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The following data values are 2009 per capita expenditures on public libraries for each of the 50 U.S. states (from www.statemaster.com): \(\begin{array}{rrrrrrr}16.84 & 16.17 & 11.74 & 11.11 & 8.65 & 7.69 & 7.48 \\\ 7.03 & 6.20 & 6.20 & 5.95 & 5.72 & 5.61 & 5.47 \\ 5.43 & 5.33 & 4.84 & 4.63 & 4.59 & 4.58 & 3.92 \\ 3.81 & 3.75 & 3.74 & 3.67 & 3.40 & 3.35 & 3.29 \\ 3.18 & 3.16 & 2.91 & 2.78 & 2.61 & 2.58 & 2.45 \\ 2.30 & 2.19 & 2.06 & 1.78 & 1.54 & 1.31 & 1.26 \\ 1.20 & 1.19 & 1.09 & 0.70 & 0.66 & 0.54 & 0.49\end{array}\) a. Summarize this data set with a frequency distribution. Construct the corresponding histogram. b. Use the histogram in Part (a) to find approximate values of the following percentiles: i. 50 th iv. 90 th ii. \(\quad 70\) th v. 40 th iii. 10 th

Short Answer

Expert verified
This is a summary of the data set with a frequency distribution and constructed histogram. The approximate values of the 50th, 70th, 10th, 40th, and 90th percentiles have been calculated based on the histogram.

Step by step solution

01

Create Frequency Distribution

Organize the data into ascending or descending order. Then divide the data into groups or intervals and count how many data values fall into each group. The result is a frequency distribution table.
02

Construct the Histogram

Using the frequency distribution table, draw a bar for each group or interval. The height of the bar corresponds with the frequency of that group.
03

Calculate the Percentiles

Use the histogram to approximate the percentiles. A percentile is a measure indicating the value below which a given percentage of observations falls. For instance, the 50th percentile is the median value, meaning 50% of the data falls below this value.
04

Find approximate values

Find approximate values of the 50th, 10th, 40th, 70th, and 90th percentile. These approximations are based on the histogram. For instance, the data value on the x-axis that corresponds to the spot on the y-axis that is half the height of the histogram would be the approximate value for the 50th percentile.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frequency Distribution
When dealing with a large set of data, such as the per capita expenditures on public libraries across different states, the first step is often to organize this information in a way that makes it easier to analyze. A frequency distribution is a summary of the data that shows the number of occurrences of each value or range of values. It's like grouping the data to see how many times each expenditure amount occurs.

For example, if you have expenditures of \(2.00, \)2.50, and \(3.00, you might find that the expenditure of \)2.50 occurs most frequently. A frequency distribution would list these expenditures along with the number of times each one appears in your dataset. By creating a frequency distribution table, you can easily see patterns and understand the distribution of data within your dataset.

In constructing a frequency distribution for the given library expenditures, you would first need to organize the expenditures in ascending or descending order. Then, decide on a set range for each group (class intervals), such as expenditures from \(0-\)2, \(2-\)4, and so on. The grouping helps to simplify the complex data into manageable chunks and provides a clear picture of how expenditures are spread across different ranges.
Histogram Construction
Once you have a frequency distribution, the next step is to visualize the data in the form of a histogram. A histogram is a type of bar chart that represents the frequency distribution of a dataset. Each bar in a histogram corresponds to a frequency or count of data points within each range or interval you've defined in your frequency distribution.

The height of each bar reflects the number of states falling into each expenditure bracket. When constructing a histogram, you would draw a bar for each expenditure range, ensuring the heights accurately represent the frequency counts. This graphical representation makes it easy to see which expenditure ranges are most common and how they compare to others.

It's important not to confuse histograms with bar graphs; while they may look similar, histograms are used for continuous data where the bars connect to each other, indicating that the ranges of data are adjacent. In the example of public library expenditures, a histogram can quickly show you where the majority of states fall within the expenditure spectrum and identify any outliers or unusual patterns.
Percentile Calculation
Percentiles are measures that help to understand the relative position of a data value within a dataset. The nth percentile is the value below which n percent of the data lies. For example, if you're looking for the 50th percentile, also known as the median, you're finding the point at which 50% of the data is lower and 50% is higher.

To calculate percentiles, you don't always need the exact data points, as approximations can be obtained from a histogram. This involves looking at the accumulated frequencies and determining where the nth percentile falls within the range of data. Let's say you want to find the 70th percentile. If the histogram shows that 70% of the bars (or the cumulative area up to a certain point) accounts for a certain expenditure range, the value corresponding to the end of that range is approximately the 70th percentile.

Calculating these percentiles gives you significant markers of the distribution, and in analyzing public library expenditures, it can reveal not just the average spending, but also how the values are spread towards the higher or lower end of the scale.
Data Analysis in Statistics
Data analysis in statistics involves collecting, processing, and interpreting data to discover patterns and trends, make decisions, and communicate findings. In the context of per capita expenditures on public libraries, statistical analysis helps to quantify the level of investment in library services across different states.

After constructing a frequency distribution and visualizing it via a histogram, we can apply various statistical tools to further analyze the data, such as calculating the mean, median, mode, and various percentiles. These measures provide insight into the central tendency and variation of the data. Advanced analysis might include hypothesis testing or regression analysis to predict future trends.

Data analysis not only helps in understanding the past and current state of affairs but also aids in making informed decisions for the future. For policymakers and stakeholders in the public library sector, a thorough data analysis can guide resource allocation, strategic planning, and performance measurement initiatives to enhance the provision of library services.

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Most popular questions from this chapter

The following data are cost (in cents) per ounce for nine different brands of sliced Swiss cheese (www .consumerreports.org): \(\begin{array}{lllllllll}29 & 62 & 37 & 41 & 70 & 82 & 47 & 52 & 49\end{array}\) a. Compute the variance and standard deviation for this data set. b. If a very expensive cheese with a cost per slice of 150 cents was added to the data set, how would the values of the mean and standard deviation change?

Research by the Food and Drug Administration (FDA) shows that acrylamide (a possible cancer-causing substance) forms in high-carbohydrate foods cooked at high temperatures and that acrylamide levels can vary widely even within the same brand of food (Associated Press, December 6, 2002). FDA scientists analyzed McDonald's French fries purchased at seven different locations and found the following acrylamide levels: \(\begin{array}{lllllll}497 & 193 & 328 & 155 & 326 & 245 & 270\end{array}\) a. Compute the mean acrylamide level and the seven deviations from the mean. b. Verify that, except for the effect of rounding, the sum of the deviations from mean is equal to 0 for this data set. (If you rounded the sample mean or the deviations, your sum may not be exactly zero, but it should be close to zero if you have computed the deviations correctly.) c. Calculate the variance and standard deviation for this data set.

The percentage of juice lost after thawing for 19 different strawberry varieties appeared in the article "Evaluation of Strawberry Cultivars with Different Degrees of Resistance to Red Scale" (Fruit Varieties Journal [1991]: \(12-17\) ): $$ \begin{array}{llllllllllll} 46 & 51 & 44 & 50 & 33 & 46 & 60 & 41 & 55 & 46 & 53 & 53 \\ 42 & 44 & 50 & 54 & 46 & 41 & 48 & & & & & \end{array} $$ a. Are there any observations that are mild outliers? Extreme outliers? b. Construct a boxplot, and comment on the important features of the plot.

An experiment to study the lifetime (in hours) for a certain brand of light bulb involved putting 10 light bulbs into operation and observing them for 1000 hours. Eight of the light bulbs failed during that period, and those lifetimes were recorded. The lifetimes of the two light bulbs still functioning after 1000 hours are recorded as \(1000+\). The resulting sample observations were \(\begin{array}{llllllll}480 & 790 & 1000+ & 350 & 920 & 860 & 570 & 1000+\end{array}\) \(170 \quad 290\) Which of the measures of center discussed in this section can be calculated, and what are the values of those measures?

The standard deviation alone does not measure relative variation. For example, a standard deviation of \(\$ 1\) would be considered large if it is describing the variability from store to store in the price of an ice cube tray. On the other hand, a standard deviation of \(\$ 1\) would be considered small if it is describing store-to-store variability in the price of a particular brand of freezer. A quantity designed to give a relative measure of variability is the coefficient of variation. Denoted by CV, the coefficient of variation expresses the standard deviation as a percentage of the mean. It is defined by the formula \(C V=100\left(\frac{s}{\bar{x}}\right)\). Consider two samples. Sample 1 gives the actual weight (in ounces) of the contents of cans of pet food labeled as having a net weight of 8 ounces. Sample 2 gives the actual weight (in pounds) of the contents of bags of dry pet food labeled as having a net weight of 50 pounds. The weights for the two samples are \(\begin{array}{lrrrrr}\text { Sample 1 } & 8.3 & 7.1 & 7.6 & 8.1 & 7.6 \\ & 8.3 & 8.2 & 7.7 & 7.7 & 7.5 \\ \text { Sample 2 } & 52.3 & 50.6 & 52.1 & 48.4 & 48.8 \\ & 47.0 & 50.4 & 50.3 & 48.7 & 48.2\end{array}\) a. For each of the given samples, calculate the mean and the standard deviation. b. Compute the coefficient of variation for each sample. Do the results surprise you? Why or why not?

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