/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 An experiment to study the lifet... [FREE SOLUTION] | 91Ó°ÊÓ

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An experiment to study the lifetime (in hours) for a certain brand of light bulb involved putting 10 light bulbs into operation and observing them for 1000 hours. Eight of the light bulbs failed during that period, and those lifetimes were recorded. The lifetimes of the two light bulbs still functioning after 1000 hours are recorded as \(1000+\). The resulting sample observations were \(\begin{array}{llllllll}480 & 790 & 1000+ & 350 & 920 & 860 & 570 & 1000+\end{array}\) \(170 \quad 290\) Which of the measures of center discussed in this section can be calculated, and what are the values of those measures?

Short Answer

Expert verified
The median of the dataset can be calculated, and it is 525 hours. The mean cannot be accurately calculated due to the presence of censored data.

Step by step solution

01

Understand the Available Data

The dataset is split into two groups: those light bulbs that failed during the experiment, providing exact lifetimes, and those that did not fail, represented as '1000+'. The lifetimes that can be used directly for calculations are 480, 790, 350, 920, 860, 570, 170, and 290 hours.
02

Calculate the Median

To calculate the median of this dataset, first sort it in ascending order: \(170, 290, 350, 480, 570, 790, 860, 920\). Since there are eight values, the median is the average of the fourth and fifth values, i.e., \((480+570)/2 = 525\) hours. The median can be calculated even in the presence of censored data, so it is one of the central measures that can be used in this case.
03

Consider the Mean

The mean, or average, cannot be accurately calculated due to the presence of censored observations. The actual lifetimes of the two bulbs labeled as '1000+' could potentially be much larger, which would result in a higher mean. Therefore, in the presence of censored data, the mean is generally not a reliable measure of central tendency.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Median Calculation
The median is a measure of central tendency that represents the middle value in a dataset. It is particularly useful when dealing with skewed distributions or outliers. To find the median, you first need to arrange the data in ascending order. Once sorted, the median is the value that separates the higher half from the lower half of the dataset.
In our exercise, we had eight lifetimes available for calculation:
  • 170
  • 290
  • 350
  • 480
  • 570
  • 790
  • 860
  • 920
To calculate the median, we identify the fourth and fifth values because with eight numbers, the median is the average of these two middle numbers.The formula for calculating the median here is \(\frac{480 + 570}{2} = 525 \)
As you can see, despite the presence of censored data (the '1000+') in the dataset, the median can still be calculated without being skewed by these values. That makes it a robust measure of central tendency in such scenarios.
Censored Data
Censored data occurs when some data points in your experiment or study do not have a precise value, often having a limit or threshold instead. In this exercise, the data points marked as '1000+' indicate that after 1000 hours, the light bulbs had not failed yet.
Censored data can pose challenges in statistical analysis since these values are not exact and could be potentially large values. However, this makes measures like the mean more difficult to use directly since the true values are unknown. For instance, while we know the bulbs surpassed 1000 hours, they could have lasted significantly longer.
Handling censored data requires special statistical methods and careful thought about how best to interpret results. The median is a measure that remains unaffected by right-censored data points, which is why it is often preferred in such cases.
Mean Limitation
The mean, also known as the average, is calculated by adding all data points and dividing by the number of data points. While it is a very common measure of central tendency, the presence of censored data can distort its accuracy.
In the given exercise, the inability to know the exact values of '1000+' bulbs affects the mean significantly. If these bulbs had lasted much longer, their inclusion in mean calculations could potentially raise the average value.
Therefore, the mean becomes a less reliable measure when dealing with censored data. The uncertainty introduced by the '1000+' values means the mean does not necessarily reflect the true average lifetime of all bulbs. This is why practitioners turn to means specifically designed for censoring issues or alternative statistics, like the median, which remains unaffected by such outliers.

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Most popular questions from this chapter

The paper cited in Exercise \(4.65\) also reported values of single-leg power for a low workload. The sample mean for \(n=13\) observations was \(\bar{x}=119.8\) (actually \(119.7692\) ), and the 14 th observation, somewhat of an outlier, was \(159 .\) What is the value of \(\bar{x}\) for the entire sample?

The ministry of Health and Long-Term Care in Ontario, Canada, publishes information on its web site (www.health.gov.on.ca) on the time that patients must wait for various medical procedures. For two cardiac procedures completed in fall of 2005, the following information was provided: a. The median wait time for angioplasty is greater than the median wait time for bypass surgery but the mean wait time is shorter for angioplasty than for bypass surgery. What does this suggest about the distribution of wait times for these two procedures? b. Is it possible that another medical procedure might have a median wait time that is greater than the time reported for " \(90 \%\) completed within"? Explain.

Consumer Reports Health (www.consumer reports.org/health) reported the sodium content \((\mathrm{mg})\) per 2 tablespoon serving for each of 11 different peanut butters: $$ \begin{array}{rrrrrrrr} 120 & 50 & 140 & 120 & 150 & 150 & 150 & 65 \\ 170 & 250 & 110 & & & & & \end{array} $$ a. Display these data using a dotplot. Comment on any unusual features of the plot. b. Compute the mean and median sodium content for the peanut butters in this sample. c The values of the mean and the median for this data set are similar. What aspect of the distribution of sodium content -as pictured in the dotplot from Part (a) - provides an explanation for why the values of the mean and median are similar?

The percentage of juice lost after thawing for 19 different strawberry varieties appeared in the article "Evaluation of Strawberry Cultivars with Different Degrees of Resistance to Red Scale" (Fruit Varieties Journal [1991]: \(12-17\) ): $$ \begin{array}{llllllllllll} 46 & 51 & 44 & 50 & 33 & 46 & 60 & 41 & 55 & 46 & 53 & 53 \\ 42 & 44 & 50 & 54 & 46 & 41 & 48 & & & & & \end{array} $$ a. Are there any observations that are mild outliers? Extreme outliers? b. Construct a boxplot, and comment on the important features of the plot.

A sample of concrete specimens of a certain type is selected, and the compressive strength of each specimen is determined. The mean and standard deviation are calculated as \(\bar{x}=3000\) and \(s=500\), and the sample histogram is found to be well approximated by a normal curve. a. Approximately what percentage of the sample observations are between 2500 and 3500 ? b. Approximately what percentage of sample observations are outside the interval from 2000 to 4000 ? c. What can be said about the approximate percentage of observations between 2000 and \(2500 ?\) d. Why would you not use Chebyshev's Rule to answer the questions posed in Parts (a)-(c)?

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