit between the peg and the hole, a positive number means the peg fits the hole, whereas a negative number means the peg is too large.
02

Calculating the Mean Value of \(y\)

The mean of random variable \(y\) is the difference between the mean values of \(x_{2}\) and \(x_{1}\). Using the given values in the problem, the mean value of \(y\) is \(0.253 - 0.25 = 0.003\) inch.
03

Calculating the Standard Deviation of \(y\)

If \(x_{1}\) and \(x_{2}\) are independent random variables, the variance of the \(y\) is the sum of the variances of \(x_{1}\) and \(x_{2}\). Hence, the standard deviation of \(y\), \(σ_{y}\), is the square root of the sum of the squares of \(σ_{x_{1}}\) and \(σ_{x_{2}}\). So, \(σ_{y} = \sqrt{(0.006)^{2}+(0.002)^{2}} = 0.0063\) inch by Pythagoras' theorem.
04

Independence of \(x_{1}\) & \(x_{2}\)

It's reasonable to think that \(x_{1}\) and \(x_{2}\) are independent because the diameter of the peg, \(x_{1}\), would not affect the diameter of the hole, \(x_{2}\), and vice versa. These diameters are determined in manufacturing processes that are distinct from each other.
05

Comparing the Calculated Mean and Standard Deviation

The positive mean value and small standard deviation of the variable \(y\) suggest that it is a common occurrence that the peg fits into the hole properly. That means finding a peg that is too big for a hole would be a relatively rare occurrence. This is because a too large peg would result in a negative value for \(y\), but the expectation (mean) of \(y\) is positive with a small deviation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variables
In probability and statistics, a random variable is a variable whose values depend on outcomes of a random phenomenon. It can be thought of as a way of mapping outcomes of random processes to numerical quantities. In this context, the peg diameter is one such variable, denoted by \(x_{1}\), and the hole diameter is another, denoted by \(x_{2}\). Both are measured in inches and represent characteristics that will vary from peg to peg and hole to hole.
  • Random variables often have a mean (average) value which is an expectation of their possible values.
  • They also have a distribution which describes how values occur.
  • Understanding a random variable's variability is crucial in quality control, such as manufacturing pegs and holes.
In the furniture assembly example, focusing on \(y = x_{2} - x_{1}\) helps understand how well a peg fits into a hole, which is essential for the assembly process. A positive \(y\) indicates a fit, whereas a negative value suggests a misfit.
Variance and Standard Deviation
Variance and standard deviation provide measures of the spread or variability of a set of data points. For random variables, they offer insights into the expected variability of their outcomes. In the simple assembly example, we want to know the variability of the peg and hole sizes:
- **Variance** is the expectation of the squared deviation of a random variable from its mean. It is denoted as \( ext{Var}(x) \) and helps us understand the consistency of measurements.- **Standard Deviation** is the square root of variance, represented as \( ext{SD}(x) \) or \( \sigma \), and provides a more intuitive measure of dispersion by using the same unit as the data.
The variance of \(y\) combines those of \(x_{1}\) and \(x_{2}\) when they are independent, calculated as follows:\[\sigma_{y} = \sqrt{\sigma_{x_{1}}^{2} + \sigma_{x_{2}}^{2}} = 0.0063\text{ inch}.\]This indicates that while some variability exists, generally the pegs should fit the holes well, given the low standard deviation.
Statistical Independence
Statistical independence between two random variables means that the realization of one variable does not affect the realization of another. For example, the peg diameter \(x_{1}\) and hole diameter \(x_{2}\) can be considered statistically independent if their creation processes do not influence each other.
In the context of manufacturing, independence is reasonable because:
  • The peg and hole dimensions are likely managed in distinct processes.
  • Quality controls for pegs and holes are generally separate, especially in different production stages or equipment.
  • Independence simplifies calculations by allowing us to add variances to find the variance of the difference \(y\).
Understanding when two variables are statistically independent helps in correctly analyzing the combined variability, such as dealing with \(x_{1}\) and \(x_{2}\) as separate yet related factors influencing \(y\). When these processes are influenced independently, meaningful conclusions about product quality and fit can be drawn more confidently.

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