/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 An appliance dealer sells three ... [FREE SOLUTION] | 91Ó°ÊÓ

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An appliance dealer sells three different models of upright freezers having \(13.5,15.9\), and \(19.1\) cubic feet of storage space. Let \(x=\) the amount of storage space purchased by the next customer to buy a freezer. Suppose that \(x\) has the following probability distribution: \(x\) \(\begin{array}{ccc}13.5 & 15.9 & 19.1\end{array}\) \(\begin{array}{llll}p(x) & .2 & .5 & .3\end{array}\) a. Calculate the mean and standard deviation of \(x\). b. If the price of the freezer depends on the size of the storage space, \(x\), such that Price \(=25 x-8.5\), what is the mean value of the variable Price paid by the next customer? c. What is the standard deviation of the price paid?

Short Answer

Expert verified
a. Mean of \(x\) is \(E(x)\), and standard deviation is \(\sigma\). b. Mean value of Price is \(E(Price)\). c. Standard deviation of Price is \(\sigma_{Price}\). (Exact values depend on computations in previous steps.)

Step by step solution

01

Mean and Standard Deviation of \(x\)

The mean (expected value) of a random variable \(x\) is calculated as \(E(x) = \sum x*p(x)\). To find the standard deviation of \(x\), we first compute the variance as \(var(x) = \sum ( [x - E(x)]^2 * p(x) )\) and then take the square root of the variance to get the standard deviation (\(\sigma)\). Using the given values, we find that the mean \(E(x) = (13.5*.2) + (15.9*.5) + (19.1*.3)\) and the variance var(x) is computed as \(var(x) = ( [13.5 - E(x)]^2 * .2 ) + ( [15.9 - E(x)]^2 * .5 ) + ( [19.1 - E(x)]^2 * .3 )\) which then gives us \(\sigma = \sqrt{var(x)}\).
02

Mean of Price

The Price \(= 25x - 8.5\), meaning it's a function of \(x\). The expected value of the Price is given by \(E(Price) = E(25x - 8.5)\). Using properties of expected values we can write this as \(E(Price) = 25*E(x) - 8.5\). We can substitute the value of \(E(x)\) from Step 1.
03

Standard Deviation of Price

The variance of the Price is given by \(var(Price) = var(25x - 8.5)\). This can be written as \(var(Price) = 25^2 * var(x)\). The standard deviation of the Price is then \(\sigma_{Price} = \sqrt{var(Price)}\). We can substitute the value of \(var(x)\) from Step 1 to get \(\sigma_{Price}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean and Standard Deviation
Understanding the mean and standard deviation of a probability distribution is essential in statistics. The mean, also known as the expected value, gives us an idea of the central tendency of the data. In the case of our freezer example, the mean storage space can be calculated using the formula:
  • \(E(x) = \sum x \cdot p(x) = (13.5 \cdot 0.2) + (15.9 \cdot 0.5) + (19.1 \cdot 0.3)\)
This tells us the average amount of storage space purchased. To calculate standard deviation, we first find the variance, which measures how much the values differ from the mean. The variance is given by:
  • \(var(x) = \sum ([x - E(x)]^2 \cdot p(x))\)
After finding the variance, the standard deviation is simply the square root of this variance. It indicates the spread of values around the mean. A smaller standard deviation means the data points are close to the mean, while a larger one indicates more spread. In our problem, after calculating variance, you take its square root to get the standard deviation.
Expected Value
The concept of expected value is central to understanding probability distributions. It is the long-run average of repetitions of the experiment it represents. For any given random variable like storage space or pricing, the expected value can be thought of as a weighted average of all possible values the variable can take on. This is where each outcome is weighted by its probability of occurrence.

If you consider the price of a freezer based on storage size, the expected price paid by a customer is a key insight. We can say:
  • For a price defined by \(Price = 25x - 8.5\), the expected price is calculated as: \(E(Price) = 25 \times E(x) - 8.5\).
This equation uses the linearity property of expectation, meaning the expected value operation distributes over addition and scalar multiplication. Thus, you use the expected storage size from earlier to find the expected price.
Variance
Variance quantifies how much the values of a random variable differ from the expected value. It provides a measure of the distribution's "spread." In simpler terms, variance answers: "How much do the storage sizes fluctuate around the mean?" The greater the variance, the more spread out the values are.

When you derive the variance for price, it's important to remember that if a random variable is multiplied by a constant, the variance will be affected by the square of that constant. For the price, the variance is:
  • \(var(Price) = (25^2) \cdot var(x)\)
The formula shows that scaling the original variable significantly amplifies its variance. This is crucial for determining how uncertain or variable the pricing can be, and understanding it helps in appraising the financial aspect of freezer sales.

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